This experiment is designed to see if neutrons can decay without emitting neutrinos.
http://media.caltech.edu/press_releases/13520 If neutrons can that would conflict with the standard model. harry On Wed, Jun 6, 2012 at 2:08 PM, David Roberson <dlrober...@aol.com> wrote: > Does anyone accept the quark model for the neutron? I find it hard to > reconcile anything of that nature with a three layer model. > > I would think that by now with all of the super accelerators that this would > be well defined. > > Dave > > > -----Original Message----- > From: Harry Veeder <hveeder...@gmail.com> > To: vortex-l <vortex-l@eskimo.com> > Sent: Wed, Jun 6, 2012 12:46 pm > Subject: Re: [Vo]:about Triumph Management (and LENR) > > Based on evidence, the neutron is believed to be comprised of positive > core surrounded by a negative shell: > http://www.terra.es/personal/gsardin/news13.htm > > However in recent years there is evidence which suggests the neutron > is comprised of three layers: a central negative core which is > surrounded by a layer of positive charge which in turn is surrounded > by an exterior negative shell. > > Harry > > On Wed, Jun 6, 2012 at 9:56 AM, David Roberson <dlrober...@aol.com> wrote: >> I guess one could look at a neutron as being similar to a proton plus an >> electron but I am not sure that the exact analogy holds up under scrutiny. >> For one thing, when a neutron decays you get more out of it than the >> electron and proton. There is a pesky antineutrino and a substantial >> amount >> of energy released. >> >> The kinetic energy of a mass is equal to Mass * Velocity * Velocity /2. >> If >> you set the energy of an electron and a proton to be equal and solve for >> the >> velocity ratio you obtain the inverse square root of the mass ratio. I >> am >> neglecting relativistic effects since we are speaking of moderate >> velocities. >> >> You could get a fairly close idea of the proton velocity with temperature >> as >> you suggest by comparing it to a neutron, but I think the solution to the >> math above would be easier. >> >> One interesting point to consider is the strange energy behavior of a >> proton >> and electron combination. If they are in free space they find each other >> and radiate a significant amount of energy until the ground energy state >> is >> obtained. Even though the two are beginning to look like a neutron, >> energy >> is released into space. The hydrino hypothesis suggests that a lot more >> energy can be obtained by allowing the electron to move closer to the >> proton. If we continue in this manner, why does energy not be released >> the >> closer you bring the two components together? And to make manners worse, >> the neutron has more mass by a significant margin as compared to these two >> major constituents. Perhaps a neutron is much more complex than it >> appears. >> >> Dave >> >> >> -----Original Message----- >> From: Axil Axil <janap...@gmail.com> >> To: vortex-l <vortex-l@eskimo.com> >> Sent: Wed, Jun 6, 2012 3:07 am >> Subject: Re: [Vo]:about Triumph Management (and LENR) >> >> To get a idea about the speed of the proton, it might be possible to make >> a >> comparison with the speed of the neutron at various temperature. This >> might >> be OK because the proton and the neutron are about the same size and >> weight. >> The neutron is just a proton and an electron together…Right! >> >> 2000K – hot - 7060 meters/second >> 330K – room temperature- 2870 M/S >> 20K – Real cold - 706 M/S >> >> >> On Wed, Jun 6, 2012 at 2:46 AM, David Roberson <dlrober...@aol.com> wrote: >>> >>> Robin, I would think the velocity of the proton of the same energy as >>> compared to an electron would be the square root of 2000 or 45 times >>> slower >>> due to the velocity squared relationship. Now, if the proton slows down >>> much faster than the electron then the deceleration would be a lot >>> greater. >>> Perhaps 10 times greater? If you factor this into account then the >>> radiation levels of the two particles are relatively close. What do you >>> think? >>> >>> Dave >>> >>> >>> -----Original Message----- >>> From: mixent <mix...@bigpond.com> >>> To: vortex-l <vortex-l@eskimo.com> >>> Sent: Wed, Jun 6, 2012 1:35 am >>> Subject: Re: [Vo]:about Triumph Management (and LENR) >>> >>> In reply to David Roberson's message of Wed, 6 Jun 2012 01:12:10 -0400 >>> (EDT): >>> Hi, >>> [snip] >>> > >>> >I have long wondered whether or not protons generate bremsstrahlung >>> > radiation >>> in the same manner as electrons. It seems that the charge is responsible >>> for >>> the radiation and not the mass unless you are suggesting that the slower >>> rate of >>> deceleration of a proton versus and electron as it travels through matter >>> is the >>> reason. >>> >>> Precisely. Furthermore the actual velocity of a proton is about 2000 >>> times >>> lower >>> than that of an electron of the same energy (relativistic considerations >>> aside). >>> >>> >>> >Would the same deceleration rate for either particle generate the same >>> radiation effect? >>> >>> I suspect so. >>> >>> > >>> >The flip side of this coin is that the proton would travel >>> > proportionally >>> further as a result of the lower deceleration rate. >>> >>> Actually, I don't think they travel as far. I suspect this is because >>> they >>> are >>> much slower, and consequently have more time to interact with the >>> electrons of >>> the atoms they pass through than an electron of equivalent energy. Alpha >>> particles have even shorter trajectories. >>> Besides, the positively charged particles tend to attract the electrons >>> of >>> other >>> atoms, dragging them away from their parent atoms, whereas a fast >>> electron >>> pushes other electrons away, making them more inclined to simply move >>> over >>> a >>> little rather then get stripped from their parent atom. >>> This means that fast electrons don't get as many opportunities to dispose >>> of >>> their energy and hence travel farther. >>> [snip] >>> Regards, >>> >>> Robin van Spaandonk >>> >>> http://rvanspaa.freehostia.com/project.html >>> >> >
