PhGr == Philippe Grosjean [EMAIL PROTECTED]
on Mon, 15 Jan 2007 18:56:00 +0100 writes:
PhGr
PhGr I will attach it to a second email send privately to
PhGr you, since the mailing list do not accept attachments.
That's not correct.
http://www.r-project.org/mail.html
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
On Thu, 11 Jan 2007, Rebecca Tagett wrote:
Hello,
I'm trying to adapt some R code that works on Windows so that it will work
on a Linux machine.
The command :
png(myFile.png, width=600, height=600)
fails claiming that it
Scott == Scott Harrison [EMAIL PROTECTED]
on Mon, 15 Jan 2007 13:15:09 -0500 writes:
Scott Hi, To whom should I send feedback/edits concerning
Scott the Writing R Extensions web page?
Scott http://cran.r-project.org/doc/manuals/R-exts.html
To R-devel (the mailing list),
Hi Johann,
The current version of gnm is unable to fit this type of model, though a
new version with more flexibility is soon to be released.
In any case, you probably want to use nls or gnls, depending on the
assumptions that can be made about the model errors. For nls it is usual
to assume
Hi,
I am trying to output pdf files with 8 graphs per page. My current study
has 8 evaluation criteria, and 38 study conditions. This would result in
38 pages of 8 graphs. I have figured out how to get the graphs looking
like I would like them, and I am using the layout() function to put them
Hello - I am fairly new to R, (i.e., ability to create functions/write
programs insignificant) and was wondering if there might be a convenient way
to model the following: I want to fit a gaussian glm to grouped data, while
allowing for unequal variances in each of the groups.
More specifically,
I often produce program listings in my LaTeX documents. I use the
verbatim environment but use commands such as
\addtolength{\oddsidemargin}{-0.95in}
\addtolength{\evensidemargin}{-0.95in}
to widen the printed page so that I do not have to resort to line
continuation characters. This method
On Tue, 16 Jan 2007, Turner, Heather wrote:
Hi Johann,
The current version of gnm is unable to fit this type of model, though a
new version with more flexibility is soon to be released.
In any case, you probably want to use nls or gnls, depending on the
assumptions that can be made about
Rob Keller wrote:
Hi,
I am trying to output pdf files with 8 graphs per page. My current study
has 8 evaluation criteria, and 38 study conditions. This would result in
38 pages of 8 graphs. I have figured out how to get the graphs looking
like I would like them, and I am using the
The following gotcha caught me off-guard just now.
I have two matrices, a and b:
a - matrix(1,3,3)
b - matrix(1,1,1)
(note that both a and b are matrices).
I want them in a list:
B - NULL
B[[1]] - a
B[[2]] - b
B
[[1]]
[,1] [,2] [,3]
[1,]111
[2,]111
[3,]
Dear Mr. Bengtsson,
I see that there is a package exclusively for clustering data, named as
Cluster Package in R library. It has some clustering algorithms implemented.
Can you tell me how to implement the CLARA and PAM functions from that package
for my data?
Bhanu Kalyan K
B.Tech Final
Hi
I have no idea how Test data look like. However help pages of
functions
data.frame()
as.data.frame()
str()
and maybe few others can help you find how to change objects to data
frames.
HTH
Petr
On 16 Jan 2007 at 10:36, Bert Jacobs wrote:
From: Bert Jacobs [EMAIL
Robin Hankin wrote:
The error is given because after B[[1]] - a, the variable B is
just a scalar and
not a matrix (why is this?)
Because [[i]] indexes more general vectors, and if you do B[[1]] when
B is NULL, R doesnt know if you want B to be a list or a simple vector.
If you
Hi
try different way of list definition, see below.
On 16 Jan 2007 at 10:10, Robin Hankin wrote:
From: Robin Hankin [EMAIL PROTECTED]
Date sent: Tue, 16 Jan 2007 10:10:42 +
To: RHelp help r-help@stat.math.ethz.ch
Subject:[R]
To create a empty list do:
B - list()
/H
On 1/16/07, Robin Hankin [EMAIL PROTECTED] wrote:
The following gotcha caught me off-guard just now.
I have two matrices, a and b:
a - matrix(1,3,3)
b - matrix(1,1,1)
(note that both a and b are matrices).
I want them in a list:
B -
Robin Hankin wrote:
The following gotcha caught me off-guard just now.
I have two matrices, a and b:
a - matrix(1,3,3)
b - matrix(1,1,1)
(note that both a and b are matrices).
I want them in a list:
B - NULL
B[[1]] - a
B[[2]] - b
B
[[1]]
[,1] [,2] [,3]
[1,]
On Tue, 16 Jan 2007, Robin Hankin wrote:
The following gotcha caught me off-guard just now.
