> 8,000 meters above sea level. James jumps out to land on
> a small island, but unfortunately his parachute fails (d'oh!). For 007,
> this means 8,000 meters of free fall before he plunges into the ocean.
>
> The Questions
> -------------
> 1. What is James' speed (in meters per second) when he hits the water? You
> may assume that his initial speed (at the moment he leaves the airplane)
is
> 0.00 meters per second.
Hmmmm, my table only goes slightly above 3830 meters (12570 ft) of freefall (
75 seconds), so 8000 meters would be pretty hefty. Usually anything above
15000 ft requires oxygen and prebreathing, etc. I would snicker and say 8000
ft (2220 meters, 45 seconds of freefall) but some of those freefall scenes go
on for days (grin- the benefits of artistic license). I don't recall the
specific scene here.
To answer the terminal velocity question a bit-
1sec- 4.8m/sec- 16 ft/sec- 17.5 kms/hr- 10.91mph
2-------14-------------46-----------50.4-------------31.36
3--------23------------76-----------83.3------------51.81
(snip)
10--------51----------167----------183.2------------113.86
11--------52------------171---------187.6---------116.59
12--------53.5---------176---------190.9--------118.64
each additional second
---------53.5---------176---------190.9--------118.64
"after terminal velocity is reached (about 12 sec),
it takes 5.7 sec to freefall each 1000 ft."
the rate of descent increases wtih other body positions,
higher temps, lower pressures, jumpsuit size
(my tables give or take 10ish mph, but my log books
are old)
My brain is not functioning beyond "information providing" on
"math" right now :-)
Dee
Still around and happy for a bit of a break on this one, thesis defense in
two weeks and a bit of overwhelmed with the traditional end of April work
crunch.
