Dear R People:
I am attempting to install SparseM on R 2.15.0 on a Linux 11.10 system.
Here is the output
install.packages(SparseM,depen=TRUE)
Installing package(s) into ‘/home/erin/R/x86_64-pc-linux-gnu-library/2.15’
(as ‘lib’ is unspecified)
--- Please select a CRAN mirror for use in this
Hello,
I am trying to get the output from the numerical simulation of a system
of ordinary differential equations for a range of values for three
parameters. I am using the ode() function (deSolve package) to run the
numerical simulation and apply() to run the simulation function for each
Hi,
I have a list of IDs on a data frame and I want to extract information for
those IDs from an external database.
I did a workaround using the IN clause in SQL but when the number of IDs
is big this method doesn't work.
In other words, I want to create a join between a local and a external
Kebrab67--
It's difficult to answer in the absence of a small bit of representative
data, and more information about it. How is age76 recorded, as numerical
years or in categories (age ranges?) And what are years (you didn't
mention them as a variable in your data.)
That being said,
Hi,
I am working on linux and i need to reduce plot size (bar plot) so that i
can easily use in sweave. How can i implement it?
Regards
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Hi,
I have data set where i have col1,col2,col3,col4
i want to write a condition where the rows has to removed from the dataset
for col110
Please help,
Thanks
Santosh
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On 25.04.2012 08:21, Erin Hodgess wrote:
Dear R People:
I am attempting to install SparseM on R 2.15.0 on a Linux 11.10 system.
Here is the output
install.packages(SparseM,depen=TRUE)
Installing package(s) into ‘/home/erin/R/x86_64-pc-linux-gnu-library/2.15’
(as ‘lib’ is unspecified)
---
Seems you should re-read An Introduction to R that comes with it. Hint: look
for subset.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#.
On 25/04/2012 08:05, Uwe Ligges wrote:
On 25.04.2012 08:21, Erin Hodgess wrote:
Dear R People:
I am attempting to install SparseM on R 2.15.0 on a Linux 11.10 system.
Here is the output
install.packages(SparseM,depen=TRUE)
Installing package(s) into
Hi,
I have a quick question regarding RCOM and in particular the comInvoke
function. When we use comCreateObject we have a way to check the
object was properly created with comIsValidHandle; however, after
calling comInvoke the only way to check it worked as expected is to
use comGetProperty and
Hello,
I am comparing two ROC curves with bootstraping. However, some runs return
p-value = NA, and I have no clue why.
Is this anyhow related to like sample size or no sufficient numbers of
bootstraping? I used the default value (i.e. boot.n=2000), and the number
of observations are quite big
See inline comments.
On 25-04-2012, at 08:40, Adam Zeilinger wrote:
Hello,
I am trying to get the output from the numerical simulation of a system of
ordinary differential equations for a range of values for three parameters.
I am using the ode() function (deSolve package) to run the
On 25.04.2012 04:02, Manish Gupta wrote:
Hi,
I am working on linux and i need to reduce plot size (bar plot) so that i
can easily use in sweave. How can i implement it?
You can control the size of the plots from Sweave, no need to change
soemthing in the plts themselves (unless you want
Probably you got NAs in some bootstrap results, or you got a 0 variance,
or you hat 0 observations in a group you compared to another group?
Check the data and the separate results!
Uwe Ligges
On 25.04.2012 09:28, O wrote:
Hello,
I am comparing two ROC curves with bootstraping. However,
Hi,
Could someone help me with this please , im trying to use
Y = Attrition_data[,1] # extract labels from the data
msk = sample.split (Y, SplitRatio=3/4)
table(Y,msk)
to do the splitting but it keeps throwing up and error
Error: could not find function sample.split
Could you please help
Cross posting
http://stackoverflow.com/questions/10308955/how-to-reduce-image-size-in-sweave
The code you have provided there is unusable, I assume your problems come from
a lack of understanding how Sweave works (nothing to do with Linux).
