On Wednesday, May 1, 2019 at 11:25:50 AM UTC-5, Brent wrote:
>
> No.  Erasing data generates heat.  So reversible computation is, in 
> principle,  possible without hear generation.
>
> Brent
>

That is basically it. Landauer demonstrated that information loss results 
in lost energy, internal energy or waste heat. This does not mean there is 
no thermal energy if no information is lost or erased, but that there is no 
change in such. The entropy of a quantum system with density matrix ρ is S 
= -k Tr[ρ log(ρ)]. The unitary transformation ρ = U^†ρU can be applied to 
this Shannon-von Neumann formula and shown it is invariant. It is easy, 
just take the Taylor series for the log. So quantum computer that do not 
suffer decoherence are reversible and produce no heat. Once photons come 
blasting out of there then bets are off.

I sort of follow Bruno below, and I concur with the statement the 
Fischer-Griess Monster group is important. It is important for a quantum 
error correction code. Its connection to moonshine, say with the 
Brunier-Kent-Ono partition theorem etc, that the monster is associated with 
all realizable number theoretic computations. Quantum numbers then have a 
Gödel number representation, say as prime numbers or zeros of the Riemann 
zeta function, and all possible errors computable may be ciphered by the 
Monster. Susskind has this idea of entangled black holes, but realistically 
such an entanglement must be highly partitioned into partial entanglements 
across some cosmic or inflationary landscape. This partition would obey the 
Brunier-Kent-Ono partition theorem, which its approximate solution as the 
Hardy-Ramanujan formula gives the density of states for strings and with 
black holes reproduces the Bekenstein formula. 

LC
 

>
> On 5/1/2019 1:56 AM, [email protected] <javascript:> wrote:
>
>
>
> By "heat" I just mean it as one studies it as a subject in a physics 
> class, for example.
> - https://en.wikipedia.org/wiki/Heat
>
> *Does all computation generate heat?*
>
> (Should be a simple enough question, I think.)
>
> - @philipthrift
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