/"The wind losses are proportional to the cube of *speed* period."/
To clarify, the drag force is proportional to vehicle speed squared.  Power,
or energy/time, is the product of this force and vehicle speed, so is
proportional to speed cubed. Then the work done per unit time against this
force is proportional to the cube of vehicle speed, which is what I think is
meant in the above by "wind losses".



--
View this message in context: 
http://electric-vehicle-discussion-list.413529.n4.nabble.com/Range-vs-Speed-tp4672366p4672479.html
Sent from the Electric Vehicle Discussion List mailing list archive at 
Nabble.com.
_______________________________________________
UNSUBSCRIBE: http://www.evdl.org/help/index.html#usub
http://lists.evdl.org/listinfo.cgi/ev-evdl.org
For EV drag racing discussion, please use NEDRA 
(http://groups.yahoo.com/group/NEDRA)

Reply via email to