date:20100115

Re: [symfony-users] Open an Excel file

2010-01-15 Thread Gareth McCumskey

With just plain old PHP and even some Javascript built in this is actually very 
difficult if not impossible to do as PHP was never designed to interact with a 
users PC. Javascript was however designed to run client-side but does not have 
direct access to a users hard drive for obvious security reasons. The only way 
you may get past this is to use another plugin. I am not sure which plugin 
would be useful, perhaps Flash, but as far as I know even Java (not Javascript) 
cannot do this (but I stand to be corrected on that). You may also want to look 
into Google Gears (which I have not yet used). The problem with these scenarios 
is that you will need the user to download a plugin for their browser.

Essentially, the easiest way is to let them upload, the changes are made by 
PHP, then PHP prompts the user to re-download the changed file.

Regards

Gareth McCumskey

- Original Message -
From: bibijosh dorothee.arno...@gmail.com
To: symfony users symfony-users@googlegroups.com
Sent: Thursday, January 14, 2010 7:02:43 PM GMT +02:00 Harare / Pretoria
Subject: [symfony-users] Open an Excel file

Hi, I'm quite new to Symfony, and not really good at php in the first
place. So if someone could give me a hand here.

Here is what my website does for now :
 - Open an explorer window so the user can upload an excel file
 - Modify that file
 - Save it on my server.

Here is what I would like to do :
 - Open an explorer window so the user can upload an excel file
 - Modify that file AND THEN open it in an Excel Window. (I can only
manage to display it in my webpage, whichdoesn't look good at all,
I heard it could be because of the mime type actions...)
AND/OR
 - Save it on the user's computer, where it was first uploaded from,
without the user having to do anything.

I'll welcome any advice.

I'm using php5, Symfony 1.0 and IE 6

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Re: [symfony-users] Open an Excel file

2010-01-15 Thread DEEPAK BHATIA

Hi I used the

I used the sfPhpExcelPlugin-1.0.2.zip from the

http://www.symfony-project.org/plugins/sfPhpExcelPlugin/1_0_2

In this I used this both for creating an excel file and downloading the same
using PHP.

Also I used the same for uploading an excel file and then reading the
contents of the excel file.

Regards

Deepak Bhatia

On Fri, Jan 15, 2010 at 1:45 PM, Gareth McCumskey gmccums...@gmail.comwrote:

With just plain old PHP and even some Javascript built in this is actually
very difficult if not impossible to do as PHP was never designed to interact
with a users PC. Javascript was however designed to run client-side but does
not have direct access to a users hard drive for obvious security reasons.
The only way you may get past this is to use another plugin. I am not sure
which plugin would be useful, perhaps Flash, but as far as I know even Java
(not Javascript) cannot do this (but I stand to be corrected on that). You
may also want to look into Google Gears (which I have not yet used). The
problem with these scenarios is that you will need the user to download a
plugin for their browser.

Essentially, the easiest way is to let them upload, the changes are made by
PHP, then PHP prompts the user to re-download the changed file.

Regards

Gareth McCumskey

- Original Message -
From: bibijosh dorothee.arno...@gmail.com
To: symfony users symfony-users@googlegroups.com
Sent: Thursday, January 14, 2010 7:02:43 PM GMT +02:00 Harare / Pretoria
Subject: [symfony-users] Open an Excel file

Hi, I'm quite new to Symfony, and not really good at php in the first
place. So if someone could give me a hand here.

Here is what my website does for now :
- Open an explorer window so the user can upload an excel file
- Modify that file
- Save it on my server.

Here is what I would like to do :
- Open an explorer window so the user can upload an excel file
- Modify that file AND THEN open it in an Excel Window. (I can only
manage to display it in my webpage, whichdoesn't look good at all,
I heard it could be because of the mime type actions...)
AND/OR
- Save it on the user's computer, where it was first uploaded from,
without the user having to do anything.

I'll welcome any advice.

I'm using php5, Symfony 1.0 and IE 6

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Re: [symfony-users] Open an Excel file

2010-01-15 Thread Benoit Montuelle

Hi,

I think there may be at least 2 solutions :

1st)
- Make for form so user can upload one or more file
- Modify that file in php, this point may be though, as php excel writers
have generally limited support. You can try something like this
http://pear.php.net/package/Spreadsheet_Excel_Writer , or if possible use
xlsx which is XML data.
- Redirect the browser and force downloading the file, the user will have to
accept the download and choose place where to put it.

2nd) As your clients are IE6 you can use some kind of activeX to handle xls
files directly on user's computer, if you're not fluent in php but are in
C#, VB or C++ this can be a better solultion.
Somme dll's already exists to modify/generate excel files But the main
disadvantage is that it will never work on any other browser than IE. As far
as I know with activeX autorised by browser you can have access to full
computer ressources, as a regular windows program.
Once I saw an app that can : interact with scanner device on local computer,
process picture to pdf on local computer, then upload it back to the server.
The server was PHP5 (without OSS framework) and client were winXP+IE6

I Know generally PHP developers avoid solution like this because of its
compatibility problem, but it still exists and being used by many intranet
apps.

Last but not least, if you're starting a new app, don't use symfony 1.0,
you'll find more reliable ressources for symfony 1.4 now.

Regards

2010/1/14 bibijosh dorothee.arno...@gmail.com

Hi, I'm quite new to Symfony, and not really good at php in the first
place. So if someone could give me a hand here.

Here is what my website does for now :
- Open an explorer window so the user can upload an excel file
- Modify that file
- Save it on my server.

I'll welcome any advice.

I'm using php5, Symfony 1.0 and IE 6

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[symfony-users] Re: doctrine many to one one the same table

2010-01-15 Thread Tom Ptacnik

Yes, you are right. In this multiselect box can be all his children,
and also all folders without a parent. But there can't be a folders
which have another parent folder.


On 12 led, 19:33, smellycat37 charley.mail...@gmail.com wrote:
 if a folder has a parent with the reference on folder_id, he has
 children with the same reference...
 so it's a relation 1:n... so it could be possible to have in a form :
 1- the parent (the folder who have as id the folder_id of the current
 item) in a select box
 2- the children (all folders who have as folder_id , the id of the
 current folder) in a mutli select box

 On 12 jan, 19:22, Tom Ptacnik to...@tomor.cz wrote:



  I think that if you want a multiselect box for the children you will
  need a many to many relationship... think about how to store the
  informations from this multiselect box...

  Or if you don't want a M:N relationship then you have to not show (in
  this multiselect box) a folders which already has a parent ... because
  you can't store it's folder_id if it already has a parent...

  I hope you will understand my ideas :)

  On 12 led, 01:16, smellycat37 charley.mail...@gmail.com wrote:

   Hello,

   I have this schema structure
   Folder:
     columns:
       id:  { type: integer, primary: true }
       name: { type: string(50), notnull: true }
       folder_id: { type: integer, notnull: true }
     relations:
       Parent: {onDelete: CASCADE, local: folder_id, foreign: id,
   foreignAlias: children}

   the symfony doctrine:build-form commande build the
   BaseFolderForm.class.php with two widgets :
   1 - the id widget
   2 - folder_id a sfWidgetFormDoctrineChoice (select box) containing the
   parent

   But i need a third one:
   3 - folders_list a sfWidgetFormDoctrineChoice (multi select box)
   containing all the children

   is it possible?

   If you have any idea, thanks for your response,
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[symfony-users] Using same database for two projects

2010-01-15 Thread DEEPAK BHATIA

Hi,

If we want to use the same database for the two projects in Symfony 1.1, how
can we achieve that. I guess we just need to execute step1 and step 2 below.