Always make sure that
=
and
@
are always the first
Hey guys,
Does anyone have an example of a REALLY simple shell script in R.
Basically i want to run this command:
library(MASS)
wilcox.test(list1,list2,paired=TRUE,alternative=c(greater),correct=TRUE,exact=FALSE)
in a shell script something like this:
#!/bin/bash
R
library(MASS)
for i in *.out
On 04/25/2012 12:28 AM, ramonovelar wrote:
Hello,
I have a barplot where each row has quite long texts and I have used par
to make some room in the left:
par(mar=c(0, 17, 3, 0), oma=c(0, 0, 0, 0))
barplot2(prueba, main = l, col=colores, horiz=TRUE,las=1, cex.names=.7)
My problem is that main
Hi,
I have searched over the last two days to try and sort this problem but
unfortunately I cannot find the correct solution.
I have a main directory - Spectra
In this folder I have two subfolders Normal and Case
I am using a package MALDIquant for processing of mass spectrometry data,
Seems to work great!
I have a last question (or 2) for you about it, and I will leave you alone
afterwords, I promise :)
I tested your function process.all for the automatization. It seems to be
OK.
It's just when I'd like to save the filled data files.
If I name process.all, for example: test
Thanks again!
I would like to construct 14 new 'year' dummy variables. I have 14 years:
1992:2006 with 231 observations pr. year. The year dummies should assign a 1
if the observation is within the specific year and 0 otherwise. So for
example: 1992dummyvariable=1 if year=0 and so on.
P
--
Dear all
When using Sweave, I'm always hitting the same bump: I want to group
repetitive calls in a function, but I want both the results and the
function calls in the printed output. Let me explain myself.
Consider the following computation in an Sweave document:
summary(iris[,1:2])
Many many thanks for the tip and for authoring this function!
The final code for the plot goes like this:
par(mar=c(0, 17, 3, 0), oma=c(0, 0, 0, 0))
barplot2(prueba, col=colores, horiz=TRUE,las=1, cex.names=.7)
mtext(l,side = 3, at = getFigCtr()[1], line = 0.8, cex=1.5)
On Wed, Apr 25, 2012
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in
column 'a' and 'b'. I found a way but I am sure this is not the best
solution. So any ideas on how to optimize this would be great!
m - factor(c(a1, a1, a2, b1, b2, b3, d1, d1), ordered
= TRUE)
df - data.frame( a=
I don't think I have touched at anything at all. I'm very newbie to R and
to be honest I don't know what Ramdom.seed is. I will try to find out.
I have seen other messages about restoring random.seed, but in order to
check that the problem is really that I have used some Viewing data
commands.
On Wed, Apr 25, 2012 at 02:22:05PM +0200, Patrick Hausmann wrote:
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in
column 'a' and 'b'. I found a way but I am sure this is not the best
solution. So any ideas on how to optimize this would be great!
m -
Dear R list,
It appears that my request from yesterday got a bit garbled. I have
tried to rephrase and retype it - please let me know if you can help me
- I am having some trouble drawing a bar-graph with two groups, both of
which are stacked.
I would like to plot the conservation status
Dear list,
In order to find a solution to my problem, I created a third objective
function including both calculations done in the previous cases. This
function return a value (i.e. the value to be minimize by optim) equal to
the sum of the two sum of squares, but it does not work (see the code
Hi Nicola,
You have provided the code and data as requested the data is in a very
unfriendly format.
If you would supply the data in an easily useable format so that the readers
here can work with it it would help.
Since it looks like you have a small data set the easiest thing is to use
row - c(a,b,c,d,e,f,g) #rows from larger data frame
row.1 - c(a,b,c,g) #rows of smaller data frame because d, e,
and f don't contain any of the species, but the zeros are important
x - data.frame(sp1=rnorm(4), sp2=rnorm(4), sp3=rnorm(4), sp4=rnorm(4))
rownames(x) - row.1
#I would like to
Hey everyone,
I hope this finds you in good cheer.
