On Sat, Oct 18, 2014 at 12:24 PM, Axil Axil janap...@gmail.com wrote:
Ni61 is non reactive as stated by DGT and confirmed by Mizuno as presented
in Cook's !CCF-18 presentation
I interpret the depletion analysis differently than presented in Cook's
presentation (e.g., slide 52 [1]). If 61Ni
recent wishful thinking kicked in.
Bob Cook
- Original Message -
From: Eric Walker
To: vortex-l@eskimo.com
Sent: Saturday, October 18, 2014 10:38 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
On Sat, Oct 18, 2014 at 6:20 AM, Bob Cook frobertc...@hotmail.com wrote
:59 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
On Sat, Oct 18, 2014 at 12:24 PM, Axil Axil janap...@gmail.com wrote:
Ni61 is non reactive as stated by DGT and confirmed by Mizuno as presented
in Cook's !CCF-18 presentation
I interpret the depletion analysis differently
energy states to occur with mass energy being changed to angular
momentum energy.
Bob Cook
- Original Message -
From: Eric Walker
To: vortex-l@eskimo.com
Sent: Friday, October 17, 2014 9:54 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
On Fri, Oct 17, 2014
. It is with electrons as Pauli
pointed out.
Bob
- Original Message -
From: Eric Walker
To: vortex-l@eskimo.com
Sent: Friday, October 17, 2014 9:54 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
On Fri, Oct 17, 2014 at 10:41 AM, Bob Cook frobertc
Bob,
I have cherry-picked three major “spin facts” from this compendium which
indicate that if one wants to apply a nano-magnetism or spin-coupling
modality to LENR, it is highly preferable to use deuterium, as opposed to
hydrogen. That may be why Mizuno chose the deuterium-nickel combination. All
would be key to controlling the rate of the process.
Bob Cook
- Original Message -
From: Jones Beene jone...@pacbell.net
To: vortex-l@eskimo.com
Sent: Saturday, October 18, 2014 6:34 AM
Subject: RE: [Vo]:Mizuno, Rossi copper transmutation
Bob,
I have cherry-picked three major “spin
-Original Message-
From: Bob Cook
Was there any indication that the Mizuno experiments used quadrupole
electric or magnetic inputs? I was not aware of this, if it happened.
This is an interesting point, and the Mizuno experiment may not have been
optimized. Hopefully the next
I wrote:
Unfortunately I don't have any other details and don't know of a particular
experiment to refer to. Here is the quote from a textbook I recently
finished reading: ...
It was late last night, and the paragraph I found and quoted pertained to
deuterium, not 4He, which you were asking
The latter link suggested the BEC that I have talked about at above
cryogenic temperatures.
Bob Cook
Bob Cook
- Original Message -
From: Jones Beene jone...@pacbell.net
To: vortex-l@eskimo.com
Sent: Saturday, October 18, 2014 7:33 AM
Subject: RE: [Vo]:Mizuno, Rossi copper
-Original Message-
From: Bob Cook
I do not know of data on high temperature BEC's of particles of high mass.
Y. Kims theory for the reaction of Bose particles, including duplex
compinations of different Bose particles, may be of some importance. I have
not studied his theory in
it is highly preferable to use deuterium, as opposed to hydrogen.
I disagree.
Deuterium has a non zero spin whereas hydrogen has a zero spin which is
required in low powered LENR reactions.
On Sat, Oct 18, 2014 at 9:34 AM, Jones Beene jone...@pacbell.net wrote:
Bob,
I have cherry-picked
From: Axil
it is highly preferable to use deuterium, as opposed to hydrogen.
I disagree.
Deuterium has a non zero spin whereas hydrogen has a zero spin which is
required in low powered LENR reactions.
Says who? What is your evidence?
Ni61 is non reactive as stated by DGT and confirmed by Mizuno as presented
in Cook's !CCF-18 presentation
On Sat, Oct 18, 2014 at 3:17 PM, Jones Beene jone...@pacbell.net wrote:
*From:* Axil
it is highly preferable to use deuterium, as opposed to hydrogen.
I disagree.
Deuterium has
See
https://mospace.umsystem.edu/xmlui/bitstream/handle/10355/36817/SimulationNuclearTransmutationPresentation.pdf?sequence=2
On Sat, Oct 18, 2014 at 3:24 PM, Axil Axil janap...@gmail.com wrote:
Ni61 is non reactive as stated by DGT and confirmed by Mizuno as presented
in Cook's !CCF-18
So what, that’s not general evidence?