=

1. php symfony propel:build-model
2. php symfony cc
3. php symfony configure:database mysql://root:@localhost/rtdb2
4. php symfony propel:build-sql
5. mysqladmin -u root -p create rtdb2
6. mysql -u root -p rtdb2  data/sql/lib.model.schema.sql
7. php symfony propel:insert-sql
8. php symfony propel:build-schema
9. php symfony propel:build-schema --xml
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[symfony-users] Base GeneratorConfiguration not found

2010-01-15 Thread HAUSa

When I go to my application, it says only this:
Fatal error: Class 'BasePageGeneratorConfiguration' not found in /srv/
www/vhosts/startersspecialist.nl/httpdocs/apps/controlpanel/modules/
page/lib/pageGeneratorConfiguration.class.php on line 11

I think it has something to do with the admin generator, but what? I
cannot recall the class and don't know where I should find it.
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[symfony-users] Re: FormFilter - sfWidgetFormChoice 'multiple' = true ... error

2010-01-15 Thread Tom Ptacnik

Nobody filter a list by checkboxes or by a multiple selectbox?


On 11 led, 20:51, Tom Ptacnik to...@tomor.cz wrote:
 Hello,

 I have classic admin generated backend (Symfony 1.4). Today I've tried
 to customize the filter for the list view.

 The problem is that I want to filter by multiple select. So I've
 changed default widgets in configure method in my TicketFormFilter
 class from:

 'tkstate'    = new sfWidgetFormChoice(array('choices' = array('' =
 '', 'new' = 'new', 'waitingforuser' = 'waitingforuser',
 'waitingforadmin' = 'waitingforadmin', 'closed' = 'closed',
 'deleted' = 'deleted'))),

 'tkstate'    = new sfValidatorChoice(array('required' = false,
 'choices' = array('new' = 'new', 'waitingforuser' =
 'waitingforuser', 'waitingforadmin' = 'waitingforadmin', 'closed' =
 'closed', 'deleted' = 'deleted'))),

 to

 $this-widgetSchema['tkstate'] = new sfWidgetFormChoice(array
 ('choices' = array('' = '', 'new' = 'new', 'waitingforuser' =
 'waitingforuser', 'waitingforadmin' = 'waitingforadmin', 'closed' =
 'closed', 'deleted' = 'deleted'), 'multiple' = true));

         $this-validatorSchema['tkstate'] = new sfValidatorChoice(array
 ('required' = false, 'choices' = array('new' = 'new',
 'waitingforuser' = 'waitingforuser', 'waitingforadmin' =
 'waitingforadmin', 'closed' = 'closed', 'deleted' = 'deleted'),
 'multiple' = true));

 ... only added the multiple parameter.

 But when i click on the filter submit (with two selected items: new,
 waitingforuser), I got this error:

 stack trace
 at ()
 in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
 \vendor\doctrine\Doctrine\Connection.php line 1082 ...
             $message .= sprintf('. Failing Query: %s', $query);
         }
         $exc  = new $name($message, (int) $e-getCode());

         if ( ! isset($e-errorInfo) || ! is_array($e-errorInfo)) {
             $e-errorInfo = array(null, null, null, null);
         }
 at Doctrine_Connection-rethrowException(object('PDOException'), object
 ('Doctrine_Connection_Statement'))
 in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
 \vendor\doctrine\Doctrine\Connection\Statement.php line 269 ...
 at Doctrine_Connection_Statement-execute(array('new',
 'waitingforuser'))
 in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
 \vendor\doctrine\Doctrine\Connection.php line 1006 ...
 at Doctrine_Connection-execute('SELECT COUNT(*) AS num_results FROM
 ticket t WHERE t.tkstate = ?', array('new', 'waitingforuser'))
 in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
 \vendor\doctrine\Doctrine\Connection.php line 800 ...
 at Doctrine_Connection-fetchAll('SELECT COUNT(*) AS num_results FROM
 ticket t WHERE t.tkstate = ?', array('new', 'waitingforuser'))
 in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
 \vendor\doctrine\Doctrine\Query.php line 2108 ...

 The problem seems to be in the generated query ... the should be OR
 statement (for this multiple choice), but it looks that it's generated
 classic simple WHERE, and as parameter is send whole array... and
 doctrine is confused of course

 Maybe the problem is only in my application.

 Did anybody of you ever tried to filter by multiple select?
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[symfony-users] Re: Having trouble modifying filters.

2010-01-15 Thread Tom Ptacnik

you can access to a user object via sfContext::getInstance()-getUser
() if you user standard user object and credentials system...


On 15 led, 00:41, Darren884 darren...@gmail.com wrote:
 Yes but how do I call the sfFormFilter object? I had tried $this-

 configuration-getFilterForm but it runs the class again.

 On Jan 14, 2:56 pm, Daniel Lohse annismcken...@googlemail.com wrote:



  sfFormFilter does have setOptions as it's only a subclass of BaseForm.

  Daniel

  On Jan 14, 2010, at 11:08 PM, Darren884 wrote:

   Actually that did not work. This is a flaw in Symfony itself, there is
   no way to pass values to the configre() method in the filters class.
   This needs to be fixed.

   On Jan 14, 12:11 pm, Darren884 darren...@gmail.com wrote:
   Hi guys, I had to actually add an argument to the original
   ConfigurationModelGenerator file and mimick the getForm() function to
   pass options. I have no idea why this wasn't implemented in the first
   place but who knows.

   On Jan 13, 3:04 pm, Darren884 darren...@gmail.com wrote:

   In my form I use the setOptions to pass my user object so I can check
   the credentials in the form class if I want to display or hide fields,
   however in the FilterForm class there is no setOptions and class
   variables do not seem to be shared among functions. How am I to get
   the user object into my FormFilter class from the action in order to
   check credentials against it and hide or display fields? Is there a
   different method in Symfony other than the __construct to get
   variables?

   Thanks,
   Darren
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[symfony-users] Re: Have it so if a user doesnt fill in a field it stays as it was?

2010-01-15 Thread Tom Ptacnik

Left it unfilled, and then when saving the profile don't change the
password if the password field is blank..

Also you have to optimize a validation process for this behaviour.



On 14 led, 18:08, Darren884 darren...@gmail.com wrote:
 HI basically I want to make it so as if a user is filling out their
 account options if they don't change their password it stays as it is.
 This is very common with profile sites and such.

 On Jan 14, 6:17 am, Alexandru-Emil Lupu gang.al...@gmail.com wrote:



  what do you mean? if a user does not complete a field, and validation stop
  the process to have the password field filled in with previous entry?
  i yes, then i am not sure you can. also ... is not a good practice AFAIK.
  Alecs

  On Thu, Jan 14, 2010 at 1:44 AM, Darren884 darren...@gmail.com wrote:
   I have a password field and I want it so if the user doesn't fill it
   in it stays the same value. How do I accomplish this? I also have a
   password confirmation field.

   Thanks

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  Have a nice day!
  Alecs

  As programmers create bigger  better idiot proof programs, so the universe
  creates bigger  better idiots!
  I am on web:  http://www.alecslupu.ro/
  I am on twitter:http://twitter.com/alecslupu
  I am on linkedIn:http://www.linkedin.com/in/alecslupu
  Tel: (+4)0748.543.798
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Re: [symfony-users] widget multiple option

2010-01-15 Thread Javier Garcia


On 01/14/2010 11:20 PM, Gabo wrote:

Help!!

I have this in schema:

documents_users:
   columns:
document_id: { type: integer }
user_id: { type: integer }
created_at:  { type: timestamp }

y en the form, i change the widget user_id for this:

'user_id' = new sfWidgetFormDoctrineChoice(array('model' = 
'sfGuardUser', 'add_empty' = true, *'multiple'= true*)),


In the form the widget is multiple option... but i want to save the 
form, print error:



SQLSTATE[HY093]: Invalid parameter number: number of bound
variables does not match number of tokens

i net to save more inserts becouse i selected 2 users_id in the 
form...but symfony dont save??





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Hi,

could you send the part that appears below the error message?

Javi
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[symfony-users] Re: how can I check the name of module and action in layout ?

2010-01-15 Thread wissl

I believe $sf_request-getParameter('action') and $sf_request-
getParameter('module') should also work.


On 14 Jan., 21:38, dziobacz aaabbbcccda...@gmail.com wrote:
 thx people !! :)

 On 14 Sty, 20:57, tirengarfio tirengar...@gmail.com wrote:

  Well put $ before both..