I just have a quick question: What is the function that outputs the p-value
for correlation?
cor(x,y) only provides the R value. I would like the p-value associated
with it.
Thank you all for your help!
[[alternative HTML version
On Wed, Apr 25, 2012 at 6:27 AM, Ramon Ovelar ramon.ove...@gmail.com wrote:
I don't think I have touched at anything at all. I'm very newbie to R and to
be honest I don't know what Ramdom.seed is. I will try to find out.
I have seen other messages about restoring random.seed, but in order to
Hi,
Look at the See also section of ?cor
Best,
Ista
On Wed, Apr 25, 2012 at 9:30 AM, Aaditya Nanduri
aaditya.nand...@gmail.com wrote:
Hey everyone,
I hope this finds you in good cheer.
I just have a quick question: What is the function that outputs the p-value
for correlation?
cor(x,y)
On 12-04-25 7:41 AM, Liviu Andronic wrote:
Dear all
When using Sweave, I'm always hitting the same bump: I want to group
repetitive calls in a function, but I want both the results and the
function calls in the printed output. Let me explain myself.
Consider the following computation in an
On Apr 25, 2012, at 8:27 AM, Ramon Ovelar wrote:
I don't think I have touched at anything at all. I'm very newbie to
R and
to be honest I don't know what Ramdom.seed is. I will try to find
out.
I have seen other messages about restoring random.seed, but in
order to
check that the
On 12-04-25 9:30 AM, Aaditya Nanduri wrote:
Hey everyone,
I hope this finds you in good cheer.
I just have a quick question: What is the function that outputs the p-value
for correlation?
cor(x,y) only provides the R value. I would like the p-value associated
with it.
cor(x,y) calculates
Well, it throws an error, because there is no such function in default R. A bit
of googling showed it might be the one in the caTools package.
execute this:
install.packages(caTools)
library(caTools)
before executing your code
Am 25.04.2012 um 12:39 schrieb Dwaipayan Dasgupta:
Hi,
Could
I think this should help:
require(pcaMethods)
data(metaboliteDataComplete)
mdc - scale(metaboliteDataComplete, center=TRUE, scale=FALSE)
## Now create 5% of outliers.
cond - runif(length(mdc))0.05;
mdcOut - mdc
mdcOut[cond] - 10
## Now we do a conventional PCA and
On Wed, Apr 25, 2012 at 3:41 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I would use the last method, or if the calls were truly repetitive (i.e.
always identical, not just the same pattern), use a named chunk.
Labeled chunks are indeed what I was looking for [1]. As far as I
understand,
Hi,
I am working with gam models in the mgcv library. My response variable (Y) is
binary (0/1), and my dataset contains repeated measures over 110 individuals
(same number of 0/1 within a given individual: e.g. 345-zero and 345-one for
individual A, 226-zero and 226-one for individual B, etc.).
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in
column 'a' and 'b'. I found a way but I am sure this is not the best
solution. So any ideas on how to optimize this would be great!
m - factor(c(a1, a1, a2, b1, b2, b3, d1, d1), ordered
= TRUE)
df - data.frame( a=
Hi Brian,
On Wednesday 25 April 2012 13:15:03 Brian Flatley wrote:
I have a main directory - Spectra
In this folder I have two subfolders Normal and Case
The following should be enough:
library(readBrukerFlexData)
Spectra - mqReadBrukerFlex(Spectra/);
...
The following command will open
Hello,
I'm an absolute beginner with R. I'm hoping to do some time-series analysis
on my data. The data looks like
#time value
18 153
20 426
70 7
83 130
84 7
and so on where time could be in seconds or hours or days (not all at the
same time). How could I import such a file to R and do some
id age76 Wage76 Grade76 Black immigrt. ...
1 25 102456 12 1 0
2 27 15432 15 0 1
3 30 12340 16 1 1
Then I have lots of data variables 100 for 5000
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Hello,
The first is easy.
