2012/6/7 Bram Moolenaar <[email protected]>:
>
> David Pineau wrote:
>
>> While configuring my indentation, I came across a behaviour that seemed
>> unintuitive to me (I did not manage to find anything related to this on the
>> mailling lists, sorry if I missed it).
>>
>> When a value in the cinoptions string is described as a shiftwidth value,
>> the value cannot be zero.
>> This means that if I write "cino=n0s", the indentation behaves as if I
>> wrote "cino=n1s".
>>
>> Reading the code (in the latest vim mercurial trunk), I found that if the
>> value and the fraction were equal to 0 when the 's' character is present,
>> then the value is set to 1 by default. I am aware that writing "n0s"
>> instead of "n0" may be a stretch, but I found this behaviour disturbing.
>>
>> Is this behaviour intended, or is it a unlucky side-effect of the default 1
>> shiftwidth width when only the s is present ?
>>
>> In the second case, I wrote a little patch that should be easy to apply and
>> check (Patch retrieved from a mercurial patch queue), that I will join to
>> my next message if you deem it useful :)
>
> Why would anyone use "0s"?  You can just use "0".

Well, it ranges from configuration artifacts to laziness: I only
indent depending on my shiftwidth value, so while tweaking the values,
I kept the 's' in case I was going to change the value. That's why I
said that it may be a stretch to do as I did.

>
> I do agree it's counter intuitive.
>

I hope my little bit of feedback was useful.
Thanks to both of you for addressing this issue as fast as you did.

Cheers,

-- 
David Pineau

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