D == Dani danicy...@gmail.com
on Tue, 24 Feb 2009 14:09:36 -0800 writes:
D Hi list,
D I don't know if somebody has spent a lot of time debugging strange
D problems with if else positioning - the parser seems to recognize only
D the syntax bellow - this is the only way of
On Tue, 24 Feb 2009, Axel Strauß wrote:
OK, the one thing I figured out:
Is should be like:
biplot(test.pca, cex=c(2,1), col=c(red,green)...
to change size, colours etc separately. But I still don't know how change
lables of observations to symbols properly.
That's not part of the design of
I am trying to use package ROCR to analyze classification accuracy,
unfortunately there are some problems right at the beginning.
Question 1)
When I try to run demo I am getting the following error message
library(ROCR)
demo(ROCR)
if(dev.cur() = 1) [TRUNCATED]
Error in
Hi there,
I'm very glad to use the R-help mailing list for R-related question but more
and more often I face general statistical problems. Does anyone know by chance
a community (mailinglist, forum, ...) where I can ask these kind of questions?
I'm glad for any link or hint :-)
Antje
Martin Maechler wrote:
I think this is FAQ (or should become one):
?if [the help page you really should read before spending too
much time or even post to R-help]
?if
won't parse completely, you need
?'if'
;)
vQ
__
David, Wacek: Just so everyone knows, I just looked and this is
explained quite clearly in the R Language Reference manual, very
similarly to what Wacek did below.
On Wed, Feb 25, 2009 at 3:42 AM, Wacek Kusnierczyk wrote:
David Winsemius wrote:
On Feb 24, 2009, at 11:36 PM, Fuchs Ira
Hi
r-help-boun...@r-project.org napsal dne 25.02.2009 06:18:04:
Hi Ira:
For your first question, under the hood of R, names- is actually a
function so , when you do that, you need to say names(a)[2] rather
than names(a[2]). why this is is tricky and I wouldn't do it justice if
i tried
Prof Brian Ripley schrieb:
On Tue, 24 Feb 2009, Axel Strauß wrote:
OK, the one thing I figured out:
Is should be like:
biplot(test.pca, cex=c(2,1), col=c(red,green)...
to change size, colours etc separately. But I still don't know how
change lables of observations to symbols properly.
Hi
I know this only affects a small number of subscribers, so I apologize
to the Non Stellenbosch University subscribers for the noise.
Two weeks ago, four R users met and discussed the possibility of forming
an interest group of R users at SUN. The interest group (r...@sun) has the
aim of:
•
Hello and thanks for your reply, but as you said, this is not really what I'm
trying to do.
My purpose is not one of variable selection within a model with multiple
predictors, but simply fitting a large number of models with only one predictor.
I was just hoping there would be a solution as
markle...@verizon.net wrote:
David, Wacek: Just so everyone knows, I just looked and this is
explained quite clearly in the R Language Reference manual, very
similarly to what Wacek did below.
thanks, that's good, because i made it up following the page quoted by
david, and if i'm flamed for
Hi
r-help-boun...@r-project.org napsal dne 24.02.2009 12:41:50:
Hi Peter,
You are totally right and it was a miscalculating and misunderstanding
from
me.
Regarding the R-squared calculation of non linear model (question 2), is
there any way to do that?
I am not an expert statistician,
Hi
If you do not insist on matrix and use data frame instead
lapply(iris4,function(x) lm(iris$Sepal.Length~x))
can do it
Regards
Petr
r-help-boun...@r-project.org napsal dne 25.02.2009 09:56:25:
Hello and thanks for your reply, but as you said, this is not really
what I'm
trying to do.
WK == Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no
on Wed, 25 Feb 2009 09:46:19 +0100 writes:
WK Martin Maechler wrote:
I think this is FAQ (or should become one):
?if [the help page you really should read before spending too
much time or even post
New versions of leaps and biglm are percolating through CRAN.
The new version of biglm fixes a bug in sandwich standard errors with weights,
and adds predict(), deviance() and AIC() methods [based on code from Christophe
Dutang].
