On Wed, Mar 23, 2022 at 4:01 PM Brent Meeker <meekerbr...@gmail.com> wrote:

> On 3/22/2022 7:55 PM, Bruce Kellett wrote: > > > Actually, that is where I started. I assumed that Alice and Bob were both > able to collect results from N trials before they met. Then there are 2^N > copies of each experimenter, and a potential (2^N)^(2^N) pairs when they > meet. The trouble to be explained is that there are actually only 2^N pairs > in a real experiment, each with inequality-violating correlations. What has > happened to all the extra pairings that MWI must produce? (Most of which > have correlations violating the quantum predictions.) > > > Don't you mean (2^N)x(2^N). > Probably. Both Alice and Bob split into 2^N copies for binary results. So each of the 2^N Alice's splits into 2^N further copies, one for each copy of Bob. That seems to give (2^N)*(2^N) pairings. That is still a lot of redundant copies when only one copy of Bob meets each copy of Alice in the actual experiment. Bruce. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/CAFxXSLSZkh8_YNySPduxeo9rB_nc9_5XbFM%2B2dtnZiFCFbyVfw%40mail.gmail.com.