A mi lahko kdo razlozi kako dolocis obmocje oz. meje za z. Moj postopek je zaenkrat tak, konkretno za to nalogo.
0<x<1 z>-x^(1/2) z>-1 ? kako vemo da je -1<z<0 in z>=0? Tukaj bi rabil malo pomoci -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Alen Loncaric Sent: Monday, January 16, 2006 10:37 AM To: 'FRIClist' Subject: RE: [Friclist] vis - stari kolokviji & izpiti Meni pride nekako takole: -inf<z<-1 - gostotaZ = 0 -1<z<0 - gostotaZ = -e^(-z+1) + e^(-sqrt(z)-z) Z>=0 - gostotaZ = -e^(-z+1) + e^(-z) Lp, Alen
