In reply to Horace Heffner's message of Tue, 22 Feb 2011 13:35:03 -0900: Hi, [snip] >This 270kWh per 0.4 g if hydrogen is obviously well beyond chemical >if the consumables actually are H and Ni. The energy E per H is: > > E = (270kwh) /(0.4 g * Na / (1.00797 gm/mol)) = 2.54x10^4 eV / H > > E = 25.4 keV per atom of H. > >This is about 2.5 times the ionization energy of the innermost >electron of Ni. This is well under expected conventional weak >reaction energies feasible between protons and Ni, but not out of >the range of feasibility for hydrino reactions, or deflation fusion >reactions.
..we also don't know how much of the H remained in the Ni after the reaction was finished. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/Project.html
