I was taught some time back that potential energy created by electric charges separated in space in a coherent system adds rest mass to that system.
Binding energy is potential energy and, thus ,IMO adds mass to the respective coherent system which it binds together. Does anyone consider binding energy is NOT associated with a field and the potential energy the field manifests as it maintains a separation of charged primary particles with their own rest mass and charge? Bob Cook . From: Axil Axil Sent: Monday, May 21, 2018 3:11 PM To: vortex-l<mailto:[email protected]> Subjgect: Re: [Vo]:The PP fusion reaction in LENR Is the binding energy released from a change in the configuration of the nucleus derived from the protons and neutrons that comprise the nucleus or does it come from the nucleus itself? On Mon, May 21, 2018 at 5:42 PM, <[email protected]<mailto:[email protected]>> wrote: In reply to Jed Rothwell's message of Mon, 21 May 2018 11:00:54 -0400: Hi, [snip] >Russ <[email protected]<mailto:[email protected]>> wrote: > >Might you point to a reference where the mass of neutrons in deuterium vs. >> other nuclides is said to be different. >> > >I do not understand. Is the claim here that a neutron in deuterium is >heavier or lighter than a neutron in some other element? Yes (heavier), that's what I'm suggesting. > There are >different kinds or neutrons, or entering deuterium changes the mass? The latter. The energy release from the nuclear reaction has to came from somewhere. I am simply saying that it comes from the conversion of part of the mass of the constituent particles. > >That seems extremely unlikely to me. Then you need to explain where the fusion energy comes from. (I'm counting addition of a neutron to a nucleus as a form of fusion). Note that the formation of D from a free proton & a free neutron releases only 2.2 MeV of energy whereas at the other extreme, addition of a neutron to a Ni nucleus releases about 8 MeV of energy. Hence my conclusion that neutrons in Ni have lower mass than those in D. Regards, Robin van Spaandonk local asymmetry = temporary success