Even if true, it relates to nickel, and not to hydrogen/deuterium.
Everything since 1989 in LENR points to deuterium being as active if not
more than hydrogen.
From: Axil Axil
* Ni61 is non reactive as stated by DGT and confirmed by
: Jones Beene
To: vortex-l@eskimo.com
Sent: Saturday, October 18, 2014 12:17 PM
Subject: RE: [Vo]:Mizuno, Rossi copper transmutation
From: Axil
it is highly preferable to use deuterium, as opposed to hydrogen.
I disagree.
Deuterium has a non zero spin whereas
a +1/2 spin. The proton and neutron spins seem to add to
make up the +1 spin of the D.
Bob
- Original Message -
*From:* Jones Beene jone...@pacbell.net
*To:* vortex-l@eskimo.com
*Sent:* Saturday, October 18, 2014 12:17 PM
*Subject:* RE: [Vo]:Mizuno, Rossi copper transmutation
-61 (ODD NUMBER OF
NUCLEONS) DOES NOT SEEM TO REACT MUCH.
Bob Cook
- Original Message -
From: Axil Axil
To: vortex-l
Sent: Saturday, October 18, 2014 4:11 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
There is good reason to believe that magnetism is the prime
- Original Message -
*From:* Axil Axil janap...@gmail.com
*To:* vortex-l vortex-l@eskimo.com
*Sent:* Saturday, October 18, 2014 4:11 PM
*Subject:* Re: [Vo]:Mizuno, Rossi copper transmutation
*There is good reason to believe that magnetism is the prime mover in
LENR. Under this speculative
On Sat, Oct 18, 2014 at 6:20 AM, Bob Cook frobertc...@hotmail.com wrote:
A quadruple oscillating electric field may also help to excite the D's to
shed their excess mass relative to the developing 4He particle.
This sounds a little bit wishful to me. :)
Eric
Eric--
You wrote the following some time ago:
- Original Message -
From: Eric Walker
To: vortex-l@eskimo.com
Sent: Thursday, October 02, 2014 7:58 PM
Subject: Re: [Vo]:Mizuno, Rossi copper transmutation
On Thu, Oct 2, 2014 at 12:17 AM, frobertcook frobertc...@hotmail.com
On Fri, Oct 17, 2014 at 10:41 AM, Bob Cook frobertc...@hotmail.com wrote:
Do you know if the experiments looked at excited spin energy states that
may be possible at higher spin quanta?
Unfortunately I don't have any other details and don't know of a particular
experiment to refer to. Here
Harry
I like the idea of excited He as an intermediate. However, I would indicate
low energy radiation associted will He* spin energy deflation with angular
momentum an the spin energy distributed throughout the quantum dot mattrix and
its electrons.
The He* may occur in pairs aligned
On Thu, Oct 2, 2014 at 12:17 AM, frobertcook frobertc...@hotmail.com
wrote:
I like the idea of excited He as an intermediate.
I recall reading that 4He does not have a bound excited nuclear state,
although it may have a resonance for a very brief period of time.
Eric
In reply to H Veeder's message of Wed, 1 Oct 2014 00:25:05 -0400:
Hi,
[snip]
Since the second nickel nucleus has an extra neutron it is
now in an excited state. While it is excited the hydrogen nucleus on the
left retreats and the hydrogen nucleus on the right is
approaches.
Timing problem
On Wed, Oct 1, 2014 at 5:52 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Wed, 1 Oct 2014 00:25:05 -0400:
Hi,
[snip]
Since the second nickel nucleus has an extra neutron it is
now in an excited state. While it is excited the hydrogen nucleus on the
left retreats and the
On Tue, Sep 30, 2014 at 1:07 AM, Eric Walker eric.wal...@gmail.com wrote:
On Mon, Sep 29, 2014 at 2:54 PM, mix...@bigpond.com wrote:
If it happened nobody would notice.
Yes. I think it would be indistinguishable from an elastic collision (if
the two situations are different).
