The thing is that I've already been working with df1, and I was looking for
a function that could replace values knowing rows and columns. Does it
exist?
Thank you, u...@host.com
--
View this message in context:
On 30.11.2011 21:53, RogerP wrote:
I am trying to add the bigmemory packages but I get the following error
message:
In file included from bigmemory.cpp:14:0:
../inst/include/bigmemory/isna.hpp: In function 'bool neginf(double)':
../inst/include/bigmemory/isna.hpp:22:57: error: 'isinf' was not
I know this is not really an R question - it is a query about a recent book
on R (R In Action) by Robert Kabacoff, (Manning Publications 2011).
There are many references to interesting topics in R in the book, BUT, I do
not find a bibliography/list of references in the book!
Does anybody know if
On 01.12.2011 10:10, Ravi Kulkarni wrote:
I know this is not really an R question - it is a query about a recent book
on R (R In Action) by Robert Kabacoff, (Manning Publications 2011).
There are many references to interesting topics in R in the book, BUT, I do
not find a bibliography/list of
Hi
Hi everybody,
I am unable to resolve this error using the following for loop. Would
appreciate help. The same loop works with for(i in 1:92) strangely. I
checked the .raw input file and everything is kosher, even Line 547
mentioned in the error message.
I wonder if there is any
On 26.11.2011 20:36, John wrote:
On Sat, 26 Nov 2011 12:41:08 -0600
Paul Johnsonpauljoh...@gmail.com wrote:
Greetings, friends (and others :) )
We generated a bunch of results and saved them in an RData file. We
can open, use, all is well, except that the size of the saved file is
quite a
the problem might be a missing quote. Try
quote = ''
Or it might be a comment character, so try
comment.char = ''
This happens a lot if your data is not clean
Sent from my iPad
On Nov 30, 2011, at 19:48, nsaraf nsa...@gmail.com wrote:
)
__
Dear Mr Sarkar,
My apologies for not being articulate enough. Your solution worked
perfectly.
Many thanks,
Ashim
On Tue, Nov 22, 2011 at 9:12 PM, Deepayan Sarkar
deepayan.sar...@gmail.comwrote:
On Fri, Nov 18, 2011 at 11:22 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
Dear all,
I want
Le mercredi 30 novembre 2011 à 18:41 +0100, Göran Broström a écrit :
On Wed, Nov 16, 2011 at 3:06 PM, Milan Bouchet-Valat
nalimi...@club.fr wrote:
Hi list!
I'm getting an error message when trying to fit an accelerated
failure
time
Monica has sent me some data and code for taking a quick look. As it
turned out, there was a simple programming error on her side. The
segm_distance() function in package 'pracma' is working correctly. And
there is no minimization procedure in here, it simply solves some
equations from plane
Dear Kristi,
Also. can anyone recommend any resources to help SPSS users learn to things in
R?
You may want to have a look at the R2STATS package, a simple GUI for
linear models.
Best,
Yvonnick Noel
University of Brittany
Department of Psychology
Rennes, France
Hi all,
I have a vector, e.g., A = c(10, 20, 30, 40). This 4 numbers have 4! = 24
different combination. I want to generate a matrix with one combination in
one row, so the output would be
B =
10 20 30 40
10 40 20 30
...
Does anyone know how to do this easily in R? Thank you very much.
Hello everyone in the forum
For introducing myself I would say I have a basic knowledge of R.
Now I am intended to implement a flood algorithm using R. I have some MatLab
experience doing these, and as an example to explain more or less what I
want, I have a m code to calculate the slope from a
Hi everyone
I've got a problem regarding the arima() and the ar() function for
autoregressive series. I would simply like to combine them.
To better understand my question, I first show you how I'm using these two
functions individually (see file in the attachement).
1)
...is it possible to do that?
I apologize for something that must be a very trivial question for most of
you but, unfortunately, it is not for me.