Checking the relevant help page is always a good idea (and that is why the
posting guide asks that you do so before posting).
I have two matrices, a and b:
a - matrix(1,3,3)
b - matrix(1,1,1)
Bhanu Kalyan.K wrote:
Dear Mr. Bengtsson,
I see that there is a package exclusively for clustering data, named as
Cluster Package in R library. It has some clustering algorithms
implemented.
Can you tell me how to implement the CLARA and PAM functions from that
package for my data?
Dawn Ashcourt wrote:
Hello - I am fairly new to R, (i.e., ability to create functions/write
programs insignificant) and was wondering if there might be a convenient way
to model the following: I want to fit a gaussian glm to grouped data, while
allowing for unequal variances in each of the
Hi,
I would suggest to use lme for doing that:
library(nlme)
vf1Ident - varIdent( c(m = 0.5), form = ~ 1 | group )
fm.lme - lme(data ~ group, weights = vf1Ident. data = DATA)
anova(fm.lme)
Hope this helps,
Thilo
On Tuesday 16 January 2007 10:30, Dawn Ashcourt wrote:
Hello - I am fairly new to
Hi,
I have a problem with the ARIMA function, occuring when I set the parameter
per (the period of SARIMA model) to a high value (see the exemple bellow). It
seems that when per is high it takes a too large amount of memory to calculate
the model and I have a memory storage error. But I
On Tue, 16 Jan 2007, yannig goude wrote:
Hi,
I have a problem with the ARIMA function, occuring when I set the
parameter per (the period of SARIMA model) to a high value (see the
exemple bellow). It seems that when per is high it takes a too large
amount of memory to calculate the model
Dear R-user,
I am trying to use the R nlme function to fit a non linear mixed
effects model. The model I wand to fit is an individual somatic growth
model with 4 parameters. For all parameters both fixed and random
effects have to be estimated, as well as their covariance matrix (see
the
I'm calculating nodes using Random Forest in R but i only get nodes for a
fraction of the compounds i want to calculate, the rest is ommited and is not
printed in the output file, (i'm working with 3012 compounds). What can i do to
have nodes printed for all the compounds. Thanks
Gonçalo
Hello,
With this program I try to repeat analysis for different years. The
results of the analysis are not printed when in the loop, except for the
year sequence. What is wrong?
Thanks a lot.
for (i in 92:99){
cat(\n,
If you really want the summary() etc to print to STDOUT use cat() or
print(). However other ways to post-process results may be preferrable,
I think about Sweave, xtable, etc.
Regards
Michael
Jorge Lampurlanes Castel wrote:
Hello,
With this program I try to repeat analysis for different
Did anyone try to run R under Window Vista, especially Windows Vista
64bit?
Thanks.
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
Hi,
Use print function print(Anova(...))
How about use of lappy functions ? It can be much easier
foo-function(data,formula){
LM - lm(formula,data=data)
Result-list(LmSum-summary(LM), Type2-Anova(LM,
type=II)),Type3-Anova(LM, type=III))
}
and
On 1/16/2007 9:35 AM, Sicotte, Hugues Ph.D. wrote:
Did anyone try to run R under Window Vista, especially Windows Vista
64bit?
I know someone who has (but I don't know if it was 32 bit or 64 bit).
He had a little trouble installing, because Vista tightens security
slightly: you need to run
Jorge Lampurlanes Castel wrote:
Hello,
With this program I try to repeat analysis for different years. The
results of the analysis are not printed when in the loop, except for the
year sequence. What is wrong?
Thanks a lot.
for (i in 92:99){
cat(\n,
On Tue, 16 Jan 2007, Martin Maechler wrote:
Scott == Scott Harrison [EMAIL PROTECTED]
on Mon, 15 Jan 2007 13:15:09 -0500 writes:
...
For edits, we'd mostly like to receive feedback on the
*source* of the above automatically produced document
(which is also the source of the PDF version,
It would also be nice if there were links in the .Rd files back
to the source of the commands, not just the source of the
documentation. That would facilitate
and encourage readers to paruse the source to clarify
the meaning of the help files.
On 1/16/07, David Forrest [EMAIL PROTECTED] wrote:
Dear List,
I want to make a parallel coordinates plot with the specific variables on
the abscissa and the cases on the ordinate should be dyed dependent on
another nominal variable from the data frame. I use the parcoord function.
Thanks for your help!