  On Jan 14, 8:55 pm, Javier Garcia tirengar...@gmail.com wrote:

   On 01/14/2010 08:51 PM, dziobacz wrote: How can I check on the layout 
   current module and action which use this
layout ?

   Hi  dziobac:

   sf_context-getModuleName() and sf_context- getActionName()

   Javi


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[symfony-users] sfForm clean bind

2010-01-15 Thread DoRiaN

Hello,

How to delete values after bind() ?
I want to clean my form.

Thank,
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Re: [symfony-users] Re: Deployed project does not load any javascript file

2010-01-15 Thread Gábor Fási

Do you call include_javascripts() in your layout? Did you clear your
cache after the deployment?

On Fri, Jan 15, 2010 at 08:47, domnuprofesor domnuprofe...@gmail.com wrote:
 yes, of course I cheked the html code...
 No script tag is generated. Firebug reports no JS files loaded nor
 any js request that could have failed.
 So, no requests for js files are performed whatsoever.

 Any ideas?

 On Jan 15, 9:29 am, Alvaro Videla harryjek...@gmail.com wrote:
 have you tried checking the HTML code of your page and see if there are some 
 script tags including the Javascript?

 On Jan 15, 2010, at 3:24 PM, domnuprofesor wrote:

  Hi there!

  I just finished a project and I deployed on a server using symfony
  built in deploy tool.
  Everything is ok with the exception that NO JAVASCRIPT FILE IS LOADED.

  The js files are on the server in /web/js. I don't get a failed
  request to the files, it just does not request the files.

  On localhost both prod and dev environments are working as expected.
  On the server dev environment is working as well, only the prod
  environment has this issue with not loading js files.

  Can you help me with this one?

  Thank you!
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[symfony-users] Why doesn't the mydomain.com - www.mydomain rewrite rule work in this .htaccess file?

2010-01-15 Thread YTH


Dear all,

Hi, I would like to allow users getting redirected to www.mydomain.com if 
they enter mydomain.com in the browser. I added rewrite rule in the 
..htaccess that comes with symfony 1.2 but the rewrite rule does not seem to 
work. When users enter mydomain.com, their browser continues to use 
mydomain.com, being unaware of the rewrite rule that I added.


The .htaccess file is shown below:

Options +FollowSymLinks +ExecCGI

IfModule mod_rewrite.c
 RewriteEngine On

 # this is the rewrite rule that I added
 # it should redirect to www.mydomain.com if http_post variable does not 
start with www

 # but I have no idea why it does not work
 RewriteCond %{HTTP_HOST}   !^www\.mydomain\.com [NC]
 RewriteCond %{HTTP_HOST}   !^$
 RewriteRule ^/(.*) http://www.mydomain.com/$1 [L,R=301]

 # uncomment the following line, if you are having trouble
 # getting no_script_name to work
 #RewriteBase /

 # we skip all files with .something
 #RewriteCond %{REQUEST_URI} \..+$
 #RewriteCond %{REQUEST_URI} !\.html$
 #RewriteRule .* - [L]

 # we check if the .html version is here (caching)
 RewriteRule ^$ index.html [QSA]
 RewriteRule ^([^.]+)$ $1.html [QSA]
 RewriteCond %{REQUEST_FILENAME} !-f

 # no, so we redirect to our front web controller
 RewriteRule ^(.*)$ index.php [QSA,L]
/IfModule


I suspected that mod_rewrite is either not installed on the server (it's a 
shared hosting server), or it prevents people from doing any override. After 
a second thought, I changed my mind because all routing rules such as 
/user/new, /product/show defined in routing.yml work perfectly. And for 
these routing rules to work, the following rewrite rule defined in .htaccess 
must have got executed:


RewriteRule ^(.*)$ index.php [QSA,L]

This means that this might be the problem of my rewrite rule.
Any ideas?

Many thanks to you all. 
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Re: [symfony-users] Why doesn't the mydomain.com - www.mydomain rewrite rule work in this .htaccess file?

2010-01-15 Thread Sebastian Schulze

The second line after the RewriteCond is wrong.
It should be more like:

RewriteCond %{HTTP_HOST} ^mydomain\.com$ [NC]
RewriteRule ^(.*) http://www.mydomain.com$1 [QSA,L,R=301]

Bascht

On 15.01.10 14:16, YTH wrote:
 Dear all,
 
 Hi, I would like to allow users getting redirected to www.mydomain.com
 if they enter mydomain.com in the browser. I added rewrite rule in the
 ..htaccess that comes with symfony 1.2 but the rewrite rule does not
 seem to work. When users enter mydomain.com, their browser continues to
 use mydomain.com, being unaware of the rewrite rule that I added.
 
 The .htaccess file is shown below:
 
 Options +FollowSymLinks +ExecCGI
 
 IfModule mod_rewrite.c
  RewriteEngine On
 
  # this is the rewrite rule that I added
  # it should redirect to www.mydomain.com if http_post variable does not
 start with www
  # but I have no idea why it does not work
  RewriteCond %{HTTP_HOST}   !^www\.mydomain\.com [NC]
  RewriteCond %{HTTP_HOST}   !^$
  RewriteRule ^/(.*) http://www.mydomain.com/$1 [L,R=301]
 
  # uncomment the following line, if you are having trouble
  # getting no_script_name to work
  #RewriteBase /
 
  # we skip all files with .something
  #RewriteCond %{REQUEST_URI} \..+$
  #RewriteCond %{REQUEST_URI} !\.html$
  #RewriteRule .* - [L]
 
  # we check if the .html version is here (caching)
  RewriteRule ^$ index.html [QSA]
  RewriteRule ^([^.]+)$ $1.html [QSA]
  RewriteCond %{REQUEST_FILENAME} !-f
 
  # no, so we redirect to our front web controller
  RewriteRule ^(.*)$ index.php [QSA,L]
 /IfModule
 
 
 I suspected that mod_rewrite is either not installed on the server (it's
 a shared hosting server), or it prevents people from doing any override.
 After a second thought, I changed my mind because all routing rules such
 as /user/new, /product/show defined in routing.yml work perfectly. And
 for these routing rules to work, the following rewrite rule defined in
 .htaccess must have got executed:
 
 RewriteRule ^(.*)$ index.php [QSA,L]
 
 This means that this might be the problem of my rewrite rule.
 Any ideas?
 
 Many thanks to you all.
 


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[symfony-users] Re: doctrine many to one one the same table

2010-01-15 Thread Tom Ptacnik

I was thinking about it and I'm not right...

You can, of course, display all folders in multiselectbox (child
folders, free folders and folders with different parent folder) but,
when you select a folder which has another parent, and set it as a
child folder for actual folder, it will be child only for actual
folder (the original parent folder will be gone)

Hope you understand :)



On 15 led, 10:25, Tom Ptacnik to...@tomor.cz wrote:
 Yes, you are right. In this multiselect box can be all his children,
 and also all folders without a parent. But there can't be a folders
 which have another parent folder.

 On 12 led, 19:33, smellycat37 charley.mail...@gmail.com wrote:



  if a folder has a parent with the reference on folder_id, he has
  children with the same reference...
  so it's a relation 1:n... so it could be possible to have in a form :
  1- the parent (the folder who have as id the folder_id of the current
  item) in a select box
  2- the children (all folders who have as folder_id , the id of the
  current folder) in a mutli select box

  On 12 jan, 19:22, Tom Ptacnik to...@tomor.cz wrote:

   I think that if you want a multiselect box for the children you will
   need a many to many relationship... think about how to store the
   informations from this multiselect box...

   Or if you don't want a M:N relationship then you have to not show (in
   this multiselect box) a folders which already has a parent ... because
   you can't store it's folder_id if it already has a parent...