A binary variable is measured, say, 50 times each year during 10 year. My
interest is focused on the percentage of 1s with respect to the total if
1. May I suggest that you try Mendeley for bibliographic management
2. There are also citations for specific R packages when you download each
version.
Let's use the ade4 package as an example:
http://cran.r-project.org/web/packages/ade4/index.html
if you selection citation info the corresponding
Hi,
I'm trying to write a small microsimulation in R: that is, I have a
dataframe with info on N individuals for the base-year and I have to
grow it dynamically for T periods:
df = data.frame(
id = 1:N,
x =
)
The most straightforward way to solve the problem that came to my mind
is to
Dear Gavin,
Thanks a lot for your reply. I am still not sure if your suggestion can help
me or not because I have got different types of errors while trying it. I
have tried my best to troubleshoot them and made some progress, but I have
reached a dead end (I don’t know how to go on). Below I am
Please send your questions to the R-help list, and not directly to me.
You provide your OS this time, but not any of the other information
requested in the posting guide, like your version of R.
What you did would be nice too. Used the menu option? Or used
install.packages() at the command line?
Hello
i need some precision about nipals in the chemometrics package in R .
When i use nipals in chemometrics i obtain T and P matrix.
I really don't understand what to do with these two matrix to obtain
the scores for every the component (like in spss fo example)
Comp1Comp2
Dear R-help members,
I'm processing a large amount of MODIS data where quality assessment
information is stored as an integer value for each pixel. I have to
converted this number to an 8 digit binary flag to get access to the
stored quality code (e.g. in2bin(165,8) = 1 0 1 0 0 1 0 1).
Dear Dustin,
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Dustin Fife
Sent: November-30-11 9:51 PM
To: r-help@r-project.org
Subject: [R] FIML with missing data in sem package
Is there a way to use full information
At one point we might have gotten something working (older version?) on
Solaris x86, but were never successful on Solaris sparc that I remember --
it isn't a platform we can test and support. We believe there are problems
with BOOST library compatibilities.
We'll try (again) to clear up the
Wendy wrote
Hi all,
I have a vector, e.g., A = c(10, 20, 30, 40). This 4 numbers have 4! = 24
different combination. I want to generate a matrix with one combination in
one row, so the output would be
B =
10 20 30 40
10 40 20 30
...
Does anyone know how to do this easily in
Dear All,
I have a binomial response with one continuous predictor (d) and one
factor (g) (8 levels dummy-coded).
glm(resp~d*g, data, family=binomial)
Y=b0+b1*X1+b2*X2 ... b7*X7
how can I get the inflection point per group, e.g., P(d)=.5
I would be grateful for any help.
Thanks in
jjcabrera20 wrote on 12/01/2011 04:02:47 AM:
Hello everyone in the forum
For introducing myself I would say I have a basic knowledge of R.
Now I am intended to implement a flood algorithm using R. I have some
MatLab
experience doing these, and as an example to explain more or less what I
Hi
now I'd like to do
for (colname in c('ColName1','ColName2','ColName3')) {
dat - measurements$colname
But that does not work, though I can write
measurements$C1 (same as measurements$C1)
(but different to measurements[C1]!)
Can you give me a hint?
greetings
Christof
Am
On Dec 1, 2011, at 6:34 AM, lincoln wrote:
...is it possible to do that?
I apologize for something that must be a very trivial question for
most of
you but, unfortunately, it is not for me.
A binary variable is measured, say, 50 times each year during 10
year. My
interest is focused on
Wendy wrote on 12/01/2011 04:27:09 AM:
Hi all,
I have a vector, e.g., A = c(10, 20, 30, 40). This 4 numbers have 4! =
24
different combination. I want to generate a matrix with one combination
in
one row, so the output would be
B =
10 20 30 40
10 40 20 30
...
Does anyone
If we assume that you are just convert 8 bits, here is one way with a
table lookup. If more than 8 bits, just partition the data and
repeat. This sets up a mapping table one time for the lookup. Does
1M in 0.3 seconds on my computer; is this fast enough?
