If a clock had absolutely no jitter whatsoever, then any available bandwidth would suffice to capture the peak amplitude at the fundamental and at any harmonics.
If a clock has enough jitter that the spectrum falls outside the measurement bandwidth, then we are not guaranteed that the measurement captures the peak amplitude, unless the measurement bandwidth simulates that of the victim receiver protected by the emission limit. This is the principle of the dithered clock, and why it was useful in protecting broadcast radio, but much less so for broadcast television. I am trying to get at what bandwidth is necessary to encompass the jitter spectrum of undithered clocks. Clearly this is a function of harmonic order, but a sense of the typical jitter spec on a clock will suffice to compute what I need. I have heard 50 ppm, but no attribution. Can anyone out there corroborate or correct? Thank you, Ken Javor Phone: (256) 650-5261 - ---------------------------------------------------------------- This message is from the IEEE Product Safety Engineering Society emc-pstc discussion list. To post a message to the list, send your e-mail to <emc-p...@ieee.org> All emc-pstc postings are archived and searchable on the web at: http://www.ieee-pses.org/emc-pstc.html Attachments are not permitted but the IEEE PSES Online Communities site at http://product-compliance.oc.ieee.org/ can be used for graphics (in well-used formats), large files, etc. Website: http://www.ieee-pses.org/ Instructions: http://www.ieee-pses.org/list.html (including how to unsubscribe) List rules: http://www.ieee-pses.org/listrules.html For help, send mail to the list administrators: Scott Douglas <sdoug...@ieee.org> Mike Cantwell <mcantw...@ieee.org> For policy questions, send mail to: Jim Bacher: <j.bac...@ieee.org> David Heald: <dhe...@gmail.com>