Eric
In reply to H Veeder's message of Tue, 30 Sep 2014 17:39:12 -0400:
Hi,
[snip]
On Tue, Sep 30, 2014 at 1:07 AM, Eric Walker eric.wal...@gmail.com wrote:
On Mon, Sep 29, 2014 at 2:54 PM, mix...@bigpond.com wrote:
If it happened nobody would notice.
Yes. I think it would be indistinguishable
On Tue, Sep 30, 2014 at 5:51 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Tue, 30 Sep 2014 17:39:12 -0400:
Hi,
[snip]
On Tue, Sep 30, 2014 at 1:07 AM, Eric Walker eric.wal...@gmail.com
wrote:
On Mon, Sep 29, 2014 at 2:54 PM, mix...@bigpond.com wrote:
If it
On Tue, Sep 30, 2014 at 9:25 PM, H Veeder hveeder...@gmail.com wrote:
When the deuterium nucleus gets close enough to connect with the second
Nickel nucleus it gives up its neutron to that nickel nucleus.
I think you're going to need a powerful force to make this part happen.
Think of the
I wrote:
Think of the proton that is part of the deuteron and the nickel nucleus as
extremely powerful, oppositely magnetized metal spheres.
I didn't say that very well. They're like two magnets with the same poles
facing each other (these magnets are monopoles, so there's no other pole to
Now I'll give *you* something to believe. I'm just one hundred and one,
five months and a day.'
'I can't believe *that!*' said Alice.
'Can't you?' the Queen said in a pitying tone. 'Try again: draw a long
breath, and shut your eyes.'
Alice laughed. 'There's no use trying,' she said 'one *can't*
In reply to H Veeder's message of Sun, 28 Sep 2014 19:18:08 -0400:
Hi Harry,
The link has two drawings on the same page. The top drawing, which is the
one I found, doesn't challenge FP research.
The bottom drawing is my modified version and it is intended to show that
the fusion process can be
On Mon, Sep 29, 2014 at 2:54 PM, mix...@bigpond.com wrote:
If it happened nobody would notice.
Yes. I think it would be indistinguishable from an elastic collision (if
the two situations are different).
Eric
I don't see how it challenge FP,
it is theory?
2014-09-28 2:34 GMT+02:00 H Veeder hveeder...@gmail.com:
On Thu, Sep 25, 2014 at 5:42 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Wed, 24 Sep 2014 23:04:12 -0400:
Hi Harry,
[snip]
Since we are dealing in impossibilities
The link has two drawings on the same page. The top drawing, which is the
one I found, doesn't challenge FP research.
The bottom drawing is my modified version and it is intended to show that
the fusion process can be considered reversible as long as it does not
reach the final stage.
Are you
On Thu, Sep 25, 2014 at 5:42 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Wed, 24 Sep 2014 23:04:12 -0400:
Hi Harry,
[snip]
Since we are dealing in impossibilities from the outset, it seems like
false logic to argue that the probability of endothermic reactions
is
I suggest that a very fast monolithic reaction process will allow Helium-2
(diproton) to form. Then immediately, before the positrons decay can take
place producing neutrons, two diproton atoms will fuse to the latent helium
4 intermediate product will take place comprised of 4 protons.
After
Upon the annihilation of both particles, two gamma,
should read
Upon the annihilation of both particles, two 512 KeV gamma are produced
that travel in an antiparallel direction away from the point of
annihilation .
On Sat, Sep 27, 2014 at 9:04 PM, Axil Axil janap...@gmail.com wrote:
I suggest
In reply to H Veeder's message of Wed, 24 Sep 2014 23:04:12 -0400:
Hi Harry,
[snip]
Since we are dealing in impossibilities from the outset, it seems like
false logic to argue that the probability of endothermic reactions
is improbable.
[snip]
I have told you what I think and why. Whether or not
I suspect both endothermic and exothermic reactions occur even inside the
tokamak, but on balance more exothermic reactions occur.
Harry
On Sun, Sep 21, 2014 at 6:30 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Sun, 21 Sep 2014 17:35:34 -0400:
Hi,
Nuclear energies are 6
In reply to H Veeder's message of Wed, 24 Sep 2014 21:46:11 -0400:
Hi,
[snip]
I suspect both endothermic and exothermic reactions occur even inside the
tokamak, but on balance more exothermic reactions occur.
