Ok ok, I don't think we'll get somewhere so I'll just tell you: the 3-cycles are nothing else than a swap of two adjacent corners followed by a U turn. So you have these two cases:
- Swap two adjacent corners. - Swap two diagonal corners. Got it? Cheers! Stefan --- In [email protected], "Craig Bouchard" <[EMAIL PROTECTED]> wrote: > > Well, you may be being picky and say 1, cuz if you execute one alg the > right way multiple times then it will solve...but I mean for a 1 look > every time... > > Craig > > --- In [email protected], "Stefan Pochmann" > <[EMAIL PROTECTED]> wrote: > > > > --- In [email protected], "Craig Bouchard" > > <[EMAIL PROTECTED]> wrote: > > > > > > Yes theres 3...the 2 3 Cycles and then the one that switches the 2 > > > sets of the adjacent corners...unless you are counting the 3 cycles > > > are 1 cuz one is just the inverse... > > > > No, the two 3-cycles are the same, and I don't mean by > > inversion/mirroring. Think again :-) > > > > > P.S. - Stefan you were the 25000th post...intense > > > > Yeah I know. The prime factorization is 2^3 * 5^5 so if you don't hear > > from me again you know the Illuminati got me. > > > > Cheers! > > Stefan > > > Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
