On 15.02.13 09:02, John Kasunich wrote:
...
> Make the pulleys as big as you have room for - that helps you
> three ways:
> 
> 1) the belt tension needed to transmit a given torque goes down
> 
> 2) there are more teeth engaged between belt and pulley.  That both
> increases the ability of the belt to transfer torque, and it reduces the
> possibility of slip (which could show up as backlash)
> 
> 3) if there is any movement (backlash) between belt and pulley,
> a given amount linear movement results in less angular rotation
> of the shaft.
> 
> Regarding backlash, it might help to work an example with
> numbers:
> 
> Suppose you have a 5 thread per inch ballscrew, and are 
> using a 3" diameter pulley to drive it.  The circumference of
> the pulley is 3 x pi = 9.42 inches.  It takes five revolutions
> of the pulley for the axis to move one inch.  That means 
> 5 x 9.42 = 47.12 inches of belt movement to cause one
> inch of axis movement.  So any backlash between the
> pulley and the belt is reduced by a factor of 47 before it
> gets to the axis.  If a belt tooth is 0.005" smaller than the
> groove in the pulley, then in theory the belt could slip by
> 0,005".  Divide that by 47 and you get 0.000106" at the
> ballscrew.

John, I read that last night before going to bed, again today, and I'm
going to add it to my notes. It's the good oil.

...

> One more thing - keep in mind that the rated torque of a
> stepper is at zero speed, and you can't load it to even half
> that level and expect to get much speed out of it.  If you are
> calculating your belt tension and bearing loads based on
> stepper rated torque you are being very conservative.  Most
> stepper machines run at one-fourth of the rated torque, or
> even less.

The motor torque graphs confirm what you say, but your words are easier
to understand.

Many thanks.

Erik

-- 
You got to learn three things. What's  real,  what's  not  real,  and
what's the difference.           - Terry Pratchett, _Witches Abroad_



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