Why did Rossi say that a DC current applied to the wire would not work? Why does the startup procedure need for a magnetic field to be applied?
On Wed, Oct 15, 2014 at 9:56 PM, Robert Lynn <robert.gulliver.l...@gmail.com > wrote: > So how do you imagine it inductively heats the powder given low AC > frequency, weak solenoid magnetic field, tiny cross section area powder, > and high resistivity of nickel near its melting point? > > The physics + mathematics to estimate the magnetic field strength and eddy > currents induced are high-school /freshman physics level (estimate wire > turns, solenoid inductance => applied voltage gives current rate of change, > => solenoid magnetic field strength rate of change => eddy currents induced > in particles of given diameter - power dissipation, so you could very > quickly do some calculation to confirm or disprove your theory, and numbers > would at least give foundation to your hope. > > On 16 October 2014 09:25, Axil Axil <janap...@gmail.com> wrote: > >> Does this not indicate that the wire must be producing inductive heating >> in the powder? >> >> On Wed, Oct 15, 2014 at 8:23 PM, Robert Lynn < >> robert.gulliver.l...@gmail.com> wrote: >> >>> the resistor wire expands with respect to the alumina as it heats up, >>> breaking any bonding contact, or lifting the wire of the inner alumina tube >>> in more and more places and leading to less and less conductive contact - >>> prompting the wire to heat up as more as more of the energy it transmits to >>> the reactor must be via radiation and conduction through gas rather than >>> contact-conduction. This is the likely what makes it appear that there is >>> a gain above 1. >>> >>> On 16 October 2014 01:13, Alan Fletcher <a...@well.com> wrote: >>> >>>> New version with embedded wires. >>>> >>>> http://lenr.qumbu.com/rossi_hotcat_oct2014_141014b.php >>>> >>>> Here I've also assumed that the wires are a simple single strand, >>>> rather than the spiral form used in the earlier tests, and are in good >>>> thermal contact with the Alumina. >>>> >>>> >>> >> >
