This doesn't make the argument wrong. Yes, you can gain some knowledge 
this way and be more sure that changing would be better. But it 
doesn't make you win more often when changing. The probability for 
that stays at 2/3.

I knew a similar case as yours, but here's a really extreme one: After 
you pick your first door, the host opens *all* three doors and let's 
you stay or change. Even with this 100% knowledge (because you see the 
car), changing is successful exactly 2/3 of the time, namely in those 
cases where you were initially wrong.

Cheers!
Stefan


--- In [email protected], Rune Wesström <rune.
[EMAIL PROTECTED]> wrote:
>
> A lot of  intuition!
> You guess on door #1. The host is staying in front of door #3. Door 
#2 is 2 meters away from him, nevertheless he opens that door. What 
would you expect to find behind door #3? A goat?! (Let us exclude 
double-crossing!).
> ----- Original Message ----- 
> From: "Stefan Pochmann" <[EMAIL PROTECTED]>
> To: <[email protected]>
> Sent: Wednesday, December 28, 2005 3:47 PM
> Subject: [Speed cubing group] Re: (Off topic)3 doors...
> 
> 
> Changing wins if and only if you initially chose the wrong door, i.
e. 
> two times of three.
> 
> Can you explain why your suggestion makes this wrong?
> 
> Cheers!
> Stefan
> 
>  --- In [email protected], Rune Wesström <rune.
> [EMAIL PROTECTED]> wrote:
> >
> > In real life the host is Not staying totally symmetrically in 
> relation to the doors. (He is right-handed Or left-handed. Maybe he 
> has to take a halfstep to open a certain door etc.). If he now opens 
> the "easiest" door, Not changing wins more often than one time of 
> three. If he opens the other door, changing will win more often than 
> two times of three.
> 
> 
> 
> 
> 
> 
> 
>  
> Yahoo! Groups Links
>






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