In the Bose-Einstein condensation of electrons that surround the nuclear active site, the positron is annihilated by an entangled electron that is a member of the condensate. The energy of this event is spread throughout the BEC ensemble.
The BEC acts as a shield for positron emissions. This is why BEC formation is so important to the LENR process. While we are thinking about these things: With the rule that odd numbered nuclei do not produce LENR reactions because that would stop the LENR cycle then as follows: In the alternative cases where an electron, proton or neutron enters the Ni62 nucleus as follows: The proton in the Ni62 atom would turn into a neutron producing cobalt 62. A cobalt/nickel loop would ensue. This would be a valid cycle but according to DGT not much cobalt is found in the ash. In the W&L case where a neutron enters the NI atom, an odd numbered nucleus NI63 is produced. According to DGT, odd numbered nuclei do not participate in LENR reactions. In the proton case hen a proton enters the Ni62 nucleus, Cu63 would result and the LENR cycle would stop. On Mon, Apr 22, 2013 at 3:35 PM, Jones Beene <[email protected]> wrote: > Axil,**** > > ** ** > > Copper-62 is an unstable isotope with a 10 minute half-life and an > unmistakable signature. Rossi has never demonstrated substantial > radioactivity to independent observers. The Swedes would have seen and > reported this, since they looked specifically for the signature, but found > nothing.**** > > ** ** > > It is true that Cu-62 was mentioned by Rossi early on, and in his early > patent application - but AFAIK he has dropped all mention lately, since > there would be the tell-tale signature on decay, which has not turned up in > testing.**** > > ** ** > > Copper-62 is a positron emitter. Positrons annihilation essentially cannot > be easily hidden, especially when the underlying reaction is in the 5 kW > power level. The evidence would have been crystal clear.**** > > ** ** > > Focardi encouraged Rossi to have a positron detector at the original demo, > which he did - but it showed nothing. Thus they dropped the copper-62 > explanation and also dropped the lead shielding.**** > > ** ** > > ** ** > > *From:* Axil Axil [mailto:[email protected]] > *Sent:* Monday, April 22, 2013 12:02 PM > > *To:* vortex-l > *Subject:* Re: [Vo]:The Mexican hat**** > > ** ** > > *I am trying to state this as gently as possible without sounding like a > bully.***** > > > I like that. You are not too hard to take when you are gentle.**** > > When you are gentle you are more persuasive.**** > > You may be right about the excess electrons.**** > > With neutron decay Ni62 transmutes into Cu62 as follows:**** > > Nickel-62 -> Copper-62, electron, anti-electron-neutrino-> **** > > The proton wants to become a neutron again and reconverts to nickel > through radioactive decay.**** > > Copper-62-> Nickel-62, positron, electron-neutrino**** > > The energy for this endless loop nickel/ copper comes from the Higgs field. > **** > > But maybe before copper has a chance to decay**** > > Copper-62-> Zinc-62, positron, electron-neutrino**** > > Then through radioactive decay**** > > Zinc-62-> Copper-62->Nickel-62 with associated positrons and electron > neutrinos.**** > > > So there may not be many free electrons produced. The free electrons will > be balanced (destroyed) by the positrons produced by radioactive decay.*** > * > > In general, a balance in things is a good thing.**** > > But this balance is disturbed by alpha decay and multiple alpha decay > (resulting in Be).**** > > The Ni becomes iron, chromium titanium, calcium and so on.**** > > ** ** > > On Mon, Apr 22, 2013 at 1:54 PM, Jones Beene <[email protected]> wrote:* > *** > > Axil,**** > > **** > > I am trying to state this as gently as possible without sounding like a > bully. You still did not address the question of "huge amounts of > electric current" which was a direct quote from you.**** > > **** > > Since Rossi says that a precision instrument is required to see the emf, > and since any Radio Shack multimeter will show milliamps – we must assume > he is talking about microamps. There is no valid reason to go further than > that.**** > > **** > > Why do you insist on polluting serious attempts to understand LENR with > this crap about 10^20 neutrons? You seem to have no grasp of the > implications of that statement.**** > > **** > > It only demonstrates that you have no prior understanding of nuclear > physics.**** > > **** > > Jones**** > > **** > > **** > > **** > > *From:* Axil Axil [mailto:[email protected]] > *Sent:* Monday, April 22, 2013 10:17 AM > *To:* vortex-l > *Subject:* Re: [Vo]:The Mexican hat**** > > **** > > > http://www.e-catworld.com/2013/01/rossi-electromagnetic-force-produced-directly-from-the-hot-cat/ > **** > > **** > > Rossi: Electromotive Force Produced Directly from the Hot Cat [UPDATED]*** > * > > **** > > On Mon, Apr 22, 2013 at 1:13 PM, Axil Axil <[email protected]> wrote:**** > > Andrea Rossi **** > > January 2nd, 2013 at 9:01 > AM<http://www.journal-of-nuclear-physics.com/?p=771&cpage=5#comment-522231> > **** > > Dear Steven Karels: > Yes, that is exactly the path we are walking through. Too soon to give > precise info, though. > Warm Regards, > A.R.**** > > · Steven Karels **** > > January 2nd, 2013 at 8:22 > AM<http://www.journal-of-nuclear-physics.com/?p=771&cpage=5#comment-522155> > **** > > Dear Andrea Rossi,**** > > Your previous postings mentioned “direct EMF” coming from the reactor > core. Could you please clarify? I have heard of possible direct conversion > to electricity by coupling the energy from a charged moving particle into a > “transformer”. In general, is this the approach by which you are able to > extract “direct EMF”?**** > > **** > > Jones Beene wrote:**** > > > From: Axil Axil**** > > This is another reason why I believe that Rossi is telling > the truth about his reactor. He says that his reactor produces huge amounts > of electric current. So much current in fact that he can tap this current > directly rather than use heat to steam conversion to produce electric > power.**** > > What? Where does Rossi say "huge amounts of electric current" ? > > In fact he says that the emf detected required very precise measurement > instrumentation. This implies microamps, not hundreds of amps. > > As usual, Axil is off by orders of magnitude. His 10^20 neutron decay > garbage is nothing but complete BS. > > Rossi claimed, on Dec 30 to one his sycophants - > Dear Bernie Koppenhofer: > You are touching a very important point: during these very days, and also > during the more recent tests, we are working on this issue. I think we will > be able to produce directly e.m.f., but much work has to be done. Actually, > we already produced direct e.m.f. with the reactors at high temperature, > and > we measured it with the very precise measurement instrumentation introduced > by the third party expert, but we are not ready for an industrial > production, while we are at a high level of industrialization for the > production of heat and, at this point, also of high temperature steam, > which > is the gate to the Carnot Cycle. Thank you for your good comment. > > Warm Regards, > A.R.**** > > **** > > **** > > ** ** >
