Hello Warren, You wrote : ----- I have a south vertical wall that declines 26 degrees to the west. I know that surface is equal to a horizontal plane at 18 South latitude with a few hours different in longitude. Does anyone know if I could design an azimuth dial for 18 deg S and shift the hours for difference of longitude and use it on that wall - with a style that is perpendicular to the surface - pointing to 26 deg west of south?
Just a thought -- Warren Thom (42N 88W) ----- I read : latitude 42N vertical dial, that is inclination 90 degrees declination of dial 26 degrees from South to West I calculate : The height of style ( for a usual dial ) than is : v = -41.91 degrees. This equals to a horizontal dial at latitude 41.91S. ( not 18 as you wrote ) Where is the error ????? The longitude correction will be ts = 36.09 degrees The substyle for a usual dial will be b = -154.04 degrees These values may be calculated with Zonwvlak. You may calculate an azimuthal dial for this Southern latitude with the longitude correction ts and place it on your wall with the original North-South line on the substyle line. You measure the azimuth of that Southern latitude, not of your own latitude. Using Spin.exe the 2 possible dials will be as in the attached drawing. I added a line for the horizon. The part of the drawing above this line is of no use. The shadow of the perpendicular style never will cath that part. Remark : I didn't include your longitude correction to your standardtime meridian. This is 90 - 88 = 2 degrees. Bets wishes, Fer. Fer J. de Vries [EMAIL PROTECTED] http://www.iae.nl/users/ferdv/ Eindhoven, Netherlands lat. 51:30 N long. 5:30 E Attachment converted: Macintosh HD:spin.gif (TIFF/JVWR) (0000F144)