Best regards,
Marco
Dear HelpeRs,
Given:
x - rnorm(50)
y - rnorm(50)
plot(x,y)
abline(lm(x ~ y))
Is there a way to plot just a portion of the line? Say for values of x
2.0 or x -2.0 and x 4.0. (Still fitting all the points.)
Thank you,
jab
--
John Bollinger, CFA, CMT
www.BollingerBands.com
If you advance
you could try something like the following:
x - rnorm(50)
y - rnorm(50)
obj - lm(y ~ x)
par(mfrow = c(2, 2))
plot(x, y, main = x -1)
x. - c(min(x), -1)
y. - predict(obj, data.frame(x = x.))
lines(x., y.)
plot(x, y, main = x 1)
x. - c(1, max(x))
y. - predict(obj, data.frame(x = x.))
lines(x.,
Use segments. In the following we overlay the black abline with
a wider red segments line segment:
set.seed(1)
x - rnorm(50)
y - rnorm(50)
plot(y ~ x)
y.lm - lm(y ~ x)
abline(y.lm) # omit this line if black abline not wanted
x0 - c(-2, 4)
y0 - predict(y.lm, list(x = x0))
segments(x0[1],
Hi,
This is my command line request: mysql -u root -ppassword -D quant
c:/cline.txt
This line works from the command line in windows.
In R, when I try to use the system function, it does not work,
system(paste('mysql -u root -ppassword -D quant
c:/cline.txt'),show.output.on.console = TRUE)
Hi,
This is my command line request: mysql -u root -ppassword -D quant
c:/cline.txt
This line works from the command line in windows.
In R, when I try to use the system function, it does not work,
system(paste('mysql -u root -ppassword -D quant
c:/cline.txt'),show.output.on.console = TRUE)
You are on Windows, and that is how system() works on Windows (not
just in R, but in C, Perl ...). The help says
command: the system command to be invoked, as a string.
A command line is not a 'system command', and the is interpreted by the
shell you are running as your 'command line in
You can try this:
system(paste('mysql -u hsdlife -p -D life ', file('c:/teste.txt')),
show.output.on.console = TRUE)
On 16/01/07, Lapointe, Pierre [EMAIL PROTECTED] wrote:
Hi,
This is my command line request: mysql -u root -ppassword -D quant
c:/cline.txt
This line works from the command
At 14:12 15/01/2007, Frank E Harrell Jr wrote:
Benjamin Dickgiesser wrote:
Hi,
I am planning on putting some R script in an appendix of a LaTex
document. Can anyone recommend me a way of how to format it? Is there
a way to keep all line breaks without having to insert \\ in every
single line?
I've run R on the 32 bit version of Vista. Because of Vista's extra
security controls you can't install a library easily, however, even though I
had not trouble installing R. You must first set the security level to
allow it (I can't recall the details but it's not to difficult to figure
out),
Dear R-Helpers,
I would like to know what syntax I need to use to do a nested anova for
1. a continuous variable and 2. count data (x out of y)
1. The first I used to do in SPSS and I would like to be able to do it
in R as well.
This is the hierarchical model I would like to use: a continuous
I'm calculating nodes using Random Forest in R but i only get nodes for a
fraction of the compounds i want to calculate, the rest is ommited and is not
printed in the output file, (i'm working with 3012 compounds). What can i do to
have nodes printed for all the compounds. Thanks
Gonçalo
Greetings guRus --
I have successfully queried a large (24,445 rows by 281 cols.) in-house
database using the following RODBC query (without the line breaks)
testout - sqlQuery(channel, select idSchedule,EXCL_Total from
dbo.vwC1198_2006_RawData_With_CMPL_EXCL)
This returns a dataframe
Charles Annis, P.E. wrote:
I've run R on the 32 bit version of Vista. Because of Vista's extra
security controls you can't install a library
You mean you can't install a *package* into a library.
Are you sure that you cannot install into some other library that is in
some directory where
As in Dmitris' post lines is a somewhat more succint so here it is
again replacing segments with lines:
set.seed(1)
x - rnorm(50)
y - rnorm(50)
plot(y ~ x)
y.lm - lm(y ~ x)
abline(y.lm) # omit this line if black abline not wanted
x0 - c(-2, 4)
y0 - predict(y.lm, list(x = x0))
lines(y0 ~
'.' is invalid in an SQL table name. I don't know what driver you are
using (you seem very reluctant to tell us anything useful about your
DBMS), but dbo.vwC1198_2006_RawData_With_CMPL_EXCL probably means table
vwC1198_2006_RawData_With_CMPL_EXCL in database dbo, and that is valid as
part of
Hi, Goncalo:
did u use compounds as features when building rf? If so, some
compounds are NOT randomly selected in splitting nodes, which might
explain what you observed. But you need to provide more info for us to
help you, like those parameters you used to build rf.
