On Sunday, December 10, 2017 at 3:34:33 PM UTC-6, agrays...@gmail.com wrote:
>
>
>
> On Saturday, December 9, 2017 at 2:17:38 PM UTC, Lawrence Crowell wrote:
>>
>> On Saturday, December 9, 2017 at 7:34:29 AM UTC-6, agrays...@gmail.com
>> wrote:
>>>
>>>
>>> I think you're making the unwarranted assumption that the measured shift
>>> in H is not
>>> effected by the cosmological red shift which presumably shifts all wave
>>> lengths. AG
>>>
>>
>> Of course it shifts all wavelengths by the same factor. So the spectrum
>> of atoms are shifted accordingly. With v = Hd the red shift factor is z =
>> v/c = H(d/c). for H = 70km/s/Mpc for v = c we then have that d = c/H =
>> 3x10^{5}km/s/(70Mpc/km/s) = 4.3x10^3Mpc = 1.4x10^{10}ly. So at z = 1 there
>> lies the cosmological horizon. We now observe galaxies with z = 8 and the
>> CMB has z = 1100. One can however thing of these photons as emitted prior
>> to these systems crossing the horizon.
>>
>> LC
>>
>
> Since a parsec is about 3.26 LY and the SoL is about 300,000 km/sec, the
> event horizon should be about 300,000/70 * 3.26 * 10^6 = 13971 * 10^6 LY =~
> 13971 MLY = 13.971 BLY. But this is a far cry from about 50 BLY, which is
> what I think the true distance is to the event horizon. I probably didn't
> account for the intervening expansion. How is accurate calculation done?
> TIA, AG
>
That is about it. There is a bit with significant figures for you might
want to use c = 299800km/s.
LC
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