On Saturday, December 9, 2017 at 2:17:38 PM UTC, Lawrence Crowell wrote: > > On Saturday, December 9, 2017 at 7:34:29 AM UTC-6, [email protected] > wrote: >> >> >> I think you're making the unwarranted assumption that the measured shift >> in H is not >> effected by the cosmological red shift which presumably shifts all wave >> lengths. AG >> > > Of course it shifts all wavelengths by the same factor. So the spectrum of > atoms are shifted accordingly. With v = Hd the red shift factor is z = v/c > = H(d/c). for H = 70km/s/Mpc for v = c we then have that d = c/H = > 3x10^{5}km/s/(70Mpc/km/s) = 4.3x10^3Mpc = 1.4x10^{10}ly. So at z = 1 there > lies the cosmological horizon. We now observe galaxies with z = 8 and the > CMB has z = 1100. One can however thing of these photons as emitted prior > to these systems crossing the horizon. > > LC >
Since a parsec is about 3.26 LY and the SoL is about 300,000 km/sec, the event horizon should be about 300,000/70 * 3.26 * 10^6 = 13971 * 10^6 LY =~ 13971 MLY = 13.971 BLY. But this is a far cry from about 50 BLY, which is what I think the true distance is to the event horizon. I probably didn't account for the intervening expansion. How is accurate calculation done? TIA, AG -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