You can use varImpPlot to
Hello,
There is any way of performing a LSD (Least Significant Diference)
multiple comparison test to separate the levels of the significant factors
of a model? I am migrating from SAS.
Thanks a lot.
--
**
Jorge Lampurlanés Castel
Departament
Look at the glht function in the multcomp package and the
MMC functions in the HH package.
Rich
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Fri, 12 Jan 2007, zhijie zhang wrote:
Dear friends,
I want to do a unequal probability sampling, that is, Probability
Proportionate to size, Is it right for the following programs?
Say my original dataset is:
ID Population
1 100
2 200
3 300
IF the population is large
On Tue, 16 Jan 2007, Gabor Grothendieck wrote:
It would also be nice if there were links in the .Rd files back
to the source of the commands, not just the source of the
documentation. That would facilitate
and encourage readers to paruse the source to clarify
the meaning of the help files.
Hi,
I'm running Rgui v2.4.0, RODBC v1.1-8, and psqlODBC v8.2.0002. Whenever
I do the following
chan - odbcConnect(mydatabase, uid=admin) # connection to a
postgresql db on a linux box
tmp - sqlQuery(chan, select * from sometable;) # this is successfull
odbcClose(chan) # this crashes Rgui and
Look at the squishplot function in the TeachingDemos package. Does
this set of commands work for you?
library(TeachingDemos)
squishplot(c(0.5,20.5),c(0.5,5.5),1)
image(1:20,1:5,a,asp=1,xlab=label here)
box()
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
Some information on the outliers is returned from the boxplot function. Try
something like:
set.seed(123)
tmp - data.frame( group=gl(3,10),
y=rcauchy(30), sex=gl(2,5,30,c('M','F')) )
tmp2 - boxplot( split(tmp$y,tmp$group) )
identify( tmp2$group, tmp2$out, tmp2$group )
Or if your grouping
Dear UseRs,
one of the outcomes of the useR! 2006 conference held in Vienna was that
JSS, the Journal of Statistical Software, is planning to publish a
series of special volumes. They will be guest edited and each volume
will have 5-10 issues (articles) of the usual JSS format.
One of the
One approach is to use the subplot function from the TeachingDemos
package. I could only get everything to line up properly if I specified
the xlim argument to hist directly and the same value as the ylim
argument to boxplot.
Try this:
x - rnorm(100)
library(TeachingDemos)
hist(x, breaks =
Reading the documentation for 'apply', I understand the following is
working exactly as documented:
M-matrix(1:6,ncol=2)
M
[,1] [,2]
[1,]14
[2,]25
[3,]36
apply(M,2,function(column) column+c(1,2,3))
[,1] [,2]
[1,]25
[2,]47
[3,]69
Try the clipplot function from the TeachingDemos package:
x - rnorm(50)
y - rnorm(50)
plot(x,y)
clipplot( abline(lm(y~x), col='red'), xlim=c(1,3))
clipplot( abline(lm(y~x), col='blue'), xlim=c(-2,1))
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain
The reshape package has an idempotent apply, iapply:
library(reshape)
iapply(M,1,function(row) row+c(1,2))
[,1] [,2]
[1,]26
[2,]37
[3,]48
On 1/16/07, Benjamin Tyner [EMAIL PROTECTED] wrote:
Reading the documentation for 'apply', I understand the following is
Hello all,
I want to assign relative score to the predictor variables on the basis of
its influence on the dependent variable. But I could not find any standard
statistical approach appropriate for this purpose.
Please suggest the possible approaches.
Thanks in advance,
Rupendra Chulyadyo
Rupendra,
depending on the nature of your data (which you haven't mentioned),
you might try hierarchical partitioning, as found in the hier.part
package on CRAN.
Cheers
Andrew
On Wed, Jan 17, 2007 at 11:07:18AM +0545, Rupendra Chulyadyo wrote:
Hello all,
I want to assign relative score to
Before you do that, you might try reading this paper:
Bring, J. 1995. Variable importance by partitioning R^2. Quality and
Quantity 29:173-189.
Cheers,
Simon.
Andrew Robinson wrote:
Rupendra,
depending on the nature of your data (which you haven't mentioned),
you might try hierarchical
I use to do this (It may help you)
boxplot(x)
bx-boxplot(x,plot=F)
In bx object, you and object names out with yaxis cordinates. For the i-th
boxplot in the figure,
use
text(rep(i,length(bx$out)),bx$out,...)
Justin BEM
Elève Ingénieur Statisticien Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
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