On 08-05-2022 05:58, Bruce Kellett wrote:
On Sun, May 8, 2022 at 11:32 AM smitra <smi...@zonnet.nl> wrote:
On 05-05-2022 01:15, Bruce Kellett wrote:
On Thu, May 5, 2022 at 5:27 AM smitra <smi...@zonnet.nl> wrote:
On 04-05-2022 01:49, Bruce Kellett wrote:
I have not introduced any concept of probability. The 2^N
branches
that are constructed when both outcomes are realized on each of
N
Bernoulli trials are all on the same basis.
If you ignore the amplitudes in the states, and that means
modifying
QM into something else.
QM does not assume that all branches exist equally. In Everett you
have already modified QM into something else.
The Schrodinger equation is insensitive to the amplitudes. You get
the
same set of 2^N branches from the Schrodinger equation, whatever
amplitudes you have. The weights of these branches certainly
depend on
the amplitudes: if there are n zeros in the set of N trials, there
are
N-n ones. The weight of the corresponding binary string is a^n
b^(N-n), but without further assumption, this plays no role in the
future development of the state or in the interpretation of the
binary
string. If you interpret it as the probability of the string, you
again have a conflict, since all binary strings are constructed on
an
equal basis, the natural probability for each is 2^{-N}.
There is no conflict whatsoever with assuming the Born rule and the
Schrodinger equation. The "construction on an equal basis" is not at
all
implied by the Schrödinger equation.
It is when you take the SE to imply that all possible outcomes exist
on each trial. That gives all outcomes equal status.
All outcomes can exist without these being equally likely. One can make
models based on more branches for certain outcomes, but these are just
models that may not be correct. What matters is that such models can be
formulated in a mathematically consistent way, which demonstrates that
there is n o contradiction. The physical plausibility of such models is
another issue.
Saibal
Bruce
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