Hello Paul,
On Jul 25, 2005, at 01:42, Paul Kislanko wrote:
Juho Laatu wrote in part:
(P.S. Number of "1000 supporter parties" could be also higher
than two,
and number of candidates in each party could be higher than two, and
the results/problems would stay the same.)
I'd be very careful with generalizations like this one. The
three-alternative case is qualitatively different from the
two-alternative
case. The example itself depends upon their being an even number of
voters
so the split can result in a tie. With the same 2000 voters and a third
candidate, you can't have a tie since 2000 is not 0 mod 3.
Ok, I'll try to be more careful with my definitions. I'll give an
example to clarify what I was thinking. I the attached example one vote
seems to be able to pick any winner - in this case the last vote picks
B.
1000: A>B>C>D
1000: E>F>G
1000: H>I
1000: J
1: B>F
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