The new version of leaps adds a regsubsets() method for biglm
a quick follow-up:
e = new.env()
e$a = 1
names(e)
# NULL
names(e) = 'a'
# error in names(e) = foo : names() applied to a non-vector
this is surprising. names(e) 'works', there is no complaint, but when
names- is used, the error is about the use of names, not names-.
Hi
r-help-boun...@r-project.org napsal dne 22.02.2009 12:11:46:
Hello all,
I'm trying to calculate the standar desviation with sd(x,na.rm=TRUE) and
I
don't know why I have this error Error in var(x, na.rm = na.rm) : no
complete
element pairs when I try to calculate it, I have been
On Wed, 25 Feb 2009 09:57:36 +0100
Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
markle...@verizon.net wrote:
David, Wacek: Just so everyone knows, I just looked and this is
explained quite clearly in the R Language Reference manual, very
similarly to what Wacek did
Berwin A Turlach wrote:
On Wed, 25 Feb 2009 09:57:36 +0100
Wacek Kusnierczyk waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
markle...@verizon.net wrote:
David, Wacek: Just so everyone knows, I just looked and this is
explained quite clearly in the R Language Reference manual, very
Hi Wacek: Somewhere I remember reading that environments have
functionality like lists EXCEPT for the names part. IIRC, I think that I
read this in the R Language Reference manual also.
On Wed, Feb 25, 2009 at 4:32 AM, Wacek Kusnierczyk wrote:
a quick follow-up:
e = new.env()
of course ! that was so obvious I didn't see it...
thanks very much and sorry for the bother
David Gouache
ARVALIS - Institut du végétal
Station de La Minière
78280 Guyancourt
Tel: 01.30.12.96.22 / Port: 06.86.08.94.32
-Message d'origine-
De : Petr PIKAL [mailto:petr.pi...@precheza.cz]
Thanks Berwin. You're correct in that I meant the R Language
Definition. Well, it may be a draft but I read it for the first time a
few months ago and
it was very enlightening so, whether it's a draft or not, I highly
recommend it. ( but not for total beginners. The R-intro is better for
a
On Wed, 25 Feb 2009, Evelina Naryvska wrote:
Colleagues,
please help me with the simple question.
How can I find R2 and p while doing best subsets regression? Also how
can I see B and p for coefficients?
You can't see coefficients or their p-values, because these are not computed.
The subset
When discussions do burst out on the allstat list, people are usually
pointed to one of the following alternatives:
http://groups.google.com/group/MedStats
http://datashaping.ning.com/forum
HTH
Heather
Peters Gj (PSYCHOLOGY) wrote:
Hey Antje list,
Antje wrote:
I'm very glad to use the
Dear friends,
I have to use a very large matrix. Something of the sort of
matrix(8,8,n) where n is something numeric of the sort 0.xx
I have not found a way of doing it. I keep getting the error
Error in matrix(nrow = 8, ncol = 8, 0.2) : too many elements specified
Dieter Menne wrote:
And, since my son asked me and I am basketball ignorant: Why are
basketball scores mostly much too close to equality? The arguments
(loose power when leading)
Characteristic of the game. Possession of the ball changes rapidly and
the probability of scoring is much higher
I have to use a very large matrix. Something of the sort of
matrix(8,8,n) where n is something numeric of the sort 0.xx
I have not found a way of doing it. I keep getting the error
Error in matrix(nrow = 8, ncol = 8, 0.2) : too many elements specified
Any
Philipp Pagel wrote:
I have to use a very large matrix. Something of the sort of
matrix(8,8,n) where n is something numeric of the sort 0.xx
I have not found a way of doing it. I keep getting the error
Error in matrix(nrow = 8, ncol = 8, 0.2) : too many elements
On Wed, Feb 25, 2009 at 06:37:53AM -0500, Duncan Murdoch wrote:
Philipp Pagel wrote:
A 8x8 matrix has 6.4 billion cells. If you assume 4 byte
(32bit) for a double precision floating point number that's an
impressive 25.6 Gb. Certainly does not fit into RAM on my machine.
