In reply to Axil Axil's message of Fri, 10 Aug 2012 19:51:55 -0400: Hi, [snip] >Sorry, please excuse me; I was thinking about the Triple alpha process: > > > http://www.youtube.com/watch?feature=player_detailpage&v=Z0IPWmm7GDc > > >With Carbon 12 => Boron 11 (5 protons and 6 neutrons) with a proton emission > > >The net positive charge of the gas from proton emmision causes the back >current as seen coming comin from the electrodes as the gas contracts.
The reaction 3*He4 => C12 yields 7.27 MeV. (Helium burning in stars). Removing a proton from C12 to produce B11 *costs* 15.96 MeV. Hence adding a proton to B11 with the ensuing production of 3 alpha particles produces 8.68 MeV. When the proton fuses with B11 it momentarily creates C12*, which usually splits into three alphas, but not always. (C12* is C12 in an excited state - it has an additional 15.96 MeV that it desperately wants to get rid of). > > >Cheers: Axil > > > >On Fri, Aug 10, 2012 at 7:28 PM, <mix...@bigpond.com> wrote: > >> In reply to Axil Axil's message of Fri, 10 Aug 2012 18:05:03 -0400: >> Hi, >> [snip] >> >This causes aneutronic >> >fusion of three helium atoms into Boron11 and a proton. >> >> This reaction doesn't happen. It's endothermic to the tune of about 8 MeV. >> In >> fact the reverse reaction (p+B11 -> 3 * He4) is the dream of hot fusion >> scientists. >> >> Regards, >> >> Robin van Spaandonk >> >> http://rvanspaa.freehostia.com/project.html >> >> Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
