date:20071009

[jQuery] Re: Applying a string as a function?

2007-10-09 Thread Pops


You kidding me?  Thats way too easy! :-)

From now on, if I'm working on something and it takes me more than 10
minutes, I'm posting the question. :-)

Question:

I was thinking usng .apply here.  But I wasn't 100% sure how that
worked.

In general, if I see something like this:

xxx.apply(x,[y,z]);

From what I am understanding, x is this inside the function xxx and
x,y is the parameter to the function?

Is that correct in general when using .apply? or am I off base
completely? g

---
HLS


On Oct 9, 1:49 am, Michael Geary [EMAIL PROTECTED] wrote:
  From: Pops
   var how = (settings.show!=)?settings.show:show;
   eval($box.+how+());

 foo.bar means the same thing as foo['bar'], so this code is the same as:

   var how = (settings.show!=)?settings.show:show;
   $box[how]();

 Or a very clean and simple version:

   $box[ settings.show || 'show' ]();

 -Mike

[jQuery] Re: jQuery (Superfish) conflicting with swfobject

2007-10-09 Thread Wessa

Thanks Joel. appreciate the response.

I have used a hybrid of a slide out menu and a drop down as the third level.
I had cleared my cache, used the alt/refresh technique etc. and still cannot
see the drop down portion of the menu. I had a collegue do the same and he
can see what I see which as about 3 pixels of the menu and that's it.

Thanks for the heads-up on the ie font issue. I will sort that shortly.
Front page is now valid xhtml - client has discovered FTP and decided to
upload some old files for me over the past couple of days - just to keep me
on my toes :-)

In the meantime, can you confirm that you can see the drop down as well in
the ie's?

Cheers, Wes

Joel Birch wrote:

Hi Wessa,

I have checked your link and the menu is actually working in both IE6
and IE7. May I suggest you attempt to reload the page in a way that
avoids the cache? Holding Alt down when clicking the refresh button
seems to ignore the cache successfully on my PC.

I notice however, that you have run into the IE issue where fonts look
jaggy due to altering the opacity (fading) on a parent element that
does not have an explicitly defined solid background colour. You will
find that you need to apply a solid orange to the submenus in IE
instead of the pretty gradient you currently have, as this mostly
fixes this issue.

Good luck.
Joel Birch.

PS. Invalid HTML. There, I said it. ;)

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[jQuery] Re: Applying a string as a function?

2007-10-09 Thread Pops


How do you passing parameters via the settings?

An example is passing the speed

   var settings = {
 ...
 show: slideDown(50),
 ...
};

I get a syntax error for:

   $box[ settings.show || 'show' ]();

I guess I have to passing the parameter as setting?

   var settings = {
 ...
 show: slideDown.
 speed: 50,
 ...
};

   $box[ settings.show || 'show' ](settings.speed);

Correct?

--
HLS




On Oct 9, 1:49 am, Michael Geary [EMAIL PROTECTED] wrote:
  From: Pops
   var how = (settings.show!=)?settings.show:show;
   eval($box.+how+());

 foo.bar means the same thing as foo['bar'], so this code is the same as:

   var how = (settings.show!=)?settings.show:show;
   $box[how]();

 Or a very clean and simple version:

   $box[ settings.show || 'show' ]();

 -Mike

[jQuery] Re: Applying a string as a function?

2007-10-09 Thread Michael Geary


 From: Pops
 
 How do you passing parameters via the settings?
 
 An example is passing the speed
 
var settings = {
  ...
  show: slideDown(50),
  ...
 };
 
 I get a syntax error for:
 
$box[ settings.show || 'show' ]();
 
 I guess I have to passing the parameter as setting?
 
var settings = {
  ...
  show: slideDown.
  speed: 50,
  ...
 };
 
$box[ settings.show || 'show' ](settings.speed);
 
 Correct?

Makes sense to me. There are a few ways you could organize this, but that's
as good as any depending on your needs.

The first example failed because it was equivalent to:

$box[ slideDown(50) ]();

which *could* be valid code (if slideDown were a function that returned a
string containing a method name) but would be unlikely to be what you
wanted.

-Mike

[jQuery] Re: Applying a string as a function?

2007-10-09 Thread Michael Geary


 You kidding me?  Thats way too easy! :-)

You win some, you lose some. Next time it will be browser inconsistencies!
:-)

 I was thinking usng .apply here.  But I wasn't 100% sure how 
 that worked.
 
 In general, if I see something like this:
 
 xxx.apply(x,[y,z]);
 
 From what I am understanding, x is this inside the function xxx and
 x,y is the parameter to the function?
 
 Is that correct in general when using .apply? or am I off 
 base completely? g

100% correct. foo.call() can also be useful in some situations - the example
above would be:

   xxx.call( x, y, z );  // === xxx.apply( x, [y,z] );

In your first example:

  var how = (settings.show!=)?settings.show:show;
  eval($box.+how+());

you don't really need call or apply, since you aren't doing anything special
about this and aren't passing any arguments into the function.

There's an interesting use of apply in some code I posted earlier today
(slightly updated from the original post):

$.expire = function( fn, callback, interval, start ) {
var timer;
function set() {
timer = setTimeout( callback, interval );
}
if( start ) set();
return function() {
clearTimeout( timer );
set();
return fn.apply( this, arguments );
};
};

$.expire takes a function (fn) and returns a replacement function which sets
a timeout and then calls the original function. In order to pass through
both the this value and the argument list from the original function, the
code uses:

return fn.apply( this, arguments );

That can be useful for all sorts of things where you want to wrap an
existing function inside a new function that adds behavior before or after
the original function.

-Mike

[jQuery] Re: jQuery (Superfish) conflicting with swfobject

2007-10-09 Thread Wessa

Actually it is sorted now... using

ul.SubCategories{margin: 0px;height:800px}

So it was a css issue.

Thanks anyways for the help.

Cheers, Wes

Wessa wrote:

Thanks Joel. appreciate the response.

I have used a hybrid of a slide out menu and a drop down as the third
level. I had cleared my cache, used the alt/refresh technique etc. and
still cannot see the drop down portion of the menu. I had a collegue do
the same and he can see what I see which as about 3 pixels of the menu and
that's it.

In the meantime, can you confirm that you can see the drop down as well in
the ie's?

Cheers, Wes

Joel Birch wrote:

Hi Wessa,

Good luck.
Joel Birch.

PS. Invalid HTML. There, I said it. ;)

--
View this message in context:
http://www.nabble.com/jQuery-%28Superfish%29-conflicting-with-swfobject-tf4545960s27240.html#a13110750
Sent from the jQuery General Discussion mailing list archive at Nabble.com.

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