Doubles
Have the counter function in R ?
if we use the software SAS
/*** SAS Code **/
data tmp(drop= i);
retain seed x 0;
do i = 1 to 5;
call ranuni(seed,x);
output;
end;
run;
data new;
counter=_n_; * this keyword _n_ ;
set tmp;
run;
/*
_n_ (Automatic
temp=data.frame(a=c(4,3,2,6),b=c(7,4,2,4))
temp
a b
1 4 7
2 3 4
3 2 2
4 6 4
temp$counter=1:nrow(temp)
temp
a b counter
1 4 7 1
2 3 4 2
3 2 2 3
4 6 4 4
Shubha Karanth | Amba Research
Ph +91 80 3980 8031 | Mob +91 94 4886 4510
Bangalore * Colombo * London * New York
I think you can use seq function:
seq(5)
On Wed, Feb 25, 2009 at 9:25 AM, Nash morri...@ibms.sinica.edu.tw wrote:
Have the counter function in R ?
if we use the software SAS
/*** SAS Code **/
data tmp(drop= i);
retain seed x 0;
do i = 1 to 5;
call
Dear R users:
Analysis of the impact of a time-dependent covariate (GVHD or use of
steroid after bone marrow transplantation) on two competing endpoints (invasive
fungal infection and death) is frequently encountered in the setting of BMT
data. Coxph package can be used as the following:
Prof Brian Ripley wrote:
On Mon, 16 Jun 2008, Wacek Kusnierczyk wrote:
Paul Adams wrote:
Hello everyone,
I have the following code which keeps giving me an error.
The code is:
dat-read.table(file=C:\\Documents and Settings\\Owner\\My
Wacek Kusnierczyk wrote:
as above, this works as well:
df[, vars] = list(NULL)
and this, simplest of them all, works too:
df[vars] = list(NULL)
That's actually a curious anomaly/design-flaw/whatever... The usual
rule is that you can treat data frames as lists, but
aq -
You might also try...
http://groups.google.com/group/sci.stat.consult
http://groups.google.com/group/sci.stat.edu
http://groups.google.com/group/sci.stat.math
Although I can't swear these don't overlap with some already mentioned.
HTH
Keith J
Heather Turner heather.tur...@warwick.ac.uk wrote in
When I execute that code, I get labels both on the branching points
and at the leaves of the tree. So I guess my reply is cannot
reproduce or do not understand. They are however not properly
positioned and the edges and bottoms of some of the labels are cut
off, but that did not sound
Alex Roy wrote:
Dear Frank,
Thanks for your comments. But in my situation, I do
not have any future data and I want to calculate Mean Square Error for
prediction on future data. So, is it not it a good idea to go for LOO?
thanks
Alex
With resampling you should be able
Monica,
I have a few thoughts.
- (I believe) it is usually better to put confidence in these metrics
instead of relying on p-values. The intervals will allow you to make
inferential statements and give you a way of characterizing the
uncertainty in the estimates. You've seen how to do this with
The _n_ construct in SAS is most analogous to that of row names in R,
accessible (and modifiable) via the row.names() function:
DF - structure(list(Month = structure(c(2L, 2L, 2L, 2L, 1L, 1L, 1L,
1L, 3L, 3L, 3L, 3L, 3L), .Label = c(Aug, July, Sept), class =
factor),
Week = 27:39,
On Wed, 25 Feb 2009, David Winsemius wrote:
When I execute that code, I get labels both on the branching points and at
the leaves of the tree. So I guess my reply is cannot reproduce or do not
understand. They are however not properly positioned and the edges and
bottoms of some of the
Hello,
This may sound crazy, but I have a large number of Multiplan data files I'm in
the process of recuperating, and I'm hoping to avoid having to open them one by
one to convert them into a modern, directly usable format. So I was wondering
if someone somewhere had encountered this and
And for completeness here's a function that returns the next integer
on each call.
n - (function(){
i - 0
function() {
i - i + 1
i
}
})()
n()
[1] 1
n()
[1] 2
n()
[1] 3
n()
[1] 4
n()
[1] 5
n()
[1] 6
;)
Hadley
On Wed, Feb 25, 2009 at 8:27 AM, David Winsemius
We should make this an FAQ (or find someone who knows how to correct the bug
in
XML).