Harry
Endothermic reactions only happen when ingoing particles have enough kinetic
On Wed, Sep 24, 2014 at 10:13 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Wed, 24 Sep 2014 21:46:11 -0400:
Hi,
[snip]
I suspect both endothermic and exothermic reactions occur even inside the
tokamak, but on balance more exothermic reactions occur.
Harry
Endothermic
On Wed, Sep 24, 2014 at 10:59 PM, H Veeder hveeder...@gmail.com wrote:
On Wed, Sep 24, 2014 at 10:13 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Wed, 24 Sep 2014 21:46:11 -0400:
Hi,
[snip]
I suspect both endothermic and exothermic reactions occur even inside the
I found it.
https://mospace.umsystem.edu/xmlui/bitstream/handle/10355/36817/SimulationNuclearTransmutationPresentation.pdf?sequence=2
On Mon, Sep 22, 2014 at 11:48 PM, Eric Walker eric.wal...@gmail.com wrote:
On Mon, Sep 22, 2014 at 9:26 AM, Axil Axil janap...@gmail.com wrote:
If you look
In reply to Jones Beene's message of Mon, 22 Sep 2014 16:32:02 -0700: [snip]
The usual lame rationalizations we have used is that the energy was
borrowed in advance to overcome the Coulomb barrier or shed in advance to
achieve the redundancy ...[/snip]
IMHO the lock step motion of gas atoms
Fran:
As is have posted many times, it is hard to tell what emerges from what.
What comes first the chicken of the egg.
Did you know that the Casmir force and zero point energy can be completely
controlled by polariton condensation.
*New regime in the Casimir force observed*
because they perceive a spatial separation due to
dilation/contraction [ the fractional hydrogen is temporally displaced without
the need for near C velocity]
Fran
From: Axil Axil [mailto:janap...@gmail.com]
Sent: Tuesday, September 23, 2014 11:59 AM
To: vortex-l
Subject: EXTERNAL: Re: [Vo]:Mizuno
In reply to Eric Walker's message of Mon, 22 Sep 2014 22:42:04 -0700:
Hi Eric,
On the face of it this sounds reasonable, but real life is seldom so simple.
Some deuterons will bounce off lattice nuclei in elastic collisions and head off
in completely different directions, so I would expect at
I've looked through the isotope charts again - searching for reactions that
rapidly decay back to the starting element or to any stable isotope which
has already been reported to be there, and have not found any other
possibility...
...other than Ni58 (d,Cu59) - Ni60 which happens by EC or
]:Mizuno, Rossi copper transmutation
Typo- the suggested reaction is Ni58 + D - Cu60 - Ni60
_
I've looked through the isotope charts again -
searching for reactions
22 septembre 2014 17:34
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno, Rossi copper transmutation
Typo- the suggested reaction is Ni58 + D - Cu60 - Ni60
_
I've looked
From: Arnaud Kodeck
Jones,
Why not consider also the Ni58 + 2p - Zn60 - Cu60 - Ni60? Zn60
has a spin 0.
_
the suggested reaction is Ni58 + D - Cu60 - Ni60
.
_
From: Jones Beene [mailto:jone...@pacbell.net]
Sent: lundi 22 septembre 2014 18:28
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Mizuno, Rossi copper transmutation
From: Arnaud Kodeck
_
From: Arnaud Kodeck
Yes, in my view, the DDL state diatomic hydrogen (shrunken hydrogen)
reacts with Ni58. Should both atoms be in shrunken state?
Yes, that would seem to be highly beneficial. The reaction looks less
In reply to Jones Beene's message of Mon, 22 Sep 2014 08:33:43 -0700:
Hi,
Typo- the suggested reaction is - Ni60
[snip]
Ni58 + D - Cu60 + 11.252 MeV
Normally one would expect prompt gammas from this reaction totaling 11.25 MeV.
If no gammas are detected, what do you propose happens to the
The usual lame rationalizations we have used is that the energy was
borrowed in advance to overcome the Coulomb barrier or shed in advance to
achieve the redundancy ...
But you're right - fusion numbers simply don't work well for the reality of
a Rossi type reaction, as there is too much excess
In reply to Jones Beene's message of Mon, 22 Sep 2014 16:32:02 -0700:
Hi,
[snip]
The usual lame rationalizations we have used is that the energy was
borrowed in advance to overcome the Coulomb barrier or shed in advance to
achieve the redundancy ...
