Juho Laatu wrote in part: > (P.S. Number of "1000 supporter parties" could be also higher > than two, > and number of candidates in each party could be higher than two, and > the results/problems would stay the same.)
I'd be very careful with generalizations like this one. The three-alternative case is qualitatively different from the two-alternative case. The example itself depends upon their being an even number of voters so the split can result in a tie. With the same 2000 voters and a third candidate, you can't have a tie since 2000 is not 0 mod 3. ---- Election-methods mailing list - see http://electorama.com/em for list info
