Oops again.  :-(
 
The force between the capacitor plates Buehler used, equals Energy/Spacing
= 0.4 joule/0.05 meter = 0.4 nt-meter/0.05 meter   = 8.0 nt.
 
 
----- Original Message -----
From: Frederick Sparber
To: vortex-l
Sent: 4/5/2006 5:13:31 AM
Subject: Re: Electrogravity From Accelerated B Fields

BTW, Jones.
 
 The force between the capacitor plates Buehler used, equals Energy/Spacing
= 0.4 joule/0.05 meter = 8.0 nt-meter/0.05 meter   = 8.0 nt.
 
Therefore the force ( F ) between the charged capacitor energy and the earth = 0.4 nt-meter/s meter
so at 1.0 meter F = 0.4 nt  regardless of the sign on each of  the capacitor plates: 
 
OTOH, Buehler's single plate with a positive potential was attracted toward
the earth as opposed to the repelling force of a negatively charged plate
which suggests that electrons repel gravity.
 
If not for the ~42 orders of magnitude greater  proton-electron electrostatic force, there
wouldn't be any electrons around.   :-)
 
Fred
----- Original Message -----
Sent: 4/4/2006 7:52:00 PM
Subject: Re: Electrogravity From Accelerated B Fields

Jones says.
>
> Put the thing in a vacuum and the effect goes away.
>
I'm not so sure about that, Jones.
 
It takes the combined energy of 1.223e-13  0.510 MeV (8.16e-14 joule) electrons to equal 1.0 joule,
the total charge, Q of 1.223e13 electrons is 2.0e-6 coulombs.
 
A  5.0e-12  farad capacitor (in air) holding 2.0 e-6 coulombs has a voltage Q/5.0e-12 = 4.0e5 volts
on its plates, and stores as Electrical Energy, 1/2 CV^2 = 0.4 joules.
 
Buehler's calculation from the data shows the  "normalized" anomalous repelling force
(regardless of the sign of the plates wrt the earth) of  0.47 newtons per joule.  
 
Thus 0.47/0.4 = 1.175 newton/joule. (about 1.0 newton per joule).
9.8 newtons at 9.8 joule-sec (9.8 watts) or 1.0 newton per joule, will make a 1.0 kg mass achieve
weightlessness at the earth's surface.
It seems that electrical energy stored in the air (vacuum?) between the plates
of a capacitor wants to repel the earth's gravity.
 
 At least on a beam balance, or a pendulum, where no work is being done?
 
Fred
 


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