   I hope you will understand my ideas :)

   On 12 led, 01:16, smellycat37 charley.mail...@gmail.com wrote:

Hello,

I have this schema structure
Folder:
  columns:
    id:  { type: integer, primary: true }
    name: { type: string(50), notnull: true }
    folder_id: { type: integer, notnull: true }
  relations:
    Parent: {onDelete: CASCADE, local: folder_id, foreign: id,
foreignAlias: children}

the symfony doctrine:build-form commande build the
BaseFolderForm.class.php with two widgets :
1 - the id widget
2 - folder_id a sfWidgetFormDoctrineChoice (select box) containing the
parent

But i need a third one:
3 - folders_list a sfWidgetFormDoctrineChoice (multi select box)
containing all the children

is it possible?

If you have any idea, thanks for your response,
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[symfony-users] Re: Using same database for two projects

2010-01-15 Thread Tom Ptacnik

Two different projects with different tables/models? Or some tables
will be shared? Or all tables will be shared?


On 15 led, 10:31, DEEPAK BHATIA toreachdee...@gmail.com wrote:
 Hi,

 If we want to use the same database for the two projects in Symfony 1.1, how
 can we achieve that. I guess we just need to execute step1 and step 2 below.

 =

 1. php symfony propel:build-model
 2. php symfony cc
 3. php symfony configure:database mysql://root:@localhost/rtdb2
 4. php symfony propel:build-sql
 5. mysqladmin -u root -p create rtdb2
 6. mysql -u root -p rtdb2  data/sql/lib.model.schema.sql
 7. php symfony propel:insert-sql
 8. php symfony propel:build-schema
 9. php symfony propel:build-schema --xml
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[symfony-users] Re: sfForm clean bind

2010-01-15 Thread ken

What's your purpose of clearing the form of its values?

On Jan 15, 7:23 pm, DoRiaN doria...@gmail.com wrote:
 Hello,

 How to delete values after bind() ?
 I want to clean my form.

 Thank,
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[symfony-users] Re: sfForm clean bind

2010-01-15 Thread DoRiaN

When the form isValid(), i display again the same form empty to add a
new element.

I do new Form because i don't know how to clean values.


On 15 jan, 14:27, ken marfillas...@gmail.com wrote:
 What's your purpose of clearing the form of its values?

 On Jan 15, 7:23 pm, DoRiaN doria...@gmail.com wrote:

  Hello,

  How to delete values after bind() ?
  I want to clean my form.

  Thank,
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Re: [symfony-users] Why doesn't the mydomain.com - www.mydomain rewrite rule work in this .htaccess file?

2010-01-15 Thread YTH


Dear Bascht,

Great! It works now.
By the way, the rewrite rule that I used (which does not work) is from this 
page, under the URL Layout section and after the Canonical Hostnames 
heading:


http://httpd.apache.org/docs/2.0/misc/rewriteguide.html

I just don't quite understand what's the problem with the rule, making it 
failed to work.



- Original Message - 
From: Sebastian Schulze maili...@bascht.com

To: symfony-users@googlegroups.com
Sent: Friday, January 15, 2010 9:21 PM
Subject: Re: [symfony-users] Why doesn't the mydomain.com - www.mydomain 
rewrite rule work in this .htaccess file?




The second line after the RewriteCond is wrong.
It should be more like:

RewriteCond %{HTTP_HOST} ^mydomain\.com$ [NC]
RewriteRule ^(.*) http://www.mydomain.com$1 [QSA,L,R=301]

Bascht

On 15.01.10 14:16, YTH wrote:

Dear all,

Hi, I would like to allow users getting redirected to www.mydomain.com
if they enter mydomain.com in the browser. I added rewrite rule in the
..htaccess that comes with symfony 1.2 but the rewrite rule does not
seem to work. When users enter mydomain.com, their browser continues to
use mydomain.com, being unaware of the rewrite rule that I added.

The .htaccess file is shown below:

Options +FollowSymLinks +ExecCGI

IfModule mod_rewrite.c
 RewriteEngine On

 # this is the rewrite rule that I added
 # it should redirect to www.mydomain.com if http_post variable does not
start with www
 # but I have no idea why it does not work
 RewriteCond %{HTTP_HOST}   !^www\.mydomain\.com [NC]
 RewriteCond %{HTTP_HOST}   !^$
 RewriteRule ^/(.*) http://www.mydomain.com/$1 [L,R=301]

 # uncomment the following line, if you are having trouble
 # getting no_script_name to work
 #RewriteBase /

 # we skip all files with .something
 #RewriteCond %{REQUEST_URI} \..+$
 #RewriteCond %{REQUEST_URI} !\.html$
 #RewriteRule .* - [L]

 # we check if the .html version is here (caching)
 RewriteRule ^$ index.html [QSA]
 RewriteRule ^([^.]+)$ $1.html [QSA]
 RewriteCond %{REQUEST_FILENAME} !-f

 # no, so we redirect to our front web controller
 RewriteRule ^(.*)$ index.php [QSA,L]
/IfModule


I suspected that mod_rewrite is either not installed on the server (it's
a shared hosting server), or it prevents people from doing any override.
After a second thought, I changed my mind because all routing rules such
as /user/new, /product/show defined in routing.yml work perfectly. And
for these routing rules to work, the following rewrite rule defined in
.htaccess must have got executed:

RewriteRule ^(.*)$ index.php [QSA,L]

This means that this might be the problem of my rewrite rule.
Any ideas?

Many thanks to you all.







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[symfony-users] Re: Have it so if a user doesnt fill in a field it stays as it was?

2010-01-15 Thread ken

You mean the form fills the field with the password as default value?
I don't think that is ever a good idea. If you want a change password
form, here is the class that I'm using.

http://gist.github.com/278064

On Jan 15, 6:38 pm, Tom Ptacnik to...@tomor.cz wrote:
 Left it unfilled, and then when saving the profile don't change the
 password if the password field is blank..

 Also you have to optimize a validation process for this behaviour.

 On 14 led, 18:08, Darren884 darren...@gmail.com wrote:



  HI basically I want to make it so as if a user is filling out their
  account options if they don't change their password it stays as it is.
  This is very common with profile sites and such.

  On Jan 14, 6:17 am, Alexandru-Emil Lupu gang.al...@gmail.com wrote:

   what do you mean? if a user does not complete a field, and validation stop
   the process to have the password field filled in with previous entry?
   i yes, then i am not sure you can. also ... is not a good practice AFAIK.
   Alecs

   On Thu, Jan 14, 2010 at 1:44 AM, Darren884 darren...@gmail.com wrote:
I have a password field and I want it so if the user doesn't fill it
in it stays the same value. How do I accomplish this? I also have a
password confirmation field.

Thanks

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   As programmers create bigger  better idiot proof programs, so the 
   universe
   creates bigger  better idiots!
   I am on web:  http://www.alecslupu.ro/
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[symfony-users] Re: sfForm clean bind

2010-01-15 Thread Tom Ptacnik

If you want to clear the form after it's proccessed, you can simply do
redirect to the same form (in the action)


On 15 led, 12:23, DoRiaN doria...@gmail.com wrote:
 Hello,

 How to delete values after bind() ?
 I want to clean my form.

 Thank,
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Re: [symfony-users] Re: Using same database for two projects

2010-01-15 Thread DEEPAK BHATIA

Thanks for all the scenarios. If possible, please send me the solution for
some tables as well as all tables.

Regards

Deepak Bhatia

On Fri, Jan 15, 2010 at 6:54 PM, Tom Ptacnik to...@tomor.cz wrote:

Two different projects with different tables/models? Or some tables
will be shared? Or all tables will be shared?

On 15 led, 10:31, DEEPAK BHATIA toreachdee...@gmail.com wrote:
Hi,

If we want to use the same database for the two projects in Symfony 1.1,
how
can we achieve that. I guess we just need to execute step1 and step 2
below.

1. php symfony propel:build-model
2. php symfony cc
3. php symfony configure:database mysql://root:@localhost/rtdb2
4. php symfony propel:build-sql
5. mysqladmin -u root -p create rtdb2
6. mysql -u root -p rtdb2 data/sql/lib.model.schema.sql
7. php symfony propel:insert-sql
8. php symfony propel:build-schema
9. php symfony propel:build-schema --xml

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[symfony-users] Re: Having trouble modifying filters.

