just to quote Larsen in his cite: - He criticize the ide that He4 is trapped, and an ad hoc excuse - he claims that some transmutation cycle produce much more coherent energry by He4 than DD fusion
you can fin their reasoning in http://www.slideshare.net/lewisglarsen/lattice-energy-llctechnical-overviewcarbon-seed-lenr-networkssept-3-2009 page 25+ with page 34 summarizing their interpretation of McKrubre results... they claim it works better than DD hypothesis+leak excuse. 2012/4/9 Abd ul-Rahman Lomax <a...@lomaxdesign.com> > At 12:31 AM 4/8/2012, mix...@bigpond.com wrote: > >> In reply to Abd ul-Rahman Lomax's message of Thu, 05 Apr 2012 11:34:24 >> -0500: >> Hi, >> [snip] >> >Widom-Larsen theory completely fails to explain the actual >> >experimental results of cold fusion experiments, particularly the PdD >> >reactions of the Pons-Fleischmann Heat Effect. >> >> Not that I'm a fan of WL :), but: >> >> D + e- => 2 n >> >> Pd106 + 2 n => Ru104 + He4 + 11.9 MeV >> > > What "experimental result" does this explain? > > Pd106 + 2 n would become Pd108, which is stable. > > > > Granted 11.9 MeV isn't 23.8 MeV, but it is about half, and I'm not >> convinced >> that the He4/heat ratio has been measured all that accurately. >> > > The problem, Robin: the difficulty in measuring helium release is in > capturing all the helium. The released energy is reasonably well measured > through the calorimetry. It is suspected that, in general, about half the > helium is trapped in the cathode. If the reaction is a surface reaction, > and if helium is born with some energy (it could be below the 20 KeV > Hagelstein limit), half the helium will have a trajectory inward to the > cathode. The rest will come off with the evolving gas, and be measured. So > the heat/helium numbers from experiment, unless adjusted according to some > assumption like this, tend to be higher than the actual reaction Q, double > or so. > > Not lower. > > I personally find it frustrating that more work on measuring Q, and > improving accuracy, with more complete capture of the helium, hasn't been > done. I've been suggesting that experiments be run with a platinum wire > cathode, on which would be plated palladium. (This is done in some SPAWAR > "co-deposition" experiments." I'm putting codeposition in quotes because > these are apparently not actually codeposition, because they first plate > out the palladium, then raise the voltage to start evolving deuterium. The > experiments I know of with a platinum wire cathode were not designed to > measure heat or helium, though.) > > In any case, once the experiment is done and XP measured, then the > electrolysis would be reversed and the palladium dissolved, which should > release all the helium. It needs to be a platinum base wire for the cathode > or it would break up. Just my idea. > > Storms, however, estimates 25 +/- 5 MeV/He-4, and it's reasonable from the > data. 12 MeV would not be. > > > > Furthermore, >> >> Pd104 + 2 n => Ru102 + He4 + 13.75 MeV and >> >> Pd102 + 2 n => Ru100 + He4 + 15 MeV >> > > > If I'm correct, there is no evidence that dineutrons are even formed, but > without the dineutrons, you would have two reactions necessary, and a > serious rate problem. There is no evidence that dineutrons would be > absorbed in toto, the dineutron is a transient phenomenon. > > W-L theory would predict a complex of transmutations, but none of them > release as much energy as the transmutation of deuterium -> helium. These > transmutations would show a predictable relationship to the elemental mix > in the close environment of the cathode surface. Palladium would, of > course, be a common activation target, and if the targets decay by alpha > emission, then we'd have hot alphas. > > I have seen no experimental evidence that such a mix of transmuations is > actually found. Transmutations are certainly reported from FPHE > experiments, but at very low levels compared with helium. The reactions > described would all produce anomalous isotopes of Ruthenium. > > Hot alphas, i.e., energetic helium nuclei, above 20 KeV, break the > Hagelstein limit, they would be observed. Charged particle radiation from > FPHE experiments are at quite low levels, not the high levels that would be > necessary if the helium is being produced by alpha emission. > > Pd-104 is stable, so why would Pd102 + 2 n not simply become Pd-104? >