Hey Frédérick, I actually tried something very similar to this over my Christmas break in 2004. I was able to get to around 25 seconds as a personal fastest time, but I averaged around 40-50 seconds to do this.
Having one or more transpositions (cycles between two edge groups only) slows me down terribly. I personally was not able to get this method under 15 seconds to identify parity. If you find a way to speed it up I would love to hear how to do it. I gave up on this idea though, but of course maybe you have found some really nice modification to it as well. Chris --- In [email protected], Frédérick BADIE <[EMAIL PROTECTED]> wrote: > > > I can't prove it, but I am almost 100% convinced that counting the > > full cycles is the only way. > > Hi, I think it is not necessary counting the full cycles with the 24 > cubies, but we can calculate a combination between the cycle for the > 12 pairs and the orientation for each 12 pairs separatly. > > Here's the method: > > Definition : > Current Pair : Any combinations of two edges cubies. > FirstEdge and SecondEdge are two edges cubies whith the two same > colors. > MyCounter values 0. > > I take one pair. > It's my Current Pair. > I add 1 to MyCounter. > > The left part of my Current Pair is my First Edge. > The pair where my Second Edge is becomes the Current Pair. > > If the Second Edge is good oriented (according blindfold), I add 1 > to my counter, else I add nothing. > > The left part of my Current Pair is my First Edge. > The pair where my Second Edge is becomes the current pair. > > If the Second Edge is good oriented (according blindfold), I add 1 > to my counter, else I add nothing. > > I do this until my Second Edge is on the first pair I choose at the > beginning. > > The first pair must be twice the current pair. > > When I finish one cycle, I choose for current pair one pair i have > not seen yet.ETC..... > > Until the 12 pairs have been seen. > > One example: > > On a boy color sheme up/yellow face/blue. > I do an "f" and a b2 move and I flip the UL and UR edges( as we do > when we have 2 edges flipped in a blindfold resolution) . The > parity/signature will be odd. > > I take the UR pair. the left part is yellow/orange. > I add one to my counter , it values 1. > > The other yellow/orange is on the UL pair and good oriented . I add > 1 to my counter = 2. > The other UL edge is White/red. > > The other white/red is on the DL pair and not good oriented . I add > nothing and my counter = 2. > The other DL edge is Yellow/red. > > The other yellow/red is on the DR pair and not good oriented . I add > nothing and my counter = 2. > The other DR edge is Yellow/orange. > > The other yellow/orange is on the UR pair and good oriented . I add > 1 and my counter = 3. > > My counter = 3 , so the parity is odd. > > Do this with all cycles if they are more cycle. > Don't forget the pair already "good paired" and add 1 if it is not > good oriented. > > Let's suppose the cube solved with only the UL pair flipped. > > I take this pair UL and add 1. > The left part is yellow/red. the other yellow/red is on UL pair and > not good oriented. I add nothing. The cycle is finish. the parity is > odd. > > Have fun, > Frédérick. > ------------------------ Yahoo! Groups Sponsor --------------------~--> Get fast access to your favorite Yahoo! Groups. Make Yahoo! your home page http://us.click.yahoo.com/dpRU5A/wUILAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