We've been working on that.
It's hard to say what the problem is without the output of
sessionInfo() and a reproducible example.
Fredrik - if you can send me this off-list, I'll take a look (but it
may
ggplot2
ggplot2 is a plotting system for R, based on the grammar of graphics,
which tries to take the good parts of base and lattice graphics and
avoid bad parts. It takes care of many of the fiddly details
that make plotting a hassle
Max,
thanks for the reply. Yes, the models are done outside R (i will see what i can
do to run some of them inside R in the future ) and the sampling is
extremely skewed. But we use as truth or reference results from a field
exercise where people actually went and gave detailed
On Wed, Feb 25, 2009 at 8:41 AM, Wacek Kusnierczyk
waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
hadley wickham wrote:
And for completeness here's a function that returns the next integer
on each call.
n - (function(){
i - 0
function() {
i - i + 1
i
}
})()
actually, you
Dear R-users,
One can use the rcorr.cens function in Design to compute the C index when only
the stop time is indicated (I think implicitely start=0 in that case). When the
start and stop times are used in a Surv object, e.g.
library(Design)
S=with(heart, Surv(start,stop,event))
the object
On Wed, Feb 25, 2009 at 3:30 PM, hadley wickham h.wick...@gmail.com wrote:
And for completeness here's a function that returns the next integer
on each call.
n - (function(){
i - 0
function() {
i - i + 1
i
}
})()
n()
[1] 1
n()
[1] 2
n()
[1] 3
n()
[1] 4
n()
[1] 5
n()
Have any way to write a funtion into a list ?
--
Nash - morri...@ibms.sinica.edu.tw
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
On Wed, Feb 25, 2009 at 11:11:51PM +0800, Nash wrote:
Have any way to write a funtion into a list ?
You can do that the same way you would use with any other object:
foo - function(x){x^2}
foo(12)
[1] 144
a - list(foo, 12, 'as')
a
[[1]]
function(x){x^2}
[[2]]
[1] 12
[[3]]
[1] as
cu
Dear R-helpers:
I am new to R and wonder how to make a warning message colorful (if
possible, having sound is also welcome). I did some research and failed
to see options to allow this functionality. Is this a techical limitation so
far, or I miss some information.
Many thanks in advance.
-sean
You may have to change/scale the sizes of the font by using cex and
then to keep all labels within the plotting window, use xpd=TRUE.
Like in
text(fit, use.n=TRUE, cex=0.8, xpd=TRUE)
Philip
--
A Smile costs Nothing But Rewards Everything
Nash wrote:
Have any way to write a funtion into a list ?
Sure:
A - list(mean, var)
A[[1]](1:2) # 1.5
A[[2]](1:2) # 0.5
Uwe Ligges
--
Nash - morri...@ibms.sinica.edu.tw
__
R-help@r-project.org mailing list
On Wed, 25 Feb 2009, Gustaf Rydevik wrote:
On Wed, Feb 25, 2009 at 3:30 PM, hadley wickham h.wick...@gmail.com wrote:
And for completeness here's a function that returns the next integer
on each call.
n - (function(){
i - 0
function() {
i - i + 1
i
}
})()
n()
[1] 1
n()
[1] 2
How do I do a data envelopment analysis in R...provide me with the step by
step procedure for that..thanks in advance...
Arup
--
View this message in context:
http://www.nabble.com/Data-Envelopment-Analysis-in-R-tp22199360p22199360.html
Sent from the R help mailing list archive at Nabble.com.
looks like you've run out of memory mate, because that sure is a big
matrix, you'd probably need 64 bit OS/CPU/R and loads of RAM.
see thread:
http://www.nabble.com/Error-in-matrix:--too-many-elements-specified-td20457910.html
I know there are some packages on cran which help with large
On Wed, Feb 25, 2009 at 9:25 AM, Fox, Gordon g...@cas.usf.edu wrote:
The tricky part isn't finding the common factors -- we knew how to do
that, though not in so concise a fashion as some of these suggestions.
It was finding all their products without what I (as a recovered Fortran
programmer)
Hi,
I need your help. I have downloaded a precompiled JRI as part of rJava. I
have included rJava as part of my R package libraries.
