On Sunday, December 10, 2017 at 8:07:15 PM UTC-6, Brent wrote:
>
>
>
> On 12/10/2017 5:25 PM, Lawrence Crowell wrote:
>
>
>
> On Sunday, December 10, 2017 at 5:13:38 PM UTC-6, [email protected] 
> wrote: 
>>
>>
>>
>> On Sunday, December 10, 2017 at 10:54:11 PM UTC, Lawrence Crowell wrote: 
>>>
>>>
>>>
>>> On Sunday, December 10, 2017 at 3:34:33 PM UTC-6, [email protected] 
>>> wrote: 
>>>>
>>>>
>>>>
>>>> On Saturday, December 9, 2017 at 2:17:38 PM UTC, Lawrence Crowell 
>>>> wrote: 
>>>>>
>>>>> On Saturday, December 9, 2017 at 7:34:29 AM UTC-6, [email protected] 
>>>>> wrote: 
>>>>>>
>>>>>>
>>>>>> I think you're making the unwarranted assumption that the measured 
>>>>>> shift in H is not 
>>>>>> effected by the cosmological red shift which presumably shifts all 
>>>>>> wave lengths. AG 
>>>>>>
>>>>>
>>>>> Of course it shifts all wavelengths by the same factor. So the 
>>>>> spectrum of atoms are shifted accordingly. With v = Hd the red shift 
>>>>> factor 
>>>>> is z = v/c = H(d/c). for H = 70km/s/Mpc for v = c we then have that d = 
>>>>> c/H 
>>>>> = 3x10^{5}km/s/(70Mpc/km/s) = 4.3x10^3Mpc = 1.4x10^{10}ly. So at z = 1 
>>>>> there lies the cosmological horizon. We now observe galaxies with z = 8 
>>>>> and 
>>>>> the CMB has z = 1100. One can however thing of these photons as emitted 
>>>>> prior to these systems crossing the horizon. 
>>>>>
>>>>> LC
>>>>>
>>>>
>>>> Since a parsec is about 3.26 LY and the SoL is about 300,000 km/sec, 
>>>> the event horizon should be about 300,000/70 * 3.26 * 10^6 = 13971 * 10^6 
>>>> LY =~ 13971 MLY = 13.971 BLY. But this is a far cry from about 50 BLY, 
>>>> which is what I think the true distance is to the event horizon. I 
>>>> probably 
>>>> didn't account for the intervening expansion. How is accurate calculation 
>>>> done? TIA, AG
>>>>
>>>
>>> That is about it. There is a bit with significant figures for you might 
>>> want to use c = 299800km/s.
>>>
>>> LC 
>>>
>>
>> But isn't the event horizon much farther out, about 50 BLY? AG 
>>
>
> No that is about where the CMB surface of last scatter lies. 
>
>
> To clarify, you mean where it lies "*now"*; and *"now" *means the 
> (universe wide) time at which the CMB is 2.7degK.
>
> Brent
>

The photons we observe from the CMB were emitted prior to the ionized gas 
crossing the cosmological horizon. We see it as it was 380k years after the 
big bang, with this huge red shifting. This red shifting indicates that on 
the Hubble frame this stuff is "way out there," in fact at about 47bly 
beyond the horizon.

LC
 

>
> It has z = 1100 and is further out beyond the horizon.
>
> LC 
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