If anyone can get some reasonable dimensions for the components involved I can do a solid model finite element analysis to figure out the relative temperature split.
It is really perturbing that the initial temperature measurements up to about 11:50 have a 4.3°C temperature difference between the inlet and outlet of the secondary, and even at max power it only rises to about 7.2°C - obviously a huge temperature error, which in itself and alone makes all the secondary loop data totally unreliable. On 14 October 2011 19:38, Alan J Fletcher <[email protected]> wrote: > The vortex mailer truncated the changed link in the message. Sorry --- > I'll re-send the whole thing: > > I've put up a couple of sketches to explain Horace's/my resistor thermal > model > > Detailed manifold schematic -- but the thermocouple isn't on THAT nut. > http://lenr.qumbu.com/111010_**manifold_001_h1200.jpg<http://lenr.qumbu.com/111010_manifold_001_h1200.jpg> > > http://lenr.qumbu.com/111010_**pics/111014_manifold_001.jpg<http://lenr.qumbu.com/111010_pics/111014_manifold_001.jpg> > > A) A rough diagram of the manifold, ignoring junctions between sections > (which I think are 2nd or 3rd order). > B) A first physical approximation as a tube with wall thickness T > C) 2-resistor model Vt = (100-30) * R2 / (R1 + R2) ... R proportional to > distance. > D) Triangulated model (21 R's in my spreadsheet) .. with the lower ends of > the resistor stepped along the tube > One group connects to 100C, the other to 30C > Each group of resistors has a value 1/R = sum(1/R) .. which can be > plugged into the 2-resistor model. > > To do : > > http://lenr.qumbu.com/111010_**pics/111014_manifold_002.jpg<http://lenr.qumbu.com/111010_pics/111014_manifold_002.jpg> > > E) Tubular mesh > F) Full-body mesh > G) Mesh with heat storage > > I've seen models with one capacitor to ground, and models with a capacitor > across each resistor. > > I have Spice installed on my system, and I can easily generate a mesh > network for it. > > I also have an idea on how to model the heat transfer for laminar fluid > flow in each arm. > There's at least a 40:1 (600:15 litres/hour) difference in flow. > > (I also have the free Elmer FE software on my system, but I'm learning how > to use it. I'll check their examples.) > > > ps Off to print my tax forms .... > pps added a googlable signature > >