2010-01-15 Thread ken

If you are using the admin generator, override apps/myapp/modules/
mymodule/lib/mymoduleGeneratorConfiguration.php

public function getFilterOptions()
{
  return array('sf_user' = sfContext::getInstance()-getUser());
}

On Jan 15, 6:35 pm, Tom Ptacnik to...@tomor.cz wrote:
 you can access to a user object via sfContext::getInstance()-getUser
 () if you user standard user object and credentials system...

 On 15 led, 00:41, Darren884 darren...@gmail.com wrote:



  Yes but how do I call the sfFormFilter object? I had tried $this-

  configuration-getFilterForm but it runs the class again.

  On Jan 14, 2:56 pm, Daniel Lohse annismcken...@googlemail.com wrote:

   sfFormFilter does have setOptions as it's only a subclass of BaseForm.

   Daniel

   On Jan 14, 2010, at 11:08 PM, Darren884 wrote:

Actually that did not work. This is a flaw in Symfony itself, there is
no way to pass values to the configre() method in the filters class.
This needs to be fixed.

On Jan 14, 12:11 pm, Darren884 darren...@gmail.com wrote:
Hi guys, I had to actually add an argument to the original
ConfigurationModelGenerator file and mimick the getForm() function to
pass options. I have no idea why this wasn't implemented in the first
place but who knows.

On Jan 13, 3:04 pm, Darren884 darren...@gmail.com wrote:

In my form I use the setOptions to pass my user object so I can check
the credentials in the form class if I want to display or hide fields,
however in the FilterForm class there is no setOptions and class
variables do not seem to be shared among functions. How am I to get
the user object into my FormFilter class from the action in order to
check credentials against it and hide or display fields? Is there a
different method in Symfony other than the __construct to get
variables?

Thanks,
Darren
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[symfony-users] Re: Base GeneratorConfiguration not found

2010-01-15 Thread Tom Ptacnik

It should be located(generated) in
/cache/controlpanel/modules/page/lib/


On 15 led, 10:46, HAUSa jeroen_heeft_behoefte_aan_r...@hotmail.com
wrote:
 When I go to my application, it says only this:
 Fatal error: Class 'BasePageGeneratorConfiguration' not found in /srv/
 www/vhosts/startersspecialist.nl/httpdocs/apps/controlpanel/modules/
 page/lib/pageGeneratorConfiguration.class.php on line 11

 I think it has something to do with the admin generator, but what? I
 cannot recall the class and don't know where I should find it.
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[symfony-users] Re: FormFilter - sfWidgetFormChoice 'multiple' = true ... error

2010-01-15 Thread ken

You need to add a custom query method in your filter class.

  public function addTkskateColumnQuery($query, $field, $value)
  {
if (!empty($value))
{
  $query-addWhereIn('p. tkstate', $value);
}
  }


On Jan 15, 5:50 pm, Tom Ptacnik to...@tomor.cz wrote:
 Nobody filter a list by checkboxes or by a multiple selectbox?

 On 11 led, 20:51, Tom Ptacnik to...@tomor.cz wrote:



  Hello,

  I have classic admin generated backend (Symfony 1.4). Today I've tried
  to customize the filter for the list view.

  The problem is that I want to filter by multiple select. So I've
  changed default widgets in configure method in my TicketFormFilter
  class from:

  'tkstate'    = new sfWidgetFormChoice(array('choices' = array('' =
  '', 'new' = 'new', 'waitingforuser' = 'waitingforuser',
  'waitingforadmin' = 'waitingforadmin', 'closed' = 'closed',
  'deleted' = 'deleted'))),

  'tkstate'    = new sfValidatorChoice(array('required' = false,
  'choices' = array('new' = 'new', 'waitingforuser' =
  'waitingforuser', 'waitingforadmin' = 'waitingforadmin', 'closed' =
  'closed', 'deleted' = 'deleted'))),

  to

  $this-widgetSchema['tkstate'] = new sfWidgetFormChoice(array
  ('choices' = array('' = '', 'new' = 'new', 'waitingforuser' =
  'waitingforuser', 'waitingforadmin' = 'waitingforadmin', 'closed' =
  'closed', 'deleted' = 'deleted'), 'multiple' = true));

          $this-validatorSchema['tkstate'] = new sfValidatorChoice(array
  ('required' = false, 'choices' = array('new' = 'new',
  'waitingforuser' = 'waitingforuser', 'waitingforadmin' =
  'waitingforadmin', 'closed' = 'closed', 'deleted' = 'deleted'),
  'multiple' = true));

  ... only added the multiple parameter.

  But when i click on the filter submit (with two selected items: new,
  waitingforuser), I got this error:

  stack trace
  at ()
  in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
  \vendor\doctrine\Doctrine\Connection.php line 1082 ...
              $message .= sprintf('. Failing Query: %s', $query);
          }
          $exc  = new $name($message, (int) $e-getCode());

          if ( ! isset($e-errorInfo) || ! is_array($e-errorInfo)) {
              $e-errorInfo = array(null, null, null, null);
          }
  at Doctrine_Connection-rethrowException(object('PDOException'), object
  ('Doctrine_Connection_Statement'))
  in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
  \vendor\doctrine\Doctrine\Connection\Statement.php line 269 ...
  at Doctrine_Connection_Statement-execute(array('new',
  'waitingforuser'))
  in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
  \vendor\doctrine\Doctrine\Connection.php line 1006 ...
  at Doctrine_Connection-execute('SELECT COUNT(*) AS num_results FROM
  ticket t WHERE t.tkstate = ?', array('new', 'waitingforuser'))
  in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
  \vendor\doctrine\Doctrine\Connection.php line 800 ...
  at Doctrine_Connection-fetchAll('SELECT COUNT(*) AS num_results FROM
  ticket t WHERE t.tkstate = ?', array('new', 'waitingforuser'))
  in SF_ROOT_DIR\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib
  \vendor\doctrine\Doctrine\Query.php line 2108 ...

  The problem seems to be in the generated query ... the should be OR
  statement (for this multiple choice), but it looks that it's generated
  classic simple WHERE, and as parameter is send whole array... and
  doctrine is confused of course

  Maybe the problem is only in my application.

  Did anybody of you ever tried to filter by multiple select?
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[symfony-users] Re: widget multiple option

2010-01-15 Thread ken

Have you defined the relation of documents_users to users in your
schema.yml? Are you trying to achieve the behavior of sfGuardUser to
sfGuardPermission via sfGuardUserPermission?

On Jan 15, 7:01 pm, Javier Garcia tirengar...@gmail.com wrote:
 On 01/14/2010 11:20 PM, Gabo wrote:





  Help!!

  I have this in schema:

  documents_users:
     columns:
      document_id: { type: integer }
      user_id:     { type: integer }
      created_at:  { type: timestamp }

  y en the form, i change the widget user_id for this:

  'user_id'     = new sfWidgetFormDoctrineChoice(array('model' =
  'sfGuardUser', 'add_empty' = true, *'multiple'= true*)),

  In the form the widget is multiple option... but i want to save the
  form, print error:

      SQLSTATE[HY093]: Invalid parameter number: number of bound
      variables does not match number of tokens

  i net to save more inserts becouse i selected 2 users_id in the
  form...but symfony dont save??

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 Hi,

 could you send the part that appears below the error message?

 Javi
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[symfony-users] Re: Base GeneratorConfiguration not found

2010-01-15 Thread ken

Are you trying to override a module in a plugin?