How can I cut these files and save them automatically (one file for ST001,
another for ST002, ...) according to these columns names?
Similar to the way they were read, using lapply on the results list.
But first make a file names vector.
(I've used the file
As to combining, use c().
as to tracking, keep track of the directory that goes with the file. There are
various ways to do this:
a) keep a vector of filenames, and every time you combine vectors of filenames,
do the same for the vectors of directory names. You will probably need to use
rep()
Alternatively, the OP might just use set.seed(1) to get a fresh seed
rather than playing with .Random.seed directly.
To the OP: if you're on Mac, follow these instructions and we'll see
if that fixes your problem:
**) open Terminal
**) type R -q --vanilla
**) At the prompt type the following
Hello Dr. Winsemius,
There was a non-numeric column. Thanks for helping me to see the obvious.
Paul
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I am subsetting a larger data frame that contains macroinverterate
taxa. I am subsetting them at different levels of taxonomic
resolution. Some of the sites do not have say Tipulidae present, so the
rows are removed completely for this site. I would like to fill in the
sites that were
You really don't want to use ts() -- if you want to use the tools in
fArma use a timeSeries (provided by the package of the same name)
Michael
On Wed, Apr 25, 2012 at 9:54 AM, Barun Saha barun.sah...@gmail.com wrote:
Hello,
I'm an absolute beginner with R. I'm hoping to do some time-series
The clarification helps; the original description was rather terse.
What about:
row - c(a,b,c,d,e,f,g) #rows from larger data frame
x - data.frame(sp1=rnorm(4), sp2=rnorm(4), sp3=rnorm(4), sp4=rnorm(4))
rownames(x) - row.1
merge(x, matrix(row, ncol=1), by.x=0, by.y=1, all=TRUE)
Hello everybody out there using the RODBC package,
On my linux (unixODBC) and windows machines, I can successfully use the RODBC
package to connect to a PostgreSQL databse.
On my Mac Book running Mac OS X 10.6 (Intel 64bit architecture), I get the
error code 202 and message ? when I try to
You can do this in bash but why not just do it in R directly? You probably need
list.files(pattern = .out)
to get started. Then just wrap your script in a function and pass it
to (s|l)apply something like:
sapply(list.files(pattern = *.out), function(x) wilcox.test ( ... ) )
Michael
On Wed,
Hello,
I am running the pgls () function of the caper programme, the output has
some estimates, some of them are negative and others are positive ( values
can be less, equal, or more than 1 ). If I have an estimate of -0.12 for a
coefficient (body size) on head size. How do I interpreted it?
Thanks for replying.
My problem is that i have say 50 input files, that i wanted to run a
particular command on, get 50 output files, and then when i close R, have
them in my directory?
so for example if i say:
R
library(MASS)
list.files(pattern = .out)
sapply(list.files(pattern = *.out),
Check out the vignette for the optparse library:
http://cran.r-project.org/web/packages/optparse/vignettes/optparse.pdf
Super helpful library if you plan on making any semi-interesting
command line scripts w/ R.
-steve
On Wed, Apr 25, 2012 at 6:47 AM, aoife doherty
aoife.m.dohe...@gmail.com
On 25/04/2012 10:20 AM, Liviu Andronic wrote:
On Wed, Apr 25, 2012 at 3:41 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I would use the last method, or if the calls were truly repetitive (i.e.
always identical, not just the same pattern), use a named chunk.
Labeled chunks are indeed
On Apr 24, 2012, at 19:15 , Rui Barradas wrote:
Has anyone realized that both 'non' and 'un' end with the same letter? The
only one we really need to check?
(tmp - c('mutation','nonmutated','unmutated','verymutated','other'))
i1 - grepl(muta, tmp)
i2 - grepl(nmuta, tmp)
tmp[i1
Thank you so much for replying. I tried what you said but it still throws the
same error i.e could not find function sample.split
Might be because of the version of R I am running (R version 2.12.2).i do not
have admin rights to upgrade to the newest version.
