On Sunday, December 10, 2017 at 10:54:11 PM UTC, Lawrence Crowell wrote: > > > > On Sunday, December 10, 2017 at 3:34:33 PM UTC-6, [email protected] > wrote: >> >> >> >> On Saturday, December 9, 2017 at 2:17:38 PM UTC, Lawrence Crowell wrote: >>> >>> On Saturday, December 9, 2017 at 7:34:29 AM UTC-6, [email protected] >>> wrote: >>>> >>>> >>>> I think you're making the unwarranted assumption that the measured >>>> shift in H is not >>>> effected by the cosmological red shift which presumably shifts all wave >>>> lengths. AG >>>> >>> >>> Of course it shifts all wavelengths by the same factor. So the spectrum >>> of atoms are shifted accordingly. With v = Hd the red shift factor is z = >>> v/c = H(d/c). for H = 70km/s/Mpc for v = c we then have that d = c/H = >>> 3x10^{5}km/s/(70Mpc/km/s) = 4.3x10^3Mpc = 1.4x10^{10}ly. So at z = 1 there >>> lies the cosmological horizon. We now observe galaxies with z = 8 and the >>> CMB has z = 1100. One can however thing of these photons as emitted prior >>> to these systems crossing the horizon. >>> >>> LC >>> >> >> Since a parsec is about 3.26 LY and the SoL is about 300,000 km/sec, the >> event horizon should be about 300,000/70 * 3.26 * 10^6 = 13971 * 10^6 LY =~ >> 13971 MLY = 13.971 BLY. But this is a far cry from about 50 BLY, which is >> what I think the true distance is to the event horizon. I probably didn't >> account for the intervening expansion. How is accurate calculation done? >> TIA, AG >> > > That is about it. There is a bit with significant figures for you might > want to use c = 299800km/s. > > LC >
But isn't the event horizon much farther out, about 50 BLY? AG -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