On Jan 15, 9:47 pm, Tom Ptacnik to...@tomor.cz wrote:
 It should be located(generated) in
 /cache/controlpanel/modules/page/lib/

 On 15 led, 10:46, HAUSa jeroen_heeft_behoefte_aan_r...@hotmail.com
 wrote:



  When I go to my application, it says only this:
  Fatal error: Class 'BasePageGeneratorConfiguration' not found in /srv/
  www/vhosts/startersspecialist.nl/httpdocs/apps/controlpanel/modules/
  page/lib/pageGeneratorConfiguration.class.php on line 11

  I think it has something to do with the admin generator, but what? I
  cannot recall the class and don't know where I should find it.
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[symfony-users] doctrine migration fails

2010-01-15 Thread pulse00

hi all,

i've tried to use the doctrine:migrate task, but i'm getting the
following error:

php symfony doctrine:migrate

 doctrine  Migrating from version 0 to 1

  The following errors
occurred:

   - SQLSTATE[23000]: Integrity constraint violation: 1217 Cannot
delete or update a parent row: a foreign key constraint fails. Failing
Query: DROP TABLE taggable_tag

The project uses the doctrine taggable extension (http://www.doctrine-
project.org/extension/Taggable/1_2-1_0).

Anyone got migrations working together with this extension? I'm using
symfony version 1.4 (svn)

thanks!

-robert
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Re: [symfony-users] Re: Deployed project does not load any javascript file

2010-01-15 Thread Francisc Nopcea

I don't call any include_javascripts().
I rely on the view.yml of each module I have defined.

I tried clearing the cache but no success.

Any ideas?

On Fri, Jan 15, 2010 at 3:03 PM, Gábor Fási maerl...@gmail.com wrote:

Do you call include_javascripts() in your layout? Did you clear your
cache after the deployment?

On Fri, Jan 15, 2010 at 08:47, domnuprofesor domnuprofe...@gmail.com
wrote:
yes, of course I cheked the html code...
No script tag is generated. Firebug reports no JS files loaded nor
any js request that could have failed.
So, no requests for js files are performed whatsoever.

Any ideas?

On Jan 15, 9:29 am, Alvaro Videla harryjek...@gmail.com wrote:
have you tried checking the HTML code of your page and see if there are
some script tags including the Javascript?

On Jan 15, 2010, at 3:24 PM, domnuprofesor wrote:

Hi there!

I just finished a project and I deployed on a server using symfony
built in deploy tool.
Everything is ok with the exception that NO JAVASCRIPT FILE IS LOADED.

The js files are on the server in /web/js. I don't get a failed
request to the files, it just does not request the files.

On localhost both prod and dev environments are working as expected.
On the server dev environment is working as well, only the prod
environment has this issue with not loading js files.

Can you help me with this one?

Thank you!
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[symfony-users] Re: sfWidgetFormPropelChoice appears as ul class=checkbox_list

2010-01-15 Thread Doraemon

But in the documentation, it seems that it's supposed to be in a line
by default.

On Jan 15, 2:06 am, Alexandru-Emil Lupu gang.al...@gmail.com wrote:
 Maybe by adding some css?
 Alecs

 sent via htc magic

 On Jan 15, 2010 6:40 AM, Doraemon theoneandonlydorae...@gmail.com wrote:

 In the 
 documentation:http://www.symfony-project.org/cookbook/1_2/en/make-a-choice

 It shows the checkbox in a line, however, when I try it, it appears in
 an unordered list.

 My code:

 $this-widgetSchema['category'] = new sfWidgetFormPropelChoice(array(
                'model' = 'ItemCategoryList',
                'key_method' = 'getPrimaryKey',
                'order_by' = array('Name','asc'),
                'expanded' = true,
                'multiple' = true,
        ));

 I simply use ? echo $form; ? in my view to display my form. But this
 is what appears in the browser.

 HTML:

 ul class=checkbox_listliinput name=addItemForm[category][]
 type=checkbox value=1 id=addItemForm_category_1 /nbsp;label
 for=addItemForm_category_1Books/label/li
 .../ul

 I want it to appear in a line just like the documentation, how do I do
 this?

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Re: [symfony-users] Re: Deployed project does not load any javascript file

2010-01-15 Thread Gábor Fási

In view.yml you specify which js files should be included when you
call include_javascripts() in your layout. Put the call right before
your /body tag and it should work.
sfCommonFilter did this for you, but it has been deprecated in
1.3/1.4. See
http://www.symfony-project.org/tutorial/1_4/en/upgrade#chapter_161aacbf11b8cc24bbdc6951ba0fb57d_sub_removal_of_the_common_filter

On Fri, Jan 15, 2010 at 15:35, Francisc Nopcea domnuprofe...@gmail.com wrote:
I don't call any include_javascripts().
I rely on the view.yml of each module I have defined.

I tried clearing the cache but no success.

Any ideas?

On Fri, Jan 15, 2010 at 3:03 PM, Gábor Fási maerl...@gmail.com wrote:

Do you call include_javascripts() in your layout? Did you clear your
cache after the deployment?

Any ideas?

On Jan 15, 9:29 am, Alvaro Videla harryjek...@gmail.com wrote:
have you tried checking the HTML code of your page and see if there are
some script tags including the Javascript?

On Jan 15, 2010, at 3:24 PM, domnuprofesor wrote:

Hi there!

I just finished a project and I deployed on a server using symfony
built in deploy tool.
Everything is ok with the exception that NO JAVASCRIPT FILE IS
LOADED.

The js files are on the server in /web/js. I don't get a failed
request to the files, it just does not request the files.

On localhost both prod and dev environments are working as expected.
On the server dev environment is working as well, only the prod
environment has this issue with not loading js files.

Can you help me with this one?

Thank you!
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Re: [symfony-users] widget multiple option

2010-01-15 Thread Gabo

Yes, I create the relation with the tables..

but the widget is multiple = true print this error, but is false no print
error:

THE ERROR:

*Notice*: Undefined offset: 2 in *
C:\development\sfprojects\bambu\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrine\Connection\Pgsql\Exception.php
* on line *101*
*
*
*SQLSTATE[HY093]: Invalid parameter number: number of bound variables does
not match number of tokens*

2010/1/15 Javier Garcia tirengar...@gmail.com

On 01/14/2010 11:20 PM, Gabo wrote:

Help!!

I have this in schema:

documents_users:
columns:
document_id: { type: integer }
user_id: { type: integer }
created_at: { type: timestamp }

y en the form, i change the widget user_id for this:

'user_id' = new sfWidgetFormDoctrineChoice(array('model' =
'sfGuardUser', 'add_empty' = true, *'multiple'= true*)),

In the form the widget is multiple option... but i want to save the form,
print error:

SQLSTATE[HY093]: Invalid parameter number: number of bound variables does
not match number of tokens
i net to save more inserts becouse i selected 2 users_id in the form...but
symfony dont save??

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Hi,

could you send the part that appears below the error message?

Javi

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Re: [symfony-users] Re: Deployed project does not load any javascript file

2010-01-15 Thread Francisc Nopcea

Gábor, thank you for the hint.
I don't use symfony 1.3, I use symfony 1.2.9 so the problem should not be
there.

On Fri, Jan 15, 2010 at 5:08 PM, Gábor Fási maerl...@gmail.com wrote:

On Fri, Jan 15, 2010 at 15:35, Francisc Nopcea domnuprofe...@gmail.com
wrote:
I don't call any include_javascripts().
I rely on the view.yml of each module I have defined.

I tried clearing the cache but no success.

Any ideas?

On Fri, Jan 15, 2010 at 3:03 PM, Gábor Fási maerl...@gmail.com wrote:

Do you call include_javascripts() in your layout? Did you clear your
cache after the deployment?

Any ideas?

On Jan 15, 9:29 am, Alvaro Videla harryjek...@gmail.com wrote:
have you tried checking the HTML code of your page and see if there
are
some script tags including the Javascript?

On Jan 15, 2010, at 3:24 PM, domnuprofesor wrote:

Hi there!

I just finished a project and I deployed on a server using symfony
built in deploy tool.
Everything is ok with the exception that NO JAVASCRIPT FILE IS
LOADED.

The js files are on the server in /web/js. I don't get a failed
request to the files, it just does not request the files.

On localhost both prod and dev environments are working as
expected.
On the server dev environment is working as well, only the prod
environment has this issue with not loading js files.

Can you help me with this one?

