So how do you imagine it inductively heats the powder given low AC frequency, weak solenoid magnetic field, tiny cross section area powder, and high resistivity of nickel near its melting point?
The physics + mathematics to estimate the magnetic field strength and eddy currents induced are high-school /freshman physics level (estimate wire turns, solenoid inductance => applied voltage gives current rate of change, => solenoid magnetic field strength rate of change => eddy currents induced in particles of given diameter - power dissipation, so you could very quickly do some calculation to confirm or disprove your theory, and numbers would at least give foundation to your hope. On 16 October 2014 09:25, Axil Axil <[email protected]> wrote: > Does this not indicate that the wire must be producing inductive heating > in the powder? > > On Wed, Oct 15, 2014 at 8:23 PM, Robert Lynn < > [email protected]> wrote: > >> the resistor wire expands with respect to the alumina as it heats up, >> breaking any bonding contact, or lifting the wire of the inner alumina tube >> in more and more places and leading to less and less conductive contact - >> prompting the wire to heat up as more as more of the energy it transmits to >> the reactor must be via radiation and conduction through gas rather than >> contact-conduction. This is the likely what makes it appear that there is >> a gain above 1. >> >> On 16 October 2014 01:13, Alan Fletcher <[email protected]> wrote: >> >>> New version with embedded wires. >>> >>> http://lenr.qumbu.com/rossi_hotcat_oct2014_141014b.php >>> >>> Here I've also assumed that the wires are a simple single strand, rather >>> than the spiral form used in the earlier tests, and are in good thermal >>> contact with the Alumina. >>> >>> >> >
