On Sat, Nov 14, 2015 at 4:57 PM, Bob Higgins <[email protected]> wrote:
When you introduce the magnet to the presence of the superconductor, > currents are induced in the superconductor that cause the magnetic field to > exactly cancel at the surface of the superconductor such that there is no > penetration of the magnetic field into the superconductor. However, this > induction of a new current is of non-zero frequency, and hence these > non-zero frequency current components will experience a finite resistance. > This sounds as though the magnet will fall through eventually, due to the finite resistance brought about by the non-zero frequency of the current. I assume this component is radiated away as heat, even in a superconductor. Is the understanding that at the atomic level this part of the analogy breaks down, and you would not see the same phenomenon? Eric