# initialize a matrix with 8 bit
Thanks Peter. I was knowing that R had not found the header tk.h file.
But i did not where it was. I opened my Manage Packages Synaptic and
installed tk-dev and other similar packages, and voila! It work. I
coul install tkrplot and the other packages that i was needing.
THANKS, for your answer,
On 12/01/2011 07:18 AM, John Fox wrote:
To:r-help@r-project.org
Subject: [R] FIML with missing data in sem package
You should check out the OpenMx R package. Just search for OpenMx and
SEM. You can download from the web site. It does FIML and is an
excellent SEM package.
Rick B .
measurements[[colname]]
?'[['
On Thu, Dec 1, 2011 at 8:34 AM, Christof Kluß ckl...@email.uni-kiel.de wrote:
Hi
now I'd like to do
for (colname in c('ColName1','ColName2','ColName3')) {
dat - measurements$colname
But that does not work, though I can write
measurements$C1 (same as
i know this is not about R.
After applying quantile regression with t=0.5,0.6 on the data set WBC(
Wisconsin Breast Cancer)with 678 observations and 9 independent
variables(inp1,inp2,...inp9) and 1 dependent variable(op) i have got the
following results for beta values.
when t=0.5(median
In the ebook version there is a list of references (pp. 434-437).
Date: Thu, 1 Dec 2011 10:48:45 +0100
From: lig...@statistik.tu-dortmund.de
To: ravi.k...@gmail.com
CC: r-help@r-project.org
Subject: Re: [R] References for book R In Action by Kabacoff
On 01.12.2011 10:10, Ravi Kulkarni
My question is this: is there a way I can make one of the arguments of the
function be a string the user can enter, and then have that be the excel
filename? ie,
foo - function(x,y,NAME){
#make a matrix with x rows and y cols
M - matrix(nrow=x,ncol=y)
#write the matrix
write.table(M, file =
zz dd:
If you want a typical score plot, say PC1 vs PC2, then plot the first and
second columns of your score matrix (T) against each other and label the points
with the row names (if available) or create a text label from where ever you
have this information stored. To get an unlabeled score
Sure, change your example as follows and then you can pass the name properly:
foo - function(x,y,NAME = filename.csv){
#make a matrix with x rows and y cols
M - matrix(nrow=x,ncol=y)
#write the matrix
write.table(M, file = NAME,append=TRUE, sep = ,)
}
Bryan
Prof. Bryan Hanson
First, dataframes can be much slower than matrices, for example, if
you are changing/accessing values a lot. I would suggest that you use
a matrix since is seems that all your values are numeric. Allocate a
large empty matrix to start (hopefully as large as you need). If you
exceed this, you
On Dec 1, 2011, at 2:06 AM, yuying shi wrote:
Dear all,
I am doing an ordinal data simulation. I have a question
regarding the cut off values between categories. Suppose I have
three categories, if I do regression, there should be two cut off
values. I find some simulation code for the
Hi,
Alternatively you could have a look at the function terrain in the
raster package, it can calculate the slope for you using different
algorithms, not sure if the one below is included though.
For typical spatial requests like this, you could also use the
mailing-list r-sig-geo.
See this earlier post for SVG logos:
http://tolstoy.newcastle.edu.au/R/e12/devel/10/10/0112.html
Using Image Magick, do something like
convert logo.svg logo.eps
On Thu, 2011-12-01 at 10:56 +0700, Ben Madin wrote:
G'day all,
Sorry if this message has been posted before, but searching for
Good idea. I'll give it a try. Thanks!
On Thu, Dec 1, 2011 at 6:18 AM, John Fox j...@mcmaster.ca wrote:
Dear Dustin,
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Dustin Fife
Sent: November-30-11 9:51 PM
To:
Assuming a logistic model, for each group solve for d at Y=0, or solve for d at
p=0.5, where d is your continuous predictor, Y is the logit score, and p is the
probability of success in the binomial model. After that you can get the
standard error of the inflection point by Taylor series (aka
Hi everybody,
Thanks for checking my code, Hans, it help to see where my initial mistake was.
