Well, in the middle of doing something else, so not quite sure if I have
the right count in the highlighted filter.
On Monday, September 13, 2021 at 12:18:45 PM UTC-3 Charlie Veniot wrote:
> <$list filter="[has[frequency]]">
> *<$vars theCount={{{ [all[current]!days:last-contact{!!frequency}count[]]
> }}} >*
>
> <$list filter="[all[current]!days:last-contact{!!frequency}]">
> <$link><$view field="title"/></$link>
> </$list>
> *</$vars>*
> </$list>
>
> On Monday, September 13, 2021 at 12:12:45 PM UTC-3 0 0 wrote:
>
>> Thank you for your answer, I appreciate your help.
>> However, your suggestion does not seem to affect the underlying problem:
>> I'm unable to get the number of tiddlers that pass the filter of second
>> list.
>> I'll try to elaborate what I meant in my original post.
>>
>> For example let's say the outer list alone would output 100 tiddlers. If
>> I added count[] to this filter to get the number of tiddlers this outer
>> list outputs I will see the number 100 instead of 100 individual titles.
>> Then the inner list filters out 30 tiddlers that do not satisfy the
>> additional condition. I see 70 tiddler titles that pass the outer AND inner
>> filter, but I'm unable to count them (except by hand).
>> Adding count[] to the inner list would just yield a mix of 30 zeroes (0 0
>> 0 0...for each time the currently evaluated tiddler does not pass the inner
>> filter) and 70 ones (1 1 1 1...whenever it does).
>>
>> Now either I'd need some way to have a variable that would increase each
>> time a tiddler passes the inner filter, or I'd need to have it all in a
>> single-level list (which with current setup doesn't work exactly for the
>> reason Eric describes). Or there could be a completely different approach
>> that I'm unable to see.
>>
>> 0
>> maanantai 13. syyskuuta 2021 klo 18.02.58 UTC+3 Eric Shulman kirjoitti:
>>
>>> On Monday, September 13, 2021 at 6:51:14 AM UTC-7 [email protected]
>>> wrote:
>>>
>>>> Aside: we could merge the two <$list> filters together
>>>
>>>
>>> That wouldn't work in this case, as the inner filter uses
>>> `{!!frequency}`, which depends upon the outer filter to set the
>>> `currentTiddler` value to each tiddler that `has[frequency]`
>>> If the two filters were merged, then `{!!frequency}` would refer to the
>>> tiddler that contains the `$list` widget, rather than each tiddler that
>>> `has[frequency]`
>>>
>>> -e
>>>
>>
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