Now I need to be able to work with some R functions from my Java apps. I'm
using NetBeans on Windows.
I have followed some instructions from
Kindly let me know the process to carry out a Linear discriminant
analysis...thanks in advance
Arup
--
View this message in context:
http://www.nabble.com/Linear-Discriminant-Analysis-tp22199424p22199424.html
Sent from the R help mailing list archive at Nabble.com.
Dear useR's,
I have a problem to read data (daily precipitation).
The data are formated in months by columns wich leads to empty items in
months with less then 31 days.
What i did was reading the file and try to reshape the object
a- read.table(nds.txt, header=TRUE, sep=;, dec = .,
na.string=NA)
Hi,
if I got it right then the survival-time we expect for a subject is the
integral over the specific survival-function of the subject from 0 to t_max.
If I have a trained cox-model and want to make a prediction of the
survival-time for a new subject I could use
survfit(coxmodel,
According to the microsoft site http://support.microsoft.com/kb/323626;, SYLK
files are
ordinary text or csv files with a peculiar character in that the first two
characters of the file are the uppercase letters.
For example for a csv file, the first column may contain the
Hi David,
May be I was not clear, but I want to label the branches itself and not the
branching points or the leaves.
Regards
Utkarsh
From: Philip Twumasi-Ankrah [mailto:nana_kwadwo_der...@yahoo.com]
Sent: Wednesday, February 25, 2009 9:07 PM
To:
Dear Arup,
See the lda function in the MASS package. In general,
require(MASS)
Loading required package: MASS
?lda
HTH,
Jorge
On Wed, Feb 25, 2009 at 4:44 AM, Arup arup.pramani...@gmail.com wrote:
Kindly let me know the process to carry out a Linear discriminant
analysis...thanks in
Dear friends
I have clustered some objects using the hclust algorithm, with method ward. I
then cutree with 48 classes.
distPredTurn-as.dist(resultMatrix)
hctr-hclust(distPredTurn,ward)
cutree(hctr,k=NC)
I would like to estimate the similarity between each pair of the 48 clusters,
for
Maybe as a starter
RSiteSearch(linear discriminant analysis)
R has tools to help you help yourself with this types of questions.
-Christos
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Arup
Sent: Wednesday, February 25,
hadley wickham wrote:
On Wed, Feb 25, 2009 at 8:41 AM, Wacek Kusnierczyk
waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
hadley wickham wrote:
And for completeness here's a function that returns the next integer
on each call.
n - (function(){
i - 0
function() {
i - i + 1
on 02/25/2009 07:52 AM Frank E Harrell Jr wrote:
Dieter Menne wrote:
Frank E Harrell Jr f.harrell at vanderbilt.edu writes:
... Word and pdf
It depends on how you copy. By all means use Insert ... Picture ...
from file and directly insert pdf.
Please, tell me how you got this to work.
Did you set a system property for java.libary.path that points to the
native library as the error message instructs?
I'm not familiar with NetBeans, but in Eclipse you can set the JVM
properties in a dialog. Otherwise you can always pass it in via the
command line: -Djava.library.path=path to the
On Wed, Feb 25, 2009 at 4:43 PM, Charles C. Berry cbe...@tajo.ucsd.edu wrote:
On Wed, 25 Feb 2009, Gustaf Rydevik wrote:
On Wed, Feb 25, 2009 at 3:30 PM, hadley wickham h.wick...@gmail.com
wrote:
And for completeness here's a function that returns the next integer
on each call.
n -
Hi dear list,
If anybody could help me, it would be great!
I have two files:
File 1 is a list (one column and around 10 rows)
File 2 is a list with all the names from file one and a few more (one
column and more than 10 rows)
What I want is to add a column in file 2 that says which name
Hi Laura.