Is there anything else I can try? Im
On Wed, Apr 25, 2012 at 6:14 AM, Patrick Hausmann
patrick.hausm...@covimo.de wrote:
Hello,
I am trying to get a new vector 'x1' based on the not NA-values in column
'a' and 'b'. I found a way but I am sure this is not the best solution. So
any ideas on how to optimize this would be great!
If
www.rmetrics.org/ebooks
There's a free book on time series classes in R here: I haven't used it myself,
but it is by the fArma (RMetrics) folks so I presume it covers their own time
series class.
Michael
On Apr 25, 2012, at 11:11 AM, Barun Saha barun.sah...@gmail.com wrote:
Thanks,
What I usually do when I have to write a report with some functions I use
multiple times is that I put them in a separate file (call it setup.Rnw or
so).
The first chunk there loads the libraries, sets initial variable values etc:
echo=FALSE, results=hide=
library( xtable )
d - iris
ind - 1
@
Don't know whats wrong there (except if you're using the eclipse R plugin on a
mac like me and the window for choosing the download site doesn't pop up.. did
it?^^)
Anyway, you could just split all of your data into 2 datasets, one that has all
the data labeled 0, the other for all labeled 1,
x=rmvnorm(2000, rep(0, 6), diag(c(5, rep(1,5
x=scale(x, center=T, scale=F)
pc - princomp(x)
biplot(pc)
There are a bunch of red arrows plotted, what do they mean? I knew that the
first arrow labelled with Var1 should be pointing the most varying
direction of the data-set (if
On Apr 25, 2012, at 10:03 AM, julia.jacob...@arcor.de wrote:
Hello everybody out there using the RODBC package,
On my linux (unixODBC) and windows machines, I can successfully use the RODBC
package to connect to a PostgreSQL databse.
On my Mac Book running Mac OS X 10.6 (Intel 64bit
On 25.04.2012 17:12, Steve Lianoglou wrote:
Check out the vignette for the optparse library:
http://cran.r-project.org/web/packages/optparse/vignettes/optparse.pdf
Super helpful library if you plan on making any semi-interesting
command line scripts w/ R.
-steve
On Wed, Apr 25, 2012 at
Hi, I am a PhD student. Basic knowing R. I have 2 datw files 1st 5min
intervals the 2nd 1min for a month. My taske is to have 15min average for
all.
This how data look;
Date Pm FF LL KK
HH NNWwDD
01/01/2012 00:00:00
Hello R-help list,
I would really appreciate help with my factoring problem.
My generated data is this:
df - expand.grid(T=seq(10,80, by=5), conc=rep(c(1, 3, 7), 2))
df$curve - as.factor(rep(1:6, each=length(seq(10,80, by=5
df$counts - 3*df$T/df$conc + rnorm(df$T,0,2)
plot(counts~T, df)
Hi everybody. I'm making a confidence interval plot using the function
plotCI. I would like to decrease the space between the lines. How can I do
that? Thanks alot
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Thanks, Michael! Could you plz point to some easy tutorials regarding this?
On Wed, Apr 25, 2012 at 8:14 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
You really don't want to use ts() -- if you want to use the tools in
fArma use a timeSeries (provided by the package of the same
Hi,
I saw you discussed about the meaning of the R squared in a nls regression. Do
you have a source or a quotation please?
kind regards,
Pierre Grison
Tel: 06 01 79 74 22
Mail: pgri...@hotmail.fr
[[alternative HTML version deleted]]
__
Hi,
On Wed, Apr 25, 2012 at 11:11 AM, aoife doherty
aoife.m.dohe...@gmail.com wrote:
Thanks for replying.
My problem is that i have say 50 input files, that i wanted to run a
particular command on, get 50 output files, and then when i close R, have
them in my directory?
so for example if i
Thanks Jeff. I had tried the 'list' approach as well but got stuck with the
below error:
Error in `$-.data.frame`(`*tmp*`, date, value = 20100701) :
replacement has 1 rows, data has 0
Couldnt find a work around to this, hence resorted to the multiple
dataframes approach. Any insights into
This question has been asked many times before. Please search the archives.
