I'm all for a new release as well, since 1.3.5 is no longer able to login without a path or svn update.
The 1.4.0 release should occur when there is a major release for the daemon. Past releases: 1.2.0 Added support for OSCAR protocol 1.3.0 Added support for (half-assed) protocol plugins 1.4.0 Added ... ? And don't forget to send out an e-mail to licq-announce, and update freshmeat. I have a script for that somewhere and will commit it once I find it. Jon On Wed, Sep 10, 2008 at 4:17 AM, Erik Johansson <[EMAIL PROTECTED]> wrote: > > 2008/9/9 Anders Olofsson <[EMAIL PROTECTED]>: >> So what do you say? Is it time for a release or does anyone have a good >> reason for waiting? > > +1 for doing a release. > >> I could do it if someone tells me how it's done. (I couldn't find any page >> in trac how to do it so it might be an idea to write one.) > > The procedure goes something like this: > 1. Update/verify http://licq.org/wiki/DeveloperArea/ReleaseNotes/1.3.6 > 2. Get http://svn.licq.org/svn/trunk/scripts/create-licq-tarball.sh > 3. Run ./create-licq-tarball.sh -n licq-1.3.6-rc1 -g -b -s -r <rev> > where <rev> is the revision that should become rc1. This will create a > gz and bz2 tarball and sign them. > 4. Get http://svn.licq.org/svn/trunk/scripts/tag-licq-release.sh > 5. Run ./tag-licq-release.sh -v 1.3.6-rc1 -r <rev>. This will create a > tag in svn. > 6. Upload the tarballs somewhere and ask Jon to upload them to sf.net. > 7. Update http://licq.org/wiki/LicqDownload > 8. Send mail to licq-dev, licq-users and licq-announce > 9. Write news entry on http://licq.org/ > > All taken from memory, so I hope I haven't forgotten anything. > >> Also, should the new release be version 1.3.6? >> I know I've done some changes to the plugin API that are not be 100% >> backwards compatible, would that be reason enough to call it 1.4.0 instead? > > Don't know our "rules" for this, but 1.4.0 might be the right thing to do. > > /Erik > > -- > Erik Johansson > Home Page: http://ejohansson.se/ > PGP Key: http://ejohansson.se/erik.asc >