Let's assume file 1 and 2 are vectors loaded in R named: vec1 and vec2,
here is a short code (with dummy numbers) for a solution:
vec1 - c(1,2,34,4,3,6,76)
vec2 - c(1,2,34,76,24,62,1,4234,435,4333,4422,304,776)
which.vec2.where.in.vec1 - vec2 %in% vec1
Dear help, suppose I have this array and want to compute sd aross rows and
columns.
p - array(c(1:5, rep(NA, times = 3)), dim = c(5, 5, 3))
apply(p, 1:2, sd) fails because sd requires at least 2 numbers to compute sd
apply(p, 1:2, sd, na.rm = TRUE) fails for the same reason
I crafted my own
I am conducting an experiment where students are put into 5 total
groups (one is the control group). They are given a task and then I'm
measuring if there are differences (A 5 X 1 between-subject design
will be used for the experiment). I'm a little confused on the data
explanation (or should I
Hi Dar.
I am not sure I got your question -
Are you asking what analysis to perform ?
Or how to perform it ?
Could you please give more details ?
On Wed, Feb 25, 2009 at 5:52 PM, Dar darre...@aol.com wrote:
I am conducting an experiment where students are put into 5 total
groups (one is
hey Laura,
I hope this help
f1 = c(a,b,c)
f2 = c(b,a,c,d)
match(f2,f1)
f3 = match(f2,f1,0)
?match
cbind(f2,f3)
cbind(f2,f30)
f4 = ifelse(f30,yes,no)
cbind(f2,f4)
data.frame(f2,f4)
Patrizio
2009/2/25 Laura Rodriguez Murillo laura.lmuri...@gmail.com:
Hi dear list,
If anybody could help me, it
Dear Matt,
Here are two ways:
# Data
p - array(c(1:5, rep(NA, times = 3)), dim = c(5, 5, 3))
# First
res-apply(p,3,function(X)
c(scols=apply(X,2,sd,na.rm=TRUE),srows=apply(X,2,sd,na.rm=TRUE))
)
res
# Second
res2-apply(p,3,function(X)
Dear list,
I am trying to use gregexpr to see if entries in a dataframe have
either of two possible values for a string.
here's an example
text-c(fat, rat, cat, dog, log, fish)
If I just wanted to find if any one of the elements in text match the
pattern at I would do
gregexpr(\\at, text)
I am confused when trying the function survfit.
my question is: what does the survival curve given by plot.survfit mean?
is it the survival curve with different covariates at different points?
or just the baseline survival curve?
for example, I run the following code and get the survival curve
gregexpr(\\at|\\og, text)
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Corey Sparks
Sent: Wednesday, February 25, 2009 11:50 AM
To: R Help
Subject: [R] Using gregexpr with multiple search elements
Dear list,
I am
Sorry - I didn't express myself very clearly. Yes, we're looking for
common factors of A and B. One way to get there is by my initial
approach: find the prime factors of each, select those that are in
common, and then take pairwise products. My initial question was about
the last step only.
Hi Mark,
There is a typo in the first way. My apologies. It should be:
# First
res-apply(p,3,function(X)
c(scols=apply(X,2,sd,na.rm=TRUE),srows=apply(X,1,sd,na.rm=TRUE))
)
res
HTH,
Jorge
On Wed, Feb 25, 2009 at 11:42 AM, Jorge Ivan Velez jorgeivanve...@gmail.com
wrote:
Dear
Hi guys,
I'm evaluating R for basic data exploration. I produce a bar plot of the
data, with the x axis labels aligned vertically. However, the start of
labels longer than about 10 characters are cut off by the bottom of the
graphics window.
I'd appreciate your help in properly spacing the space
Eleni Rapsomaniki wrote:
Dear R-users,
One can use the rcorr.cens function in Design to compute the C index when only the stop time is indicated (I think implicitely start=0 in that case). When the start and stop times are used in a Surv object, e.g.
library(Design)
S=with(heart,
How do you want the labels to appear? Each branch will be the logical
conjunction of the criteria for *all* of the upstream splits. Perhaps
you can get direction by looking at the code of text.rpart:
getAnywhere(text.rpart)
Any split would need to add an Split-N yes or an Split-N No to
Well add1 (and others) does fit the regressions you asked about if you give it
the base model only including the intercept and the scope including the x
variables of interest. Unfortunately it only returns certain statistics on
those models, not the whole object, but if you were interested in
rcorr.cens is not meant for that.