I am sorry i assumed that there was a minimization problem.
In short i had 2 wavy lines (left and right) that didn't intersect and lots
of straight parallel lines that intersect the first 2 lines. I
This really isn't the appropriate forum for most of your questions: I'd suggest
you work through the Wikipedia article on quantiles regression and direct
follow up to stats.stackexchange.com.
As to the R question: use the predict() function.
Michael
On Dec 1, 2011, at 8:12 AM, narendarreddy
I'd also suggest you read circle 2 of the R inferno (just google it)
which has some helpful tips on how to deal with these sorts of
problems.
Also, did you know that matrices can have column names and that
rbind() preserves them? E.g.,
m - matrix(1:6, 3); colnames(m) - letters[1:2]
print(m)
Dear R users/helpers,
I am wondering is there an existing function in which you can round
numbers to a set of values. I know you can use 5 * round(x/5) for
rounding to the nearest 5 or so, but what if the interval size is not
constant.
For example:
## Not run
test - rnorm(100)
round(test,
Hazard() is not implemented except for parametric survival models.
You are not calling nomogram() correctly; in rms the plotting step is
separated from the nomogram computations.
To plot cumulative event rates do something like:
mort10 - function(lp) 1 - surv(10,lp)
and tell nomogram about
?findInterval
.. would get you the endpoints and then you could determine which is nearer.
Of course in your example, everything would get rounded to 1.
-- Bert
On Thu, Dec 1, 2011 at 7:55 AM, Michael Kao mkao006rm...@gmail.com wrote:
Dear R users/helpers,
I am wondering is there an existing
Thank you very much, that does exactly what I want it to! :)
Aodhán
--
View this message in context:
http://r.789695.n4.nabble.com/Writing-a-function-want-a-string-argument-to-define-the-name-of-the-excel-sheet-to-be-called-tp4128384p4128495.html
Sent from the R help mailing list archive at
Hi List
Apologies if this isn't the correct place for this query (I've tried a search
of the mail archives but not had much joy).
I'm running R (2.14.0) on a Mac (OSX v 10.5.8, 2.66GHz, 4GB memory) and am
having a few performance issues with reading data in from a Postres database
(using
Hi, I want to do a 2 sample hotelling's test but i can't figure out how. When
i type T2.test it says there is no such test and when i tried library(rrcov)
it says there is no such program. Cheers.
--
View this message in context:
Thanks.
So, suppose for one specific year (first year over 10) the percentage of
successes deriving from 100 trials with 38 successes (and 62 failures), its
value would be 38/100=0.38.
I could calculate its confidence intervals this way:
success-38
total-100
On 12/01/2011 02:46 PM, jim holtman wrote:
If we assume that you are just convert 8 bits, here is one way with a
table lookup. If more than 8 bits, just partition the data and
repeat. This sets up a mapping table one time for the lookup. Does
1M in 0.3 seconds on my computer; is this fast
What is your goal? I have used and like mice pretty well, but using
mice + sem to try to address missingness seems like more work than
using FIML in OpenMx or lavaan to try to address it. Is there a
reason you want to use the sem package or a reason you do not want to
use the others?
I
Got it.
Thank you so much for the help!
Min Yi MD, PhD
Department of Surgical Oncology - Unit 1484
1400 Pressler Street, #FCT17.6061
University of Texas M.D. Anderson Cancer Center
P.O. Box 301402
Houston, TX 77230-1402
Phone: 713-563-1874
Fax: 713-792-4689
From: Frank Harrell [via R]
On 01/12/2011 10:55 AM, Michael Kao wrote:
Dear R users/helpers,
I am wondering is there an existing function in which you can round
numbers to a set of values. I know you can use 5 * round(x/5) for
rounding to the nearest 5 or so, but what if the interval size is not
constant.