But you're right - fusion numbers simply don't
On Mon, Sep 22, 2014 at 9:26 AM, Axil Axil janap...@gmail.com wrote:
If you look at the ICCF-18 transmutation study of nickel and palladium
study by Cook, you will see that Mizuno shows the same isotopic shifts in
nickel that DGT shows. Ni61 does not participate in the reaction but all
other
On Mon, Sep 22, 2014 at 8:01 PM, mix...@bigpond.com wrote:
I would still be inclined to consider reactions that produce heavy charged
particles. The heavier and slower, the better. E.g. fusion/fission
reactions.
The reactions I've been looking at recently have charged particles as
daughters
In reply to Eric Walker's message of Mon, 22 Sep 2014 21:08:59 -0700:
Hi Eric,
[snip]
On Mon, Sep 22, 2014 at 8:01 PM, mix...@bigpond.com wrote:
I would still be inclined to consider reactions that produce heavy charged
particles. The heavier and slower, the better. E.g. fusion/fission
On Mon, Sep 22, 2014 at 10:33 PM, mix...@bigpond.com wrote:
...but wouldn't you expect 1/2 to fly away from the surface, and half to fly
into it?
I would expect there to be an anisotropy. As I envision it, there's an
electric arc pulling a mass of protons into a recess. For a fraction of a
On Sat, Sep 20, 2014 at 10:42 AM, Jones Beene jone...@pacbell.net wrote:
Secondly, and most importantly - the neutron of the deuteron offers Coulomb
shielding.
Can you elaborate on this? I would have expected the neutron to be more or
less invisible, as far as the Coulomb field is concerned.
From: Eric Walker
Secondly, and most importantly - the neutron of the deuteron offers Coulomb
shielding.
Can you elaborate on this? I would have expected the neutron to be more or
less invisible, as far as the Coulomb field is concerned.
Eric
Of course, the neutron looks to be
On Sun, Sep 21, 2014 at 8:35 AM, Jones Beene jone...@pacbell.net wrote:
The strong force is so much stronger than electrical repulsion, that any
small effect can make a difference at close range.
If the possible Coulomb shielding effect from the neutron works at the same
range as the strong
Eric,
It really gets down to whether the gainful reaction is thermonuclear or quantum
mechanical. If you look in the archives, “stripping” was favored by me for many
years, and I first introduced it here - but opinions change.
Your opinion may not change, but here is what convinced me
On Sun, Sep 21, 2014 at 9:42 AM, Jones Beene jone...@pacbell.net wrote:
If you look in the archives, “stripping” was favored by me for many years,
and I first introduced it here - but opinions change.
The first reference I saw to the OP process was from a thread between you
and Abd Lomax, in
Eric - In the end, there’s nothing new under the sun and the best we can do
is try to get it right at least once along the pathway.
One good thing about a long-running forum, with a heated give-and-take of
ideas - is that if you can grasp everyone’s position, even for a few hours,
and evolve
On Sat, Sep 20, 2014 at 10:59 PM, mix...@bigpond.com wrote:
In reply to H Veeder's message of Sat, 20 Sep 2014 20:53:37 -0400:
Hi,
[snip]
If hydrinos and deuterinos are both present, perhaps it is possible for
the
neutron stripping to work in two directions such that a deuterino can give
In reply to H Veeder's message of Sun, 21 Sep 2014 17:35:34 -0400:
Hi,
Nuclear energies are 6 orders of magnitude larger than chemical energies, which
I would expect to reduce the chances to the point where it's not even worth
considering.
However, that said, it should be noted that the same is
In reply to mix...@bigpond.com's message of Mon, 22 Sep 2014 08:30:04 +1000:
Hi,
[snip]
9Be+2H = 4He + 4He + 3H + 4.684 MeV
BTW, this reaction also works for H (but only just).
1H+9Be = 4He + 4He + 2H + 0.651 MeV
..and I suspect that 9Be is the only naturally occurring isotope for which it
One more thing to add ... wrt the overdue suggestion (Doh, slaps forehead)
that Rossi's secret sauce is looking like it is deuterium. Thank you,
Clean Planet.
