Hi Daniel,

By removing the human element your computer program only shows that
the pseudo-"random number generator" you used works well within a
million expressions. It says nothing about a human making choices
within a single game.

Cheers,

David J

--- In [email protected], "Daniel Hayes"
<[EMAIL PROTECTED]> wrote:
>
> Excellent explanation!  When I was young and knew everything, I KNEW
> that changing doors didn't matter.  So I wrote a short program to run
> around 1000000 tests of this and catalogue how often the contestant
> won after switching, and how oftent they won after not switching.  It
> was always very close to 1/3 without switching and 2/3 after
> switching.  I eventually figured out the logic behind the below post,
> and was convinced.
>   Interestingly, (now that I am older, wiser, and have a bit better
> math background) I used this same approach from time to time to check
> my work on a few probability assignments that I really felt shakey on.
>  It's not highly efficient, but it lets me combine two things I really
> enjoy: Math and Programming.
> 
> -Daniel
> 
> --- In [email protected], Evan Gates
> <[EMAIL PROTECTED]> wrote:
> >
> > After you choose a door, the host has to open one.  Two out of the
three
> > times, he has no choice which one to open.  When you pick the door
> at first,
> > you have a 1/3 chance of being right.  After he opens a door, if you
> stay
> > with the door you first chose, you still have a 1/3 chance, if you
> switch,
> > you have a 2/3 chance.  There are three possibilities, considering you
> > switch doors.
> > 1) you were right at first, and you lose
> > 2) you were wrong at first, and you win
> > 3) you were wrong at first(other door), and you win
> > Two out of the three possible outcomes, you win
> > 
> > It also might help if you think of 100 doors instead of 3.
> > You choose one door, you have a 1/100 or 1% chance of being right. 
> You stay
> > with that door while the host opens 98 doors, so you are down to 2,
> the one
> > you originally chose, and the last one that he hasn't open.  Staying
> with
> > your first choice, you still have a 1% chance.  But if you switch,
> you have
> > a 99% chance.  There is a reason that he hasn't yet opened that
> door.  By
> > opening the other ones, he's giving you a clue about where the car is.
> > 
> > and boy do I hope I'm right, because rereading that i sound really
> > arrogant lol (really, I'm not and I don't mean to be) ;-)
> > -Evan
> > 
> > Until next time, Happy Cubing
> > http://www.deepcube.net
> > 
> > 
> > On 12/24/05, pjgat09 <[EMAIL PROTECTED]> wrote:
> > >
> > > Hmm, lets see. You start with 3 doors, one with a car. The host
> > > cancels out a door giving you 2 doors. That means your guess has
a 1/2
> > > chance of being correct. There is no point in changing, its 50-50 no
> > > matter what. (unless the game is rigged where the car moves from one
> > > door to the next :P )
> > >
> > > I would stay with my first choice, though it doesnt matter. Its all
> > > personal preferance.
> > >
> > > Peter Greenwood
> > >
> > > --- In [email protected], Pedro
<[EMAIL PROTECTED]>
> > > wrote:
> > > >
> > > > Ok, this is off topic, but is interesting...
> > > >
> > > >   (please forgive if I make some mistake on the english...)
> > > >   Suppose you are at a TV show, where you have 3 doors. 1 of the
> > > doors has a car, and the other 2 don't have anything. So, the show
> > > presenter asks you to choose a door. So, you choose, but he doesn't
> > > open your choosen door. He opens an empty door. Then, he makes a
> > > question: do you want to continue with your first choice or
change to
> > > the other door?
> > > >
> > > >   What do you do?
> > > >   What situation gives you more chances of winning?
> > > >
> > > >   Think about it...
> > > >
> > > >   Pedro
> > > >
> > > >
> > > > ---------------------------------
> > > >  Yahoo! doce lar. Faça do Yahoo! sua homepage.
> > > >
> > > > [Non-text portions of this message have been removed]
> > > >
> > >
> > >
> > >
> > >
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