On Wed, Mar 23, 2022 at 4:01 PM Brent Meeker <meekerbr...@gmail.com> wrote:

> On 3/22/2022 7:55 PM, Bruce Kellett wrote:
> Actually, that is where I started. I assumed that Alice and Bob were both
> able to collect results from N trials before they met. Then there are 2^N
> copies of each experimenter, and a potential (2^N)^(2^N) pairs when they
> meet. The trouble to be explained is that there are actually only 2^N pairs
> in a real experiment, each with inequality-violating correlations. What has
> happened to all the extra pairings that MWI must produce? (Most of which
> have correlations violating the quantum predictions.)
> Don't you mean (2^N)x(2^N).

Probably. Both Alice and Bob split into 2^N copies for binary results. So
each of the 2^N Alice's splits into 2^N further copies, one for each copy
of Bob. That seems to give (2^N)*(2^N) pairings. That is still a lot of
redundant copies when only one copy of Bob meets each copy of Alice in the
actual experiment.


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