Thank you for the clarification. On a second thought, I think (hope) a
time-dependent AUC index should be more appropriate in this case, such
as survivalROC.
Many many thanks for all your help!
Eleni Rapsomaniki
Research Associate
Tel: +44 (0) 1223
Following Dr Ripley's advice I looked at the text.rpart documentation
a bit more thoroughly and after seeing The edges connecting the nodes
are labeled by left and right splits. I find that the fancy=TRUE
invocation does cause a labeling of what you appear to be calling
branches.
See if
Hi,
Does anyone know how to fit a GAM where one or more smooth terms are
constrained to be monotonic, in the presence of by variables or
other terms? I looked at the example in ?pcls but so far have not been
able to adapt it to the case where there is more than one predictor.
For example,
R User R User wrote:
Hi guys,
I'm evaluating R for basic data exploration. I produce a bar plot of the
data, with the x axis labels aligned vertically. However, the start of
labels longer than about 10 characters are cut off by the bottom of the
graphics window.
I'd appreciate your help in
I’m just setting up the experiment and need help explaining what the
data analysis would be. Let me know of any questions….. what would be
compared and how it would be measured. Is it a multi-way or 1-way
anova?
Thanks!
A 5 X 1 between-subject design will be used for the experiment. Four
tool
R 2.5.1 compiled, passed the make check and has been successfully
running for a couple years on a Sun Fire V490 running Solaris 9. I
need a newer version of R, but can't get a newer version of R to pass
the make check. I've tried 2.8.1, 2.7.2, 2.6.2 and 2.6.0. (2.5.1 still
passes on this
I have read that when the gradient function is not supplied (is null) then
first order differencing is used to find the differential. I was trying to
track down this for my own information but I run into .Internal(optim.). I
was not sure where to look next to see the function that is
poLCA is designed to work this way. There's a complete user's guide and
manual on the project website at
http://userwww.service.emory.edu/~dlinzer/poLCA/
http://userwww.service.emory.edu/~dlinzer/poLCA/
Thanks,
Drew
==
Drew Linzer
Assistant Professor
Department of Political Science
Emory
Perhaps this may help you.
Regards
data(iris3)
ir - rbind(iris3[ , , 1], iris3[ , , 2], iris3[ , , 3])
ir.pca - princomp(ir)
biplot(ir.pca)
# Rehacer Biplot
# Calcular Factor para re-escalar scores y eigenvectores
lambda - ir.pca$sdev[1:2] * sqrt(ir.pca$n.obs)
scores - t(
have you thought about extracting the data and using this in ggplot?
On Wed, Feb 25, 2009 at 3:52 AM, Axel Strauß a.stra...@tu-bs.de wrote:
Prof Brian Ripley schrieb:
On Tue, 24 Feb 2009, Axel Strauß wrote:
OK, the one thing I figured out:
Is should be like:
biplot(test.pca, cex=c(2,1),
Try this:
Lines -
'Jahr;Tag;Jan;Febr;März;April;Mai;Juni;Juli;Aug;Sept;Okt;Nov;Dez
1978;1;NA;NA;NA;0.0;5.5;0.0;11.8;0.0;2.4;6.4;0.0;0.0
1978;2;NA;NA;NA;0.0;0.5;0.0;2.0;2.0;0.0;9.0;0.0;0.0
1978;3;NA;NA;NA;0.3;0.0;3.0;3.2;0.4;0.0;24.7;0.0;0.0
1978;4;NA;NA;NA;0.7;0.0;0.0;24.4;1.1;0.0;8.6;0.0;0.0
R 2.5.1 compiled, passed the make check and has been successfully running
for a couple years on a Sun Fire V490 running Solaris 9. I need a newer
version of R, but can't get a newer version of R to pass the make check.
I've tried 2.8.1, 2.7.2, 2.6.2 and 2.6.0. (2.5.1 still passes on this
server)
Hi all,This is really a stats question as much as an R question. I'm
trying to do a joint scaling test (JST - see below) on some very
oddly-distributed data and was wondering if anyone can suggest a good way of
dealing with model violations and/or using R to evaluate how sensitive the
model
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