Thank you!
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[symfony-users] Get raw/unprocessed route in a Template

2010-01-15 Thread Donald

I am trying to better integrate a Javascript Datagrid that I'm using
with the symfony routing system. I want to pass the unprocessed route
for to view a particular entity type to the javascript class.

For example, I have the following route:

email_show
/email/:id.sf_format

When displaying a datagrid on the client that was built with
Javascript, I can't simply use url_for('email_show'), because I need
to generate the URL *after* PHP has finished processing (on the client
side).

1. When the Javascript requests the emails (via XMLHttpRequest) to
populate the datagrid with, use url_for to embed the URL for each
entity in the entity itself. (I don't like this, it sounds messy).

2. Pass the raw route above to the Javascript, and have it build the
URL for the entity whenever it needs it.

So if I was to use method 2 above, I would need a way to get the
unprocessed route via a template. (I would imagine some helper like
route_for('email_show'))
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[symfony-users] 2 layers of embedded forms

2010-01-15 Thread jondro

I'm trying to have 2 layers of embedded forms, meaning i have a
Product model that has many Series and the Series have many Documents.
I wanted to have the series form embedded in the product and the
documents embedded in series thus having two layers of embedding. I
followed the advanced techniques tutorial on Forms but the problem is
that in the Series form i cannot check if the newDocument form was
filled because the form is never bound so getValues returns an empty
array.
Is it possible to achieve the above easly?
Thanks,
Andrew
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[symfony-users] Embed optional form

2010-01-15 Thread Palleas

Hi there !

I'm working on a simple Quiz plugin for my Symfony project, so I'm
heavily using the Symfony embedding form system to have one big form
to edit my whole quiz :
- Quiz title
- Quiz questions
- For each questions, a list of proposals

I want to be able to add a question and a proposal when I edit my
quiz, so here is what I do :
abstract class PluginNoeQuizQuestionForm extends
BaseNoeQuizQuestionForm
{
  public function configure()
  {
parent::configure();
$this-useFields(array('label', 'multiple'));

foreach ($this-getObject()-getProposals() as $id =
$proposition)
{
  $pForm = new NoeQuizProposalForm($proposition);
  $this-embedForm(sprintf('proposal%d', $id), $pForm);
}

// new proposal
$newProposal = new NoeQuizProposal();
$newProposal-setQuestion($this-getObject());

$pForm = new NoeQuizProposalForm($newProposal);
$pForm-getValidator('value')-setOption('required', false);
$pForm-getValidator('is_valid')-setOption('required', false);

$this-embedForm('newproposal', $pForm);
  }
}

As you can see, my $pForm does not contain any mandatory fields
because I want the user to be able to add a proposal to one question
only if he wants to. So it works, I don't have any fatal error, but
every time I save my form, I have an empty proposal that is created.

Can you see where I went wrong and how to fix this ? ;)

Thanks!
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[symfony-users] Symfony PHP Developer in Pune, India

2010-01-15 Thread Aceadi

Hello friends,

I have a good job opening for symfony and thought it will better to
share it here.


Here's the description:


Position: Senior Software Engineer - PHP

Company Profile: Our firm is a product engineering company that builds
commercial grade software for its customers. Our customers are ISVs
that are building, implementing and maintaining cutting edge products,
focused on time to market, client satisfaction, brand recognition, and
technology advantage. We help our customers meet these objectives. Our
approach to software development is characterized by our refreshing
approach best articulated as ‘Fresh Thinking! New Ideas!’. We have the
right blend of experience and can-do attitude. We deploy high-end
infrastructure facilities, state-of-the-art technology and best-in-
class resources to meet and exceed customer expectations.

Job Description:

We have an opening for a SSE / SE - PHP in Pune, India.

Key responsibilities:

   * Part of development team.
   * Participate in project scope definition and requirements
definition.
   * Write/review requirements and design documents.
   * Periodically communicate with client and provide them project
status.
   * Code applications using PHP 5, MySQL 5, AJAX and JavaScript.
   * Configure Linux, Apache, PHP and MySQL for development, QA and
production environments.

Candidate Will Have:

   * Overall 3+ years of experience for SSE level with experience in
PHP, Symfony frameworks, JavaScript, Apache and Linux servers
(including Linux command line and SSH).
   * Strong SQL and data manipulation skills (joining tables,
calculating fields, writing complex sql queries, etc).
   * Good knowledge of HTML, DHTML and CSS.
   * Good verbal and written communication skills.
   * Hands on skills on LAMP technologies.
   * applications using LAMP technologies.
   * Candidate should be able to manage a team of developers or
complete projects alone.
   * BE /B.Tech/ MCA from reputed institute

To be considered for this post email your resume
to:shi...@apexglobal.co.in

Please feel free to pass on the opportunity to your friends.

Thanks,
Adi
http://www.appliedeye.com
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Re: [symfony-users] Re: Deployed project does not load any javascript file

2010-01-15 Thread Alexandru-Emil Lupu

Are your files chowned to the apache group? Does symfony has access on your
ymls for parsing? Are you sure that you have the correct priviledges on your
cache folder?
Switch it to dev mode (i think you have to upload the dev file) and check
whatever your debug bar says.

I guess you are a romanian guy. If so, i think we could use a chat system to
try fixing your problem.
Alecs

sent via htc magic

On Jan 15, 2010 5:21 PM, Francisc Nopcea domnuprofe...@gmail.com wrote:

Gábor, thank you for the hint.
I don't use symfony 1.3, I use symfony 1.2.9 so the problem should not be
there.

On Fri, Jan 15, 2010 at 5:08 PM, Gábor Fási maerl...@gmail.com wrote:  
In view.yml you specif...

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[symfony-users] Editing a embedded form | Alterando um form embeddado

2010-01-15 Thread Cainã

Hi ppl,

I'm trying to alter a formulary which is being embedded on another form, in
order to change from table to divs, but i'm getting stuck, since i don't
know which template should i change. I tried to create a _form.php on both
of the forms, but it only change the father form, not the children ones.

Any ideas?

===

Olá pessoal!

Eu estou tentando alterar um formulário que está embeddado em outro, de
maneira que eu possa mudar ele de tabelas para divs, mas eu estou preso, já
que não sei que template eu devo alterar. Eu tentei criar um _form.php em
ambos os formulários, mas isso alterou apenas o formulário pai, não os
filhos.

Alguma idéia?
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[symfony-users] Identify the module in the referer URL.

2010-01-15 Thread Bruno Reis

Hi,

I have a referer url and I want to identify what is the module from that
url. So I will need to parse this url the same way symfony does it on it´s
routing or front controller. How can I parse a string containing a URL to
know what is the module in it considering the actual defined routing
configuration?

Thanks,
Bruno
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[symfony-users] sfDoctrineGuardPlugin in Project with multiple DB connections

2010-01-15 Thread Tiago Nunes


Hello,


I'm having some issues trying to use sfDoctrineGuardPlugin with a 
symfony project that uses 2 Doctrine connections.


I use 2 connections because I have a phpBB forum embedded in my project 
(using prestaForumConnectorPlugin), and I want to keep the forum and 
application specific databases separate.


What I want to know, is how to specify which connection should 
sfDoctrineGuardPlugin use to manage it's users, grups and permissions.


My current databases.yml reads as follows:

all:
  doctrine:
class: sfDoctrineDatabase
param:
  dsn: 
mysql:host=localhost;dbname=mydb;unix_socket=/var/run/mysqld/mysqld.sock

  username: mydb
  password: *

  forum:
class: sfDoctrineDatabase
param:
  dsn: 
mysql:host=localhost;dbname=forum;unix_socket=/var/run/mysqld/mysqld.sock

  username: forum
  password: *


and currently, sfDoctrineGuardPlugin is trying to create it's tables and 
manage it's users in the forum DB, which is not what I want.


What's the best way to tell the plugin to use the doctrine connection 
(instead of the forum one)?


The solutions that come to mind are:
1. Specify it in ProjectConfiguration::configureDoctrine() or 
ProjectConfiguration::setupPlugins() using the Doctrine Manager;
2. Change the plugin schema.yml to add the connection property to each 
model (bad and ugly, and not the preferred aproach);

3. Override some kind of plugin configuration and set it there? (how?)


What's the best way to do this?


