On 5/8/2022 5:25 PM, Bruce Kellett wrote:
On Mon, May 9, 2022 at 10:17 AM Brent Meeker <meekerbr...@gmail.com>
wrote:
On 5/8/2022 3:42 PM, Bruce Kellett wrote:
On Mon, May 9, 2022 at 6:37 AM smitra <smi...@zonnet.nl> wrote:
On 08-05-2022 05:58, Bruce Kellett wrote:
> It is when you take the SE to imply that all possible
outcomes exist
> on each trial. That gives all outcomes equal status.
All outcomes can exist without these being equally likely.
One can make
models based on more branches for certain outcomes, but these
are just
models that may not be correct.
Such models are certainly inconsistent with the SE. So if your
concern is that the SE does not contain provision for a collapse,
then you should doubt other theories that violate the SE. You
can't have it both ways: you can't reject collapse models because
they violate the SE and then embrace other models that also
violate the SE. Either the SE is universally correct, or it is not.
What matters is that such models can be
formulated in a mathematically consistent way, which
demonstrates that
there is n o contradiction. The physical plausibility of such
models is
another issue.
This has been discussed. To allow for real number probabilities,
the number of branches on each split must be infinite.
I don't think that's a problem. The number of information bits
within a Hubble sphere is something like the area in Planck units,
which already implies the continuum is a just a convenient
approximation. If the area is N then something order 1/N would be
the smallest non-zero probability. Also there would be a cutoff
for the off-diagonal terms of the density matrix. Once all the
off-diagonal terms are zero then it's like a mixed matrix and one
could say that one of the diagonal terms has "happened".
As I have pointed out before, a finite number of branches does not
work because after a certain finite number of splits, one would run
out of branches to partition in anything like the way appropriate for
the related probabilities. One cannot go adding more branches at that
stage without rendering the whole concept meaningless. Keeping things
finite has its attractions, but it does not work in this case.
I think it depends on how you count splits. If the number of dof within
a Hubble volume is finite, then the number of splits doesn't grow
exponentially. They get cut off when their probability becomes too small.
Brent
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