Hello, While configuring my indentation, I came across a behaviour that seemed unintuitive to me (I did not manage to find anything related to this on the mailling lists, sorry if I missed it).
When a value in the cinoptions string is described as a shiftwidth value, the value cannot be zero. This means that if I write "cino=n0s", the indentation behaves as if I wrote "cino=n1s". Reading the code (in the latest vim mercurial trunk), I found that if the value and the fraction were equal to 0 when the 's' character is present, then the value is set to 1 by default. I am aware that writing "n0s" instead of "n0" may be a stretch, but I found this behaviour disturbing. Is this behaviour intended, or is it a unlucky side-effect of the default 1 shiftwidth width when only the s is present ? In the second case, I wrote a little patch that should be easy to apply and check (Patch retrieved from a mercurial patch queue), that I will join to my next message if you deem it useful :) Thanks, -- David Pineau -- You received this message from the "vim_dev" maillist. Do not top-post! Type your reply below the text you are replying to. For more information, visit http://www.vim.org/maillist.php
