Post 10

Bob Higgins stated: *What does "strength" of Rydberg matter, and "match the
fusion of proton cooper pairs" mean?  These don't make sense.  While it may
be possible that there is Cooper-pair like coupling of protons, no one has
yet explained how, if this occurred, that the LENR transmutations are
enabled.  Twice the mass and twice the charge doesn't necessarily help.*

Axil Responds:

http://arxiv.org/abs/1101.1393v1
*Novel insights into transfer processes in the reaction 16O+208Pb at
sub-barrier energies
The collision of the doubly-magic nuclei $^{16}$O+$^{208}$Pb is a benchmark
in nuclear reaction studies. Our new measurements of back-scattered
projectile-like fragments at sub-barrier energies show show that transfer
of 2 protons ($2p$) is much more probable than $\alpha$-particle transfer.
$2p$ transfer probabilities are strongly enhanced compared to expectations
for the sequential transfer of two uncorrelated protons; at energies around
the fusion barrier absolute probabilities for two proton transfer are
similar to those for one proton transfer. This strong enhancement indicates
strong $2p$ pairing correlations in $^{16}$O, and suggests evidence for the
occurrence of a nuclear supercurrent of two-proton Cooper pairs in this
reaction, already at energies well below the fusion barrier.*

**
Quantum mechanics results in some strange and unexpected stuff that is
counter intuitive.
This reference states that proton pairs will tunnel into a nucleus with a
higher probability than does a single proton.

Also, the Rydberg ions that Rossi uses in his reactor do not damage the
delicate nano-cavities that produce the cooper pairs of protons. They
are mild. By contrast, if LeClair’s Rydberg ions got close to the Rossi
micro-powder, the powder would be destroyed by electrostatic induced
collision between the ion and the powder.


Regards: Axil

On Wed, Mar 21, 2012 at 11:51 AM, Bob Higgins <[email protected]>wrote:

> Axil, these are interesting posts that will stir our imagination.
> However, some of what you said doesn't ring true and some of it I just
> don't understand.
>
> You said:
>
>  *Rossi’s previous work experience includes the development of prototype
> thermionic converter, so he should know all about Rydberg matter.*
>
> I haven't seen this anywhere.  I know that Rossi and Leonardo Corp worked
> on TE (Thermoelectric, not Thermionic) conversion for the US Military, but
> that was solid state Peltier effect devices.  I worked for many years with
> Peltier devices and never once heard mention of Rydberg effects, because
> they are not involved in such devices.  I don't think Rossi has any past
> experience with Rydberg matter and I have not seen where he mentioned this
> in association with his eCat technology.  I think it is only your
> speculation that Rydberg matter is involved in his process.
>
> You said:
>
>  *IMHO, both Rossi and DGT use pulsed application of heat as a way to
> control the proper hydrogen envelope temperature profile; that is to make
> sure that a cold zone is properly maintained.*
>
> Well, IMHO, Rossi and DGT both use resistive heaters incapable of
> providing "pulsed heat" due to the thermal mass.  In fact, the high
> pressure H2 has tremendous heat capacity and will also make it hard
> to create thermal pulsing by any means.  I don't believe short time-scale
> thermal pulses are being created as a stimulus.
>
> Early Rossi devices did not use his "frequencies" generator.  That
> appeared to be an addition to help stimulate the reaction at a lower H2
> pressure where the reaction had less tendency to run out of control.  It is
> known that the reaction rate increases with temperature and with H2
> pressure.  The early eCat reactors were water cooled and used a stainless
> steel cell.  The thermal resistance in the stainless shell allowed the
> temperature of the reactant/H2 to be at 400-600C while the water was only
> at 100C; however, it also meant that the ability to extract heat was
> limited by the same thermal resistance.  Above a critical heat generation
> inside the cell, the water cooling could no longer pull out enough heat
> through the thermal resistance of the poorly conducting stainless to keep
> the temperature of the reactant from rising.  This was the thermal
> runaway.  This caused Rossi to operate at lower H2 pressures to keep the
> maximum heat generation below what he could pull out through the stainless
> thermal resistance, allowing him to control the temperature from going so
> high as to melt the nickel and eliminate the surface properties that
> stimulate the reaction.  Unfortunately, operation on this threshold of LENR
> was tenuous when just based on keeping it at the right temperature.  The
> reaction is somewhat chaotic (like noise) and it can quickly fall below the
> operational threshold when operated so close to threshold.
>
> Interestingly, DGT operates at noticeably higher H2 pressure, that in
> Rossi's case would cause a thermal runaway.  DGT has found a means to
> rapidly "quench" the reaction (stop it) so that they can control the heat
> output.  They can turn the quench on and off and get reaction pulses - as
> many as they like to get the heat output they want.  I have some ideas on
> how they do the quenching - and it is not thermal.
>
> The Rydberg matter seems to be going in the wrong direction.  Normal
> ground state atoms have a smaller mean orbital radius.  Outside of this
> radius the atom appears net neutral.  If you get inside of this radius,
> there is a strong electric field.  To get fusion to occur, the nuclei must
> be much much closer than the the radius of the the ground state hydrogen
> orbital.  The + nuclear charge is only screened as long as you are outside
> the orbital.  In Rydberg atoms, the orbital is HUGE.  This allows them to
> easily couple and form condensates.  However, it also means that the nuclei
> cannot get as close to another nucleus as a ground state atom because the
> orbital is bigger.  The instant you are inside the orbital you have the
> nuclear repulsion.  From this perspective, Fran's Inverse Rydberg state
> (orbital smaller than ground state) makes more sense - it would allow the
> nuclei to become closer before the orbital is crossed exposing the
> repulsive electrostatic forces.  I think the Inverse Rydberg "matter" would
> be natually less likely to form a condensate than a ground state atom due
> to the shrunken orbital which I think decreases the coupling coefficient.
> The Inverse Rydberg state would seem to fit better into a theory of the
> solid state effects inside the lattice of nickel or palladium and is going
> in the right direction to explain proton insertion into another nucleus.
>
> Rossi stated that his fuel is a Ni powder with MICRON dimensions - not
> nano.  To that he adds a secret sauce, likely to be a nanopowder.  This
> added nanopowder combined on the 1000x larger surface of the Ni powder may
> form islands of atoms that could each form a Rydberg like condensate on the
> top of the Ni.  This in turn could stimulate the catalysis of H2 into H and
> funnel it into the Ni lattice.  However, I don't believe the Rydberg
> formation is known to be the cause of the catalysis, but that would be an
> interesting examination.
>
> You said:
>
>  *A Rydberg condensate can be engineered to vary in potency from very
> weak to extremely strong. *
>
> *Rossi has set the strength of his Rydberg matter to match the fusion of
> proton cooper pairs with nickel nuclei.*
>
> *On the other hand, the Rydberg matter in the LeClair reactor is
> extremely powerful.*
>
> I don't know what any of that means.  The "dipole" of the Rydberg is just
> a measure of its electron orbital radius and essentially its ability to
> couple to other atoms by wrapping around them.  The electron is very weakly
> bound and is moving relatively slowly.  There is no "power" associated with
> it or a condensate of these atoms.  There is no net charge exposure because
> such would mean it is an ion, not a Rydberg atom.  There is no observable
> oscillation of charge, because that would cause EM radiation that would
> quickly cause the electron to drop to a lower energy state.
>
> What does "strength" of Rydberg matter, and "match the fusion of proton
> cooper pairs" mean?  These don't make sense.  While it may be possible that
> there is Cooper-pair like coupling of protons, no one has yet explained
> how, if this occurred, that the LENR transmutations are enabled.  Twice the
> mass and twice the charge doesn't necessarily help.
>
> In the case of the LeClair reactor, the crystalline formation at extremely
> high pressure & mass density is interesting and it is at such tremendous
> pressure that, there is a large potential energy in its release.  In the
> cavitation, plasmas are formed, and it would certainly be possible to find
> an intermediate form of matter (Rydberg) between the plasma state and the
> ground state for the atoms.  It is not clear at all how this is complicit
> in LENR.  I have not heard a plausible speculation of how Rydberg is
> complicit in the act of insertion of protons into another nucleus.
>
> So, even if there is a Rydberg condensate, how do you eliminate the "magic
> happens here" moment that causes the proton insertion into another
> nucleus?  [BTW, I do believe that they are being inserted in some manner,
> but not necessarily as a Rydberg effect.]
>
>
>
>
>

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