The reaction would probably work best if it is started with regular
hydrogen, and then deuterium is added later. This is because the
On Sat, Sep 20, 2014 at 7:40 AM, Jones Beene jone...@pacbell.net wrote:
However, all reactions of nickel with a proton result in a
radioactive isotope with a half-life which is long enough for it to have
been seen. This kind of hot isotope is not reported in any study of the
Rossi reactor -
On Sat, Sep 20, 2014 at 7:40 AM, Jones Beene jone...@pacbell.net wrote:
This elegant possibility of a gainful reaction in which stable nickel
converts to stable nickel, giving up energy, is why my prediction for the
Mizuno presentation in November is to suggest that they will see a relative
From: Eric Walker
* This elegant possibility of a gainful reaction in which stable nickel
converts to stable nickel, giving up energy, is why my prediction for the
Mizuno presentation in November is to suggest that they will see a relative
decrease in Ni58 and a relative increase in
You've certainly been consistent Jones. Quoting you from 2011:
[Vo]:Deuterium kills the reaction?
Jones Beene jone...@pacbell.net via eskimo.com
1/19/11
to vortex-l
One detail worth exploring further was the statement from Rossi that
only hydrogen works, and that deuterium kills the reaction
On Sat, Sep 20, 2014 at 10:40 AM, Jones Beene jone...@pacbell.net wrote:
Terry will remember
that in the very first image to come from Rossi, there was a color-coded
tank of deuterium in the Lab.
It might be in this vid:
http://www.rainews.it/it/video.php?id=23074
The D2 gas might have been
strips = stripes
On Sat, Sep 20, 2014 at 2:38 PM, Terry Blanton hohlr...@gmail.com wrote:
On Sat, Sep 20, 2014 at 10:40 AM, Jones Beene jone...@pacbell.net wrote:
Terry will remember
that in the very first image to come from Rossi, there was a color-coded
tank of deuterium in the Lab.
It
Single proton capture will not work because the spin of a single proton is
non zero. Double proton capture will work because the spin of 2He is zero.
Piantelli shows a 6 MeV proton coming out of a nickel bar. This implies
that a proton pair entered the nickel nucleus: one to produce the 6 MeV via
Deuterium kills the reaction because its spin is non zero.
On Sat, Sep 20, 2014 at 2:35 PM, Terry Blanton hohlr...@gmail.com wrote:
You've certainly been consistent Jones. Quoting you from 2011:
[Vo]:Deuterium kills the reaction?
Jones Beene jone...@pacbell.net via eskimo.com
1/19/11
to
This spin alignment of deuterium is why a plasma of hydrogen must be formed
to produce hydrogen crystals where deuterium must be reconfigured to a zero
spin alignment as the plasma cools.
Adding deuterium gas from a tank as Rossi has done will provide non zero
spin deuterium. It order for the
One reason the Rossi requires high heat from external electric power input
is to produce molecules with zero spin. He now uses the Mouse to make
these special molecules.
The down side of high heat that can form a plasma is that such application
of heat can cause reactor-away. The Mouse was
In reply to Eric Walker's message of Sat, 20 Sep 2014 10:18:40 -0700:
Hi,
[snip]
The nickel to nickel idea seems very promising. I doubt there is deuteron
capture, because if there is deuteron capture, there is probably proton
capture as well, along with all of the nasty gammas. This is what is
This hang-up on neutrons and 4He is due to this irresistible indoctrination
from old time nuclear physics. Rossi states that he has never seen a
neutron. 4He is just as likely to transmute as any other element. 4He has
no special status in LENR, IMHO.
On Sat, Sep 20, 2014 at 6:47 PM,
On Sat, Sep 20, 2014 at 4:30 PM, Axil Axil janap...@gmail.com wrote:
This hang-up on neutrons and 4He is due to this irresistible indoctrination
from old time nuclear physics. Rossi states that he has never seen a
neutron. 4He is just as likely to transmute as any other element. 4He has
no
If hydrinos and deuterinos are both present, perhaps it is possible for the
neutron stripping to work in two directions such that a deuterino can give
up a neutron to a heavy nucleus and a heavy nucleus can give up a neutron
to hydrino. ( I am thinking of a nuclear version of epicatalysis.)
Harry
In reply to H Veeder's message of Sat, 20 Sep 2014 20:53:37 -0400:
Hi,
[snip]
If hydrinos and deuterinos are both present, perhaps it is possible for the
neutron stripping to work in two directions such that a deuterino can give
up a neutron to a heavy nucleus and a heavy nucleus can give up a
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