On Aug 3, 2007, at 9:39 PM, thomas malloy wrote:
Vortexians;
I've been wondering. Suppose that the resonant frequency
electrolyzer works. It's actions, including the energy gain, are
attributed to the electrical pulse causing the H and O atoms to
move apart to a point where they suddenly become separate, I'm
thinking that perhaps this might happen because the two electrons
might just pop into existence. In a private communication, Hal
Puthoff told me that electron pairs materialize spontaneously out
of the quantum foam. Normally they annihilate each other, these
electron pairs, but suppose that a pair materialized in between the
H and the O, and pop, the electrons in opposite directions. I'm
thinking that this would be the opposite side of the coin to
electron fugacity.
Actually, in the lattice, a somewhat different situation, the
probability of virtual pair separation is *increased* by high
electron fugacity. Further, the probability of the creation of a
deflated hydrogen state is also increased, but only slightly I
think. I have some doubts it is a very common event, for reasons
I'll now describe, but there are also reasons to think it might be
common.
It takes a tremendous electrostatic field to separate a virtual
electron and positron, and thereby make them real. This can only
happen in the lattice when an electron is close up to the nucleus.
The electrons which can fulfill this role of being close-up to the
nucleus are the ionically bound partners to the adsorbed hydrogen.
Just call them partner electrons. In a close packed lattice partner
electrons occupy partial orbitals when in spaces too small to permit
a full orbital to form. These partial orbitals pulnge deep toward
the nucleus. In other words the probability of the ionically bound
partner electron being found close up to the partner nucleus is much
higher than for any other electron in the lattice. The greater the
compression of the partner electrons' partial orbitals, i.e. the
greater the fugacities and external fields, the deeper the partner
electrons plunge on average.
Some of the time the partner electron (at least probabilistically
speaking) spends inside the nucleus in the deflated hydrogen state.
Some of the time the partner electron spends nearby but not in the
nucleus. It is these very nearby times that virtual particle pair
separation may play a role. Virtual pair creation increases the
probability of a deflated hydrogen state. This happens because when
the pair is separated, the positron is attracted to the electron and
annihilation can proceed. This must not happen very much, because
the high energy photon pairs from positron annihilation are extremely
energetic and easily detectable. At any rate, virtual the electron
of the pair is attracted by and to the nucleus, and this increases
the probability of formation of the deflated hydrogen state.
According to some models of pair creation, when the virtual pair is
pulled apart it ceases to be virtual and become real by virtue of the
energy supplied to pull them apart. However, if the virtual positron
is "real" then it should generate high energy photon pairs when it
annihilates whith the real electron - and this does not happen.
Now, I could be wrong about the *necessity* of annihilation photon
pair production, which would change the picture dramatically. Some
physicists cosider a "phoenix" model of the electron valid. They view
a free electron as a point particle. This means the electron, close
up to itself, has an electric field strong enough to separate a
virtual particle pair, and thereby self annihilate with the positron,
leaving the fresh new electron some distance away. The electron
thereby dies and is reborn, thus the "phoenix effect". In the
phoenix model all free electrons do this at a very high rate. The
mystery to me, if this is so, is why the high energy annihilation
photon pairs are not visible and continually produced. If this is an
accurate or even remotely credible model of a free electron the
photon pairs should be there, but aren't.
One answer may come from the fact virtual pairs have no gravitational
mass, and thus no energy, and vice versa. The annihilation of the
virtual electron and real electron may not proceed until some
mechanism conveys "realness" to the virtual electron of the pair,
i.e. gives it gravitational mass. A virtual particle and real
particle can not mutually annihilate because they are not identical
opposites. Being of opposite Coulomb charge, however, virtual
positrons and real electrons certainly can pair up to make a neutral
particle, and thereby avoid further pair creation, and any
radiation. But what happens then to the virtual electron of the
pair? Perhaps it acts as an orbital placeholder for the original
electron, or maybe it simply joins a nucleus, in effect neutralizing
one positive charge. There it can not react, even by a weak force
perhaps, but it is bound to the nucleus by its charge indefinitely.
Now, if a neutral pair, i.e. a virtual positron and real electron
combined particle enters a nucleus containing a virtual electron,
then the virtual particles can annihilate without radiation, and the
nucleus is left with one remaining excess real electron. It is in the
de-energized deflated hydrogen state, and got there without any
radiation. Interesting.
Horace Heffner
http://www.mtaonline.net/~hheffner/