The short answer is: R-squared is more or less meaningless in
nonlinear regression. The archives provide elaboration and caveats to
this claim.
-- Bert
On Wed, Apr 25, 2012 at 8:12 AM, Pierre Grison pgri...@hotmail.fr
try this: (uses 'ave')
df - expand.grid(T=seq(10,80, by=5), conc=rep(c(1, 3, 7), 2))
df$curve - as.factor(rep(1:6, each=length(seq(10,80, by=5
df$counts - 3*df$T/df$conc + rnorm(df$T,0,2)
plot(counts~T, df)
df$zero - ave(df$counts, df$curve, FUN = function(x) x - min(x))
df
T
On Apr 25, 2012, at 10:57 AM, Carly Huitema wrote:
Hello R-help list,
I would really appreciate help with my factoring problem.
My generated data is this:
df - expand.grid(T=seq(10,80, by=5), conc=rep(c(1, 3, 7), 2))
df$curve - as.factor(rep(1:6, each=length(seq(10,80, by=5
df$counts
Thank you all very much, that did the trick.
Stephen
On Wed 25 Apr 2012 09:59:38 AM CDT, Sarah Goslee wrote:
The clarification helps; the original description was rather terse.
What about:
row- c(a,b,c,d,e,f,g) #rows from larger data frame
x- data.frame(sp1=rnorm(4), sp2=rnorm(4),
http://www.cs.purdue.edu/homes/jv/pubs/ecoop12.pdf
A new paper out on R the language -- I'm not all the way through it but it's
been an interesting read so far. Thought it might be of interest to the list.
Michael Weylandt
[[alternative HTML version deleted]]
Dear Berend,
Yes, the wnv.sim function should have included wnv.model instead of
wnv.incubation. Sorry for the typo.
Although I had inspected the expand.grid() object, I had not connected
the error with a naming problem. Thanks so much for the help! The
function works perfectly.
The arrows are not pointing in the most-varying direction of the data. The
principal components are pointing in the most-varying direction of the
data. But you are not plotting the data on the original scale, you are
plotting the data on the rotated scale, and thus the horizontal axis is the
Hmmm
an 'objective' assessment? Maybe. But it looks to me that some
commercial enterprise paid for this study as a means to argue against the
use of R in favor of a commercial package
On Wed, Apr 25, 2012 at 1:48 PM, R. Michael Weylandt
michael.weyla...@gmail.com michael.weyla...@gmail.com
I have 3 files A ,B ,C as binary files. C represents the values of tepm
measured every 3 hours for one month so it has 674200 columns and 248
rows.values of A represent the correspond lines(these values could be within
1to360) and , while values of B represent the correspond pixel(1to720) for
each
I have not read it yet, but the acknowledgements at the end of the paper note
that:
1. It was supported by an NSF grant.
2. At least two members of R Core are recognized amongst the list of names.
Regards,
Marc Schwartz
On Apr 25, 2012, at 1:07 PM, Thomas Adams wrote:
Hmmm∑ an 'objective'
Dear List,
I was wondering if there is a simple way to solve (equate) two functions in
R. For example:
(1) 5x + 3y = 30
(2) 12x - 2y = 26
I would like R to finde x = 3 and y = 5
Is there an implemented function in R or would I have to write an own
function?
Thank you very much for your help.
Hi. I would use the function aggregate, but first you will have to tag each
row with a special code so R can recognize the group of data and apply the
function you desire. For example, with your data I would do this:
Date Pm FF LL
KK
Dear List,
I know this is not the first post on this topic, but I need basic help I
guess. Assuming the simple case of two lines with one intercept, how can I
make R calculate this intercept, NOT using locator().
par (xaxs=i, yaxs=i)
plot( 1, bty=n ,xlim=c(0,300) , ylim=c(0,300) , xlab=X, ylab=Y)
Hello,
Try
(x - matrix(c(5, 12, 3, -2), ncol=2))
(y - c(30, 26))
solve(x, y)
solve.qr(qr(x), y)
(Use the second.)