Best Regards,
--
Tiago Nunes


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[symfony-users] Trying to add prototype functions

2010-01-15 Thread Javier Garcia


Hi,

I have added this in a template:

div id=mutsu class=apple/div

?php  if( $('mutsu').hasClassName(apple) ){
  alert(div has CSS apple class.); ?
   }

but when i load the template in the browser, the javascript alert is not 
showed.


Even in Netbeans i have a syntax error...

I added also the code above in a file where im using another prototype 
function (toggleClassName()) that works ok to be sure the problem is not 
caused because im not loading prototype.js. This is the code i say:


?php echo link_to_remote('Marcar como leido', array(

'url' = 'mensaje/cambiarEstadoLeido?id='.$m-getId(),

// Aqui se desplegará el resultado de la acción.
'update' = 'mensaje_'.$m,

complete = $('$m').toggleClassName('mensaje_1');,

)); ?

Any help?

Javi

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[symfony-users]

2010-01-15 Thread Chris LeBlanc

Chris LeBlanc
webPragmatist
(817) 988-9616
http://www.webPragmatist.com/
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[symfony-users] Re: Trying to add prototype functions

2010-01-15 Thread Tiago Nunes

Hi,

Just lose the ?php ? tags and you're good to go. ;)

You're trying to run javascript code in the PHP interpreter, which
isn't going to work.
All you have to do is replace your code with:

div id=mutsu class=apple/div

if( $('mutsu').hasClassName(apple) ) {
   alert(div has CSS apple class.);
}

and then that code will be executed on the client.

You're confusing PHP code with Javascript code, and that's not good.

PHP is intended to be executed *on the server*, before sending a
response to the client, while Javascript is supposed to execute *on
the client browser* (although it's also possible to run javascript
server-side).

Perhaps you're confused because symfony has some javascript helpers
that should be placed inside ?php ? tags, but these javascript
helpers are actually PHP functions, hence the tags.
When you want to write real javascript, you should write it outside
the ?php ? tags, or echo/print it from inside them.


Best Regards,
--
Tiago Nunes

On Jan 15, 8:09 pm, Javier Garcia tirengar...@gmail.com wrote:
 Hi,

 I have added this in a template:

 div id=mutsu class=apple/div

 ?php  if( $('mutsu').hasClassName(apple) ){
        alert(div has CSS apple class.); ?
     }

 but when i load the template in the browser, the javascript alert is not
 showed.

 Even in Netbeans i have a syntax error...

 I added also the code above in a file where im using another prototype
 function (toggleClassName()) that works ok to be sure the problem is not
 caused because im not loading prototype.js. This is the code i say:

 ?php echo link_to_remote('Marcar como leido', array(

              'url' = 'mensaje/cambiarEstadoLeido?id='.$m-getId(),

              // Aqui se desplegar el resultado de la acci n.
              'update' = 'mensaje_'.$m,

              complete = $('$m').toggleClassName('mensaje_1');,

              )); ?

 Any help?

 Javi
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Re: [symfony-users] Re: Trying to add prototype functions

2010-01-15 Thread Javier Garcia


On 01/15/2010 09:20 PM, Tiago Nunes wrote:

You're confusing PHP code with Javascript code, and that's not good.



Thanks Tiago, it's true..

Anywy im trying this:

?php echo javascript_tag(
  if($('mutsu').hasClassName(apple)) {
  alert(div has CSS apple class.);
   }
) ?

And it doesn't work...

No problem with ordinary code:

script type=text/javascript
   if($('mutsu').hasClassName(apple)) {
  alert(div has CSS apple class.);
   }
/script

Javi
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Re: [symfony-users] Re: Trying to add prototype functions

2010-01-15 Thread Rodrigo Ruiz Fuentes


El 15/01/2010 18:10, Javier Garcia escribió:

Thanks Tiago, it's true..

Anywy im trying this:

?php echo javascript_tag(
if($('mutsu').hasClassName(apple)) {
alert(div has CSS apple class.);
}
) ?

And it doesn't work...

No problem with ordinary code:

script type=text/javascript
if($('mutsu').hasClassName(apple)) {
alert(div has CSS apple class.);
}
/script

Javi




Javier, try just using (') into javascript_tag:

?php echo javascript_tag(
if($('mutsu').hasClassName('apple')) {  //= '
alert('div has CSS apple class.');  //= '
}
) ?


--
Rodrigo Ruiz Fuentes
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[symfony-users] is there a way to unsubscribe from this group?

2010-01-15 Thread Zeek

Was there any follow up regarding the bug that kept sending out email?
I recall Fabien looked into it and decided that Google was responsible
for the bug, but usually Google fixes such bugs in 24 or 48 hours.
This has been going on for 2 months or so. I've trouble believing that
Google would leave Google Groups broken for this long. I have
repeatedly tried to turn off the email from this group, but I keep
getting sent email.

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Re: [symfony-users] is there a way to unsubscribe from this group?

2010-01-15 Thread Stéphane

No, it's forever or you die instantaneously ! :-)

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Before Printing, Think about Your Environmental Responsibility!
Avant d'Imprimer, Pensez à Votre Responsabilitée Environnementale!

On Fri, Jan 15, 2010 at 11:13 PM, Zeek z...@thesecondroad.org wrote:

Was there any follow up regarding the bug that kept sending out email?
I recall Fabien looked into it and decided that Google was responsible
for the bug, but usually Google fixes such bugs in 24 or 48 hours.
This has been going on for 2 months or so. I've trouble believing that
Google would leave Google Groups broken for this long. I have
repeatedly tried to turn off the email from this group, but I keep
getting sent email.

You received this message because you are subscribed to the Google Groups "symfony users" group.

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[symfony-users] Re: Trying to add prototype functions

2010-01-15 Thread Tiago Nunes

In my last email I forgot the opening and closing javascript tags
(or the symfony helper), but Rodrigo already gave you the correct
answer.

Try:

?php echo javascript_tag(
if($('mutsu').hasClassName('apple')) {
alert('div has CSS apple class.');
}
) ?

--
Tiago Nunes


On Jan 15, 9:10 pm, Javier Garcia tirengar...@gmail.com wrote:
 On 01/15/2010 09:20 PM, Tiago Nunes wrote:

  You're confusing PHP code with Javascript code, and that's not good.

 Thanks Tiago, it's true..

 Anywy im trying this:

 ?php echo javascript_tag(
    if($('mutsu').hasClassName(apple)) {
        alert(div has CSS apple class.);
     }
 ) ?

 And it doesn't work...

 No problem with ordinary code:

 script type=text/javascript
     if($('mutsu').hasClassName(apple)) {
        alert(div has CSS apple class.);
     }
 /script

 Javi
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[symfony-users] How to access form filter object from within action?

2010-01-15 Thread Darren884

Can someone please tell me or show me an example on how to access a
form filter object from within an action so I can pass objects and
variables to it? This is killing me that Symfony does not allow
instances to travel globally.
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[symfony-users] Re: How to access form filter object from within action?

2010-01-15 Thread Darren884

Hi guys I finally found the solution. The setOptions does not work
with FilterForms.

You must edit /lib/generate/sfModelGeneratorConfiguration.php and make
getFilterForm resemble getForm so it can contain options.

The first instance of the getFilterForm will be called in the
protected buildQuery method which you can pass the options to.

I hope this helps anyone who had as much trouble as I did with this
issue.

Thanks,
Darren

On Jan 15, 2:51 pm, Darren884 darren...@gmail.com wrote:
 Can someone please tell me or show me an example on how to access a
 form filter object from within an action so I can pass objects and
 variables to it? This is killing me that Symfony does not allow
 instances to travel globally.
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[symfony-users] Re: Installation on shared hosting

2010-01-15 Thread Maciek

There is an easier way which works when you have ssh access.
Remove public_html directory and create symbolic link to project/web

ln -s where/your/project/is/web public_html

This method allows to place files wherever you want.
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