Instead of rectangles, I would use a different approach. Rather than
checking for overlapping rects, I would use the starting loc and
compare against the distance between the loc of the dropped sprite to
the loc of the underlying sprite. Then I would use the work of Mr.
Pythagoras many years ago to see how far away these points are.
For example, if you had a starting point of (10, 10), and a user
drops a piece at (13, 14) (point chosen for easy math), then using
the Pythagorean theorem, you know that the drop is 5 pixels away from
the exact location. You have to determine what is an "exectable"
about of variance.
I have previously done a similar puzzle, and there is a trick you can
use. You do not need two sprites. If you start by laying out the
puzzle in the score in the final solved state, then you know where
the solving point is. Then you can remember the final point in a
behavior, and set a new location at random. For example:
property pStartingLoc
property spriteNum
on beginSprite me
pStartingLoc = sprite(spriteNum).loc
newLoc = random((the stage).right, (the stage).left) -- or however
you choose locations.
sprite(spriteNum).loc = newLoc
end
Then do your dragging and dropping here, and on mouseUp (and
mouseUpOutside) do your distance check.
Hope this helps,
Irv
At 7:23 PM +0200 7/25/05, Michael Nadel wrote:
I'm making a puzzle game where I have each sprite in the score
twice. Once (underneath) the sprite's blend = 0 and above it (the
sprite that you drag's) blend = 100. When the sprite you are
dragging intersects the invisible sprite underneath, the invisible
sprite becomes visible and the drag sprite is thrown off the stage.
My question is, the "intersect" function is too vague and too easy.
I want that the user should be almost exactly on top of the
invisible sprite in order for the puzzle piece to become visible. Is
there another way to do this that would test if the user is
approximately almost exactly within the rect of the invisible
sprite?? (not "exactly", but "approximately exactly?")
Thanks for any help!
Michael Nadel
MediArt.Corp
"Creativity is more powerful than knowledge" -- Albert Einstein
***********************************************************************
Tel: (972-2) 5807-454
Email: [EMAIL PROTECTED]
Web: http://www.intelligineering.com/mediart/home.htm
[To remove yourself from this list, or to change to digest mode, go
to http://www.penworks.com/lingo-l.cgi To post messages to the
list, email lingo-l@penworks.com (Problems, email
[EMAIL PROTECTED]). Lingo-L is for learning and helping with
programming Lingo. Thanks!]
--
Multimedia Wrangler.
[To remove yourself from this list, or to change to digest mode, go to
http://www.penworks.com/lingo-l.cgi To post messages to the list, email
lingo-l@penworks.com (Problems, email [EMAIL PROTECTED]). Lingo-L is for
learning and helping with programming Lingo. Thanks!]