Also, see section 5.7.5 of the R-intro.pdf that comes with your (any)
installation of R.
Hope this helps,
Rui Barradas
--
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Hi pannigh,
The following might get you started:
x0 - uniroot(function(x) 100-0.5*x - (150- x), c(0, 150))$root
x0
[1] 100
100- 0.5*x0
[1] 50
HTH,
Jorge.-
On Wed, Apr 25, 2012 at 1:01 PM, pannigh wrote:
Dear List,
I know this is not the first post on this topic, but I need basic help I
On Apr 25, 2012, at 20:19 , Marc Schwartz wrote:
I have not read it yet, but the acknowledgements at the end of the paper note
that:
1. It was supported by an NSF grant.
2. At least two members of R Core are recognized amongst the list of names.
Also, most of the overall content is
On 25-04-2012, at 18:52, pannigh wrote:
Dear List,
I was wondering if there is a simple way to solve (equate) two functions in
R. For example:
(1) 5x + 3y = 30
(2) 12x - 2y = 26
I would like R to finde x = 3 and y = 5
Is there an implemented function in R or would I have to write an
Thanks Michael:
Interesting!
Is it legitimate to comment on this in this list? It would only be my
opinions, not real R-Help stuff. Where would be a better place to post
such UN-expert opinion?
-- Bert
On Wed, Apr 25, 2012 at 10:48 AM, R. Michael Weylandt
michael.weyla...@gmail.com
On 12-04-25 4:04 PM, Trevor Miles wrote:
Thanks Duncan.
The only .site files I have are Reviron.site and Rprofile.site, which
are both in C:\Program Files\R\R-2.14.1\etc.
My advice was about 2.15.0, but I don't remember any of this changing
recently.
Copying these files to C:\Program
rafitoariaz rafitoariaz at hotmail.com writes:
Hi everybody. I'm making a confidence interval plot using the function
plotCI. I would like to decrease the space between the lines. How can I do
that? Thanks alot
There may be a better answer than this, but here goes:
The lines are plotted
Hi,
I came across this paper which is essentially a tutorial on how to generate
designs in R using the AlgDesign package. Hope it's helpful.
I'm not trying to generate designs in R using priors, but haven't found a
way to do it yet. Anyone out there have any ideas?
Cheers,
John Paul
--
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Hi,
On Wed, Apr 25, 2012 at 4:06 PM, Bert Gunter gunter.ber...@gene.com wrote:
Thanks Michael:
Interesting!
Is it legitimate to comment on this in this list? It would only be my
opinions, not real R-Help stuff.
FWIW, I'd be interested in hearing opinions about it from R-folk ...
Where
You can also use range( MC.pH, MV.pH, na.rm=TRUE).
On Tue, Apr 24, 2012 at 1:29 PM, David Doyle kydaviddo...@gmail.com wrote:
Hi Greg,
Sloved my own problem.
I had some missing data NA in the datasets. So I manually entered the
ylim=range(4,6)
and it worked!!!
Thanks!!
David
On Tue,
Doesn't the p-value from using offset work for you? if you really
need a p-value. The confint method is a quick and easy way to see if
it is significantly different from 1 (see Rolf's response), but does
not provide an exact p-value. I guess you could do confidence
intervals at different
I believe that fortune(312) applies here. As my current version of
fortunes does not show this I am guessing that it is in the
development version and so here is what fortune(312) will eventually
print (unless something changes or I got something wrong):
The problem here is that the $ notation
sorry for cross-posting
Dear all,
I have tow (several) bivariate distributions with a known mean and
variance-covariance structure (hence a known density function) that I would
like to compare in order to get an intersect that tells me something about how
different these distributions are (as
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