Thanks, but still no luck (the syntax didn't matter either).
Result looks something like this (I add some arbitrary linebreaks here to
make the logic clearer):
Task1 *You have 1*
Task2* You have 1*
*You have 0*
Task 4 *You have 1*
Task 5 *You have 1*
*You have 0*
*You have 0*
Task 8 *You have 1*
Task 9 *You have 1*
Task 10 *You have 1*
maanantai 13. syyskuuta 2021 klo 20.58.04 UTC+3 [email protected] kirjoitti:
> Hi, give this a spin:
>
> <$list filter="[has[frequency]]">
> *<$vars theCount={{{ [all[current]!days:last-contact{!!frequency}count[]]
> }}} >*
>
> <$list filter="[all[current]!days:last-contact{!!frequency}]">
> <$link><$view field="title"/></$link>
> </$list>
>
> *You have <$text text=<<theCount>>/>*
> *</$vars>*
> </$list>
>
> Not being convinced I have my vars set right, this as an alternative:
> *<$vars theCount={{{ [all[current]!days:last-contact{!!frequency}]
> +[count[]] }}} >*
> On Monday, September 13, 2021 at 2:25:02 PM UTC-3 0 0 wrote:
>
>> <$list filter="[has[frequency]]"> I have 10 recurring tasks
>> <$list filter="[all[current]!days:last-contact{!!frequency}]"> 7 tasks
>> haven't been completed in {{!!frequency}} days. last-contact contains the
>> timestamp of latest completion.
>> <$link><$view field="title"/></$link>
>> </$list>
>> </$list>
>>
>> As expected the output is 7 tiddler titles:
>> Task1
>> Task2
>> Task4
>> Task5
>> Task8
>> Task9
>> Task10
>>
>> After this list I want:
>> You have *[7]* tasks.
>> ___________________
>> <$vars theCount={{{ [all[current]!days:last-contact{!!frequency}count[]]
>> }}} > does not seem to work.
>> "[all[current]..." contains only one title at a time which then either
>> passes the !days filter or not. Thus after count[], <<theCount>> variable
>> will contain a 1 or a 0.
>>
>> I'm afraid there is no solution at my level of competence :/
>>
>> maanantai 13. syyskuuta 2021 klo 18.36.56 UTC+3 [email protected]
>> kirjoitti:
>>
>>> This may seem silly, but a mock-up screenshot of expected output would
>>> be pretty awesome. Information with labels of what the information means.
>>>
>>> My last sample I posted should have had the question "something like
>>> this?", because it definitely wasn't any kind of "this is the answer you're
>>> looking for.'
>>>
>>>
>>>
>>> On Monday, September 13, 2021 at 12:20:15 PM UTC-3 Charlie Veniot wrote:
>>>
>>>> Well, in the middle of doing something else, so not quite sure if I
>>>> have the right count in the highlighted filter.
>>>>
>>>> On Monday, September 13, 2021 at 12:18:45 PM UTC-3 Charlie Veniot wrote:
>>>>
>>>>> <$list filter="[has[frequency]]">
>>>>> *<$vars theCount={{{
>>>>> [all[current]!days:last-contact{!!frequency}count[]] }}} >*
>>>>>
>>>>> <$list filter="[all[current]!days:last-contact{!!frequency}]">
>>>>> <$link><$view field="title"/></$link>
>>>>> </$list>
>>>>> *</$vars>*
>>>>> </$list>
>>>>>
>>>>> On Monday, September 13, 2021 at 12:12:45 PM UTC-3 0 0 wrote:
>>>>>
>>>>>> Thank you for your answer, I appreciate your help.
>>>>>> However, your suggestion does not seem to affect the underlying
>>>>>> problem: I'm unable to get the number of tiddlers that pass the filter
>>>>>> of
>>>>>> second list.
>>>>>> I'll try to elaborate what I meant in my original post.
>>>>>>
>>>>>> For example let's say the outer list alone would output 100 tiddlers.
>>>>>> If I added count[] to this filter to get the number of tiddlers this
>>>>>> outer
>>>>>> list outputs I will see the number 100 instead of 100 individual titles.
>>>>>> Then the inner list filters out 30 tiddlers that do not satisfy the
>>>>>> additional condition. I see 70 tiddler titles that pass the outer AND
>>>>>> inner
>>>>>> filter, but I'm unable to count them (except by hand).
>>>>>> Adding count[] to the inner list would just yield a mix of 30 zeroes
>>>>>> (0 0 0 0...for each time the currently evaluated tiddler does not pass
>>>>>> the
>>>>>> inner filter) and 70 ones (1 1 1 1...whenever it does).
>>>>>>
>>>>>> Now either I'd need some way to have a variable that would increase
>>>>>> each time a tiddler passes the inner filter, or I'd need to have it all
>>>>>> in
>>>>>> a single-level list (which with current setup doesn't work exactly for
>>>>>> the
>>>>>> reason Eric describes). Or there could be a completely different
>>>>>> approach
>>>>>> that I'm unable to see.
>>>>>>
>>>>>> 0
>>>>>> maanantai 13. syyskuuta 2021 klo 18.02.58 UTC+3 Eric Shulman
>>>>>> kirjoitti:
>>>>>>
>>>>>>> On Monday, September 13, 2021 at 6:51:14 AM UTC-7 [email protected]
>>>>>>> wrote:
>>>>>>>
>>>>>>>> Aside: we could merge the two <$list> filters together
>>>>>>>
>>>>>>>
>>>>>>> That wouldn't work in this case, as the inner filter uses
>>>>>>> `{!!frequency}`, which depends upon the outer filter to set the
>>>>>>> `currentTiddler` value to each tiddler that `has[frequency]`
>>>>>>> If the two filters were merged, then `{!!frequency}` would refer to
>>>>>>> the tiddler that contains the `$list` widget, rather than each tiddler
>>>>>>> that
>>>>>>> `has[frequency]`
>>>>>>>
>>>>>>> -e
>>>>>>>
>>>>>>
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