--- In [email protected], Tyson Mao <[EMAIL PROTECTED]> 
wrote:
>
> Hi GameOfDeath,
> 
> Stefan and I fully understand that running a simulation is not a 
> mathematical proof.  However, we have given a mathematical proof 
many 
> times.  In fact, Stefan has given the exact same mathematical 
proof, 
> which is why we've resorted to simulations in an attempt to 
convince 
> people that the answer is in deed 2/3 winning probability when one 
> switches doors.
> 

I guess I only read some of the posts. In that case, I take it back 
(about people using simulations instead of proofs) and instead 
congratulate you both for presenting proofs.

> You know... having 76 successes out of 100 is very nearly (order of 
> magnitude) the probability of getting lucky on a Rubik's Cube is it 
> not?

I don't know what the probability of getting lucky on a Rubik's cube 
is. (Are you talking about the Revenge - with the probability being 
75% that one can skip one of the two non-standard 3x3x3 situations.)

In fact, I don't even know the probablitiy of getting lucky. : )

I guess one must have

P(Getting lucky on a Rubik's cube)=
P(Getting lucky|one is on a Rubik's cube)=
[P(Getting lucky)-P(Getting lucky|one is not on a Rubik's cube)*P(One 
is not being on a Rubik's cube)]/P(One is on a Rubik's cube)

at least assuming P(One is on a Rubik's cube)>0.

> 
> Tyson Mao
> MSC #631
> California Institute of Technology
> 
> On Dec 30, 2005, at 10:00 AM, Stefan Pochmann wrote:
> 
> > --- In [email protected], "Daniel Hayes"
> > <[EMAIL PROTECTED]> wrote:
> >>
> >> Thus, the probability of having 76 success out of 100 without
> >> switching doors = 2.59697e-18 = 0.000000000000000259697%
> >
> > Bah, using % is a cheap trick to make it look larger.
> > I prefer 0.00000000000000000259697
> >
> > I did know the formula, just didn't think I have a tool good 
enough to
> > handle these very large and very small numbers. I was wrong, 
actually
> > even my pocket calculator easily can...
> >
> > It's btw close to the probability that a random scramble results 
in a
> > solved 3x3. Just to get on-topic again... :-)
> >
> > Cheers!
> > Stefan
> >
> >
> >
> >
> >
> >
> >
> >
> > Yahoo! Groups Links
> >
> >
> >
> >
> >
> >
> >
>






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