I think that it is symmetrical. If you begin outside of the nucleus and enter energy is released. If you then reclaim that same amount of energy back to the nucleus and allow the proton to exit, you will be at the same condition as you started. The net round trip yields a balanced condition with no net energy transferred.
Dave -----Original Message----- From: mixent <[email protected]> To: vortex-l <[email protected]> Sent: Sat, Aug 11, 2012 10:57 pm Subject: Re: [Vo]:the Coil In reply to Axil Axil's message of Sat, 11 Aug 2012 21:52:52 -0400: Hi, [snip] > The coulomb barrier is symmetric. It take as much energy to leave a >nucleus as it take to get in. This is clearly not true. If it were then hot fusion wouldn't work, and there would be no Sun. It takes less energy to get in than it takes to get out. The difference between the two is the net energy of the reaction. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