For example:
##
The first version of the package was created by re-writing the main program in
the original Fortran as C, and calls other Fortran subroutines that were mostly
untouched, so dynamic memory allocation can be done. Later versions have most
of the Fortran code translated/re-written in C.
You might be interested in package bit.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Thanks for all the response,
I manage to write a small function to complete what I want based on the
wonderful helps.
iround - function(x, interval){
## Round numbers to desired interval
##
## Args:
## x:Numeric vector to be rounded
## interval: The interval
On Dec 1, 2011, at 8:24 AM, René Mayer wrote:
Dear All,
I have a binomial response with one continuous predictor (d) and one
factor (g) (8 levels dummy-coded).
glm(resp~d*g, data, family=binomial)
Y=b0+b1*X1+b2*X2 ... b7*X7
Dear Dr Mayer;
I think it might be a bit more complex than
Hi, I want to do a 2 sample hotelling's test but i can't
figure out how. When i type T2.test it says there is no such
test and when i tried library(rrcov) it says there is no such
program.
Have you installed rrcov using install.packages?
S
On Dec 1, 2011, at 10:49 AM, lincoln wrote:
Thanks.
So, suppose for one specific year (first year over 10) the
percentage of
successes deriving from 100 trials with 38 successes (and 62
failures), its
value would be 38/100=0.38.
I could calculate its confidence intervals this way:
Hello,
A bit of fairly simple code, yet I don't seem to be able to manipulate it
quite as much as I would like:
1) It would be nice if the objects appearing in the legend were aligned,
and by aligned I mean the boxes are centered over the lines. Do I need to
adjust the use of NA in the code
On 12/01/2011 05:25 PM, Dustin Fife wrote:
What is your goal? I have used and like mice pretty well, but using
mice + sem to try to address missingness seems like more work than
using FIML in OpenMx or lavaan to try to address it. Is there a
reason you want to use the sem package or a reason
On Thu, Dec 1, 2011 at 10:02 AM, Berry, David I. d...@noc.ac.uk wrote:
Hi List
Apologies if this isn't the correct place for this query (I've tried a search
of the mail archives but not had much joy).
I'm running R (2.14.0) on a Mac (OSX v 10.5.8, 2.66GHz, 4GB memory) and am
having a few
Dear List,
I was wondering if any of you worked on an R package which has many branches on
a repository i.e. SVN. Is it recommended to branch an R package source tree
based on a specific project? I know it depends on project but it would be great
to
hear opinions from R community.
Best,
Hi,
On Thu, Dec 1, 2011 at 10:35 AM, Majid golden_boy...@yahoo.com wrote:
Hi.
Can you please answer to my questions about R ?
1.how can I write command for vector ?
for exaple in this sample :
I have this :
a1 - c (1:10)
now how can I put in the vector ?
I'm afraid I don't understand
Hi all,
I'm trying to fit a Cox regression model with two factor variables but
have some problems with the interpretation of the results. Considering
the following model, where var1 and var2 can assume value 0 and 1:
coxph(Surv(time, cens) ~ factor(var1) * factor(var2), data=temp)
What is
The references are here: http://manning.com/kabacoff/excerpt_references.pdf
(they will be included on the next printing too, got omitted by mistake)
regards,
Pablo
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
I am new to R but am experienced SAS user and I was hoping to get some help on
counting the occurrences of a character within a string at a row level.
My dataframe, x, is structured as below:
Col1
abc/def
ghi/jkl/mno
I found this code on the board but it counts all occurrences of / in the
Dear R users,
I have been trying to obtain the MLE of the following model
state 0: y_t = 2 + 0.5 * y_{t-1} + e_t
state 1: y_t = 0.5 + 0.9 * y_{t-1} + e_t
where e_t ~ iidN(0,1)
transition probability between states is 0.2
I've generated some fake data and tried to estimate the parameters using
Thanks again for your help.
I've been able to add several packages, bigmemory seems to be the only one
to fail and it
fails on isinf.
