Hal wrote:
[...]
> All that remains then, is to determine what triangle will produce an area
> equal to the value of 813,487,178,923.54 square kilometers where you know
> two of the three sides of the triangle's length if you know the included
> angle between those two sides.  Once you know the included angle between two
> sides, you can determine the last side of the triangle, and compute the area
> of the triangle where it is equal to 1/2 Base times Height.

Hello Hal,

approximating the swept area with a triangle is only possible 
for very small angles -- otherwise the circle segment will be
a significant part of the circle sector.

As Dataweaver pointed out, you're going one of the ways to 
reinvent calculus from the ground up if you want to minimize
this error.

Also, real-world trajectories go from and to planets, so you
would have to solve the http://en.wikipedia.org/wiki/Three-body_problem

Regards,
Onno
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