Well, Mark - there is one more detail about the 300 eV value which could also be coincidental … or not.
Less than a month ago we talked about serendipity and hexavalency. http://www.mail-archive.com/[email protected]/msg78698.html … and now it turns out that the release of 6 electrons from Nickel will provide the 300 eV Millsean energy “hole” which is necessary to force hydrogen into deep redundancy. It may be “all Greek” to some vorticians but “hexa” does imply the magic number here since that is where the Rydberg value lines up almost exactly.. Nickel has 10 valence electrons and taking 6 of them all at once seems unlikely – but what about the situation where there is a chemical see-saw in which 6 electrons move back-and-forth at a rapid resonant rate and the on occasion, this allows hydrogen to be forced into this kind of redundancy. From: MarkI-ZeroPoint Well, it certainly has many properties that make it a good candidate to house the core, so is it just a coincidence that it also happens to be non-magnetic, and what’s inside is ferromagnetic… You know what they say about coincidences! ;-) The electrical resistivity units I do not recognize; it’s usually reported in Ω⋅m (Ohm*m)… Still intrigued by your revelations about ~300eV… you put some puzzle pieces together and there seems to be a picture developing. Hope you continue to travel down that path, Sherlock! -Mark Iverson From: Jones Beene [mailto:[email protected]] Sent: Friday, May 24, 2013 9:35 AM To: [email protected] Subject: RE: [Vo]:Why did Rossi prevent detailed measurement of the power input? Mark, In the end – it looks to me like the secrecy about the wave-from was probably due to similarity to the Energetics patent and not a “trade secret” per se; and that Rossi is using the magnetic properties of the waveform to stimulate the nickel powder, which is itself ferromagnetic. Would you agree? SS spec sheet: http://www.northamericanstainless.com/wp-content/uploads/2010/10/Grade-310S-314.pdf From: MarkI-ZeroPoint “It is possible that RF would pass through these ceramics, no?” Yes, more than likely that RF could pass thru a ceramic, however, if electrically conductive, then probably not. An E or B field will most likely go thru the ceramics, but the reactor vessel is stainless steel: “The most important element of the E-Cat HT was lodged inside the structure. It consisted of an AISI 310 steel cylinder, 3 mm thick and 33 mm in diameter, housing the powder charges. Two AISI 316 steel cone-shaped caps were hot-hammered in the cylinder, sealing it hermetically. Cap adherence was obtained by exploiting the higher thermal expansion coefficient of AISI 316 with respect to AISI 310 steel.” End caps are made of 316 due to greater coef of thermal expansion: 310: 15.5x10-6 316: 16.5x10-6 For our noninvasive glucose sensor, we used a Ni-plated soft iron housing which acts as both a faraday cage to shield outside EM, and to complete a magnetic flux circuit which channels the flux from internal permanent mags. Since stainless is only about 50% Fe, a mag fld should penetrate it, but due to its electrical conductivity, an E-fld would not. In that case, is he using magnetic properties to help control the reaction? Is it causing alignment of grains, or forcing dipole oscillations to be aligned? -Mark From: Jones Beene Robert Lynn wrote: And all of the resistive heating elements are positioned around it, so they do nothing but deliver heat to the reactor contents - no special magnetic or electrical excitation can pass through the reactor vessel. There is still confusion on that point. From Forbes article: http://www.forbes.com/sites/markgibbs/2013/05/20/finally-independent-testing-of-rossis-e-cat-cold-fusion-device-maybe-the-world-will-change-after-all/ They described the E-Cat HT as a cylinder having a silicon nitride ceramic outer shell, 33 cm in length, and 10 cm in diameter. A second cylinder made of a different ceramic material (corundum) was located within the shell... It is possible that RF would pass through these ceramics, no?
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