Is there a way I can download the code and change it to include a ininf
function or definition?
I'm using the GNU compiler; should I have been using the SUN
On Dec 1, 2011, at 12:00 PM, Andreas Schlicker wrote:
Hi all,
I'm trying to fit a Cox regression model with two factor variables
but have some problems with the interpretation of the results.
Considering the following model, where var1 and var2 can assume
value 0 and 1:
Sorry if this is a duplicate: This is a re-post because the pdf's mentioned
below did not go through.
Hello,
I'm new'ish to R, and very new to glm. I've read a lot about my issue:
Warning message:
glm.fit: fitted probabilities numerically 0 or 1 occurred
...including:
Terry will correct me if I'm wrong, but I don't think the
answer to this question is specific to the coxph function.
For all the [well-written] formula-based modelling functions
(essentially, those that call model.frame and model.matrix to interpret
the formula) the option contrasts controls how
## It's not a data frame -- it's just a vector.
x
[1] abc/def ghi/jkl/mno
gsub([^/],,x)
[1] / //
nchar(gsub([^/],,x))
[1] 1 2
?gsub
?nchar
-- Bert
On Thu, Dec 1, 2011 at 8:32 AM, Douglas Esneault
douglas.esnea...@mecglobal.com wrote:
I am new to R but am experienced SAS user and I
Just a heads up -- I don't think your code will work with an actual
.xls(x) file, only .txt, .csv, etc (aka, plain text files). I may be
wrong about that, but if you actually need to work with Excel files
directly you will need an additional package.
Michael
On Thu, Dec 1, 2011 at 9:10 AM,
Hello
Hello
I have a data frame, x, holding 5 persons answering the question which
cars they have used:
# the data frame
x - as.data.frame(
matrix(
c('BMW', '', '',
'Mercedes', 'VW', '',
'Skoda', 'VW', 'BMW',
'', '', '',
'VW', 'Skoda', ''
),
ncol=3,
I repeat myself:
Any more automated solution will depend on whether your data has
rownames or not. [...] create a plain text representation of R data
using the dput() command.
Another way that might make more sense is to cbind() the data you need
later on before the split and then it will be
On Dec 1, 2011, at 18:54 , Ben quant wrote:
Sorry if this is a duplicate: This is a re-post because the pdf's mentioned
below did not go through.
Still not there. Sometimes it's because your mailer doesn't label them with the
appropriate mime-type (e.g. as application/octet-stream, which is
Hi all
How can I change the limits (xlim or ylim) in a plot that has been already
created?
For example, consider this naive example
curve(dbeta(x,2,4))
curve(dbeta(x,8,13),add=T,col=2)
When adding the second curve, it goes off the original limits computed by R
for the first graph, which are
Hi R-users,
I'm trying to produce decompositions of a multiple time-series, grouped by a
factor (called area). I'm modifying the code in the STLperArea function of
package ndvits, as this function only plots produces stl plots, it does not
return the underlying data.
I want to extract the trend
Hi,
I have a multilevel situation where subjects are nested within clinics, and
each subject has multiple measurements.
For simplicity, suppose there 4 clinics, 3 subjects per clinic, and each
subject has 3 repeated measures.
Outcome is continuous. I am trying to implement this model with
Hi,
With some help I learned how to use plsr(Y~x, 2, data=my) function in R (and
build my from vector Y and matrix x).
But still I have question about results interpretation. In the end I want to
construct prediction function in form:
Y=a1x1+a2x2
But I do not understand how to do it.
jcano wrote on 12/01/2011 12:12:03 PM:
Hi all
How can I change the limits (xlim or ylim) in a plot that has been
already
created?
For example, consider this naive example
curve(dbeta(x,2,4))
curve(dbeta(x,8,13),add=T,col=2)
When adding the second curve, it goes off the original
Thanks David and Rubén!
@David: indeed 15 betas I forgot the interaction terms, thanks for correcting!
@Rubén: the re-parameterize would be done within nls()? how to do
this practically with including the factor predictor?
and yes, we can solve within each group for Y=0 getting
0=b0+b1*X
I think part of your problem is the loop:
you probably mean
for(i in unique(area))
Michael
On Thu, Dec 1, 2011 at 1:13 PM, lglew l.g...@soton.ac.uk wrote:
Hi R-users,
I'm trying to produce decompositions of a multiple time-series, grouped by a
factor (called area). I'm modifying the code
On 01/12/2011 1:12 PM, jcano wrote:
Hi all
How can I change the limits (xlim or ylim) in a plot that has been already
created?
You can't, if you're using classic R graphics. They use an ink on
paper model of graphics. If you want to change what you've drawn, you
get a new piece of paper.
saschaview wrote on 12/01/2011 12:30:18 PM:
Hello
I have a data frame, x, holding 5 persons answering the question which
cars they have used:
# the data frame
x - as.data.frame(
matrix(
c('BMW', '', '',
'Mercedes', 'VW', '',
'Skoda', 'VW', 'BMW',
'',
Hi,
On Thu, Dec 1, 2011 at 2:43 PM, Majid golden_boy...@yahoo.com wrote:
Dear Sarah.
Thanks so much,Really I am new in this software,I am wrking to learn the
software.
First, you should always send your replies to the list. That way
information can help others,
and more people are available
On Dec 1, 2011, at 1:00 PM, William Dunlap wrote:
Terry will correct me if I'm wrong, but I don't think the
answer to this question is specific to the coxph function.
It depends on our interpretation of the questioner's intent. My answer
was predicated on the assumption that the phrase
On Thu, Dec 1, 2011 at 3:11 PM, Majid golden_boy...@yahoo.com wrote:
Hi,
yes, It is homework,
Then ask your TA/instructor for help.
These are 2 command:
first for generating data:
(1:10)
that output is 1 2 310
ok ?
second is :
a1-c( 1:10)
what is the output ?I didnot see any
Thank you for the feedback, but my data looks fine to me. Please tell me if
I'm not understanding.
I followed your instructions and here is a sample of the first 500 values :
(info on 'd' is below that)
d - as.data.frame(l_yx)
x = with(d, y[order(x)])
x[1:500] # I have 1's and 0's dispersed
Dear all, I have a data frame (DF) in the following format:
NAME
ID
a
b
c
d
1
Control_1
probe~B01R01C01
381
213
345
653
2
Control_2
probe~B01R01C02
574
629
563
783
3
Control_1
probe~B01R09C01
673
511
521
967
4
Control_3
probe~B01R09C02
53
809
999
50
5
MM0289~RFU:11810.15
I think your attachment got scrubbed so I can't verify this, but i
think the difficulty is that the inner apply returns a whole set of
orders, instead of just one and that throws arima off: would this
work?
getOrder - function(x) ar(na.omit(x), method = mle)$order
all.equal(apply(TSX, 2,
NAME
ID
a
b
c
d
1
Control_1
probe~B01R01C01
381
213
345
653
2
Control_2
probe~B01R01C02
574
629
563
783
3
Control_1
probe~B01R09C01
673
511
521
967
4
Control_3
probe~B01R09C02
53
809
999
50
5
MM0289~RFU:11810.15
probe~B29R13C06
681
34
115
587
6
MM0289~RFU:9238.41
probe~B29R13C05
784
443
On Dec 1, 2011, at 21:32 , Ben quant wrote:
Thank you for the feedback, but my data looks fine to me. Please tell me if
I'm not understanding.
Hum, then maybe it really is a case of a transition region being short relative
to the range of your data. Notice that the warning is just that: a
With binomial/binary responses (0|1) running MCMCglmm with
family=multinomial terminates with
Error in if (nJ 1) { : missing value where TRUE/FALSE needed
with family=categorical there are no errors
I have not looked in the code, do I need format the responses
TRUE/FALSE